a x 5 + a - 5 = 43 tìm A
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a) 159 - (25 - x) = 43
25 - x = 159 - 43
25 - x = 116
x = 25 - 116
x = -91
b) (x - 15) : 4 = 5² - 2³
(x - 15) : 4 = 25 - 8
(x - 15) : 4 = 17
x - 15 = 17 . 4
x - 15 = 68
x = 68 + 15
x = 83
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5\left(x-1\right)+3=43\)
\(5\left(x-1\right)=40\)
\(x-1=8\)
\(x=9\)
\(\left(1+2+3+...+50\right)+x=5050\)
\(\dfrac{50\left(50+1\right)}{2}+x=5050\)
\(1275+x=5050\)
\(x=3775\)
\(\left(2x+1\right)^3=64\)
\(\left(2x+1\right)^3=4^3\)
\(2x+1=4\)
\(2x=3\)
\(x=1,5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 6: Khôg có cau nào đúng
Câu 7: C
Câu 8: B
Câu 9: B
Câu 10: D
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a. 2 x 134 x 5 = (2 x 5) x 134
= 10 x 134
= 1340
b. 43 x 95 + 5 x 43
= 43 x (95 + 5)
= 43 x 100 = 4300
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a) Ta có: \(x\left(x^2-4\right)=0\)
\(\Leftrightarrow x\left(x-2\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)
Vậy: \(x\in\left\{0;2;-2\right\}\)
b) Ta có: \(\left(2x-3\right)+\left(-3x\right)-\left(x-5\right)=40\)
\(\Leftrightarrow2x-3-3x-x+5=40\)
\(\Leftrightarrow-2x+2=40\)
\(\Leftrightarrow-2x=38\)
hay x=-19
Vậy: x=-19
Bài 2:
a) Ta có: \(-45\cdot12+34\cdot\left(-45\right)-45\cdot54\)
\(=-45\cdot\left(12+34+54\right)\)
\(=-45\cdot100\)
\(=-4500\)
b) Ta có: \(43\cdot\left(57-33\right)+33\cdot\left(43-57\right)\)
\(=43\cdot57-43\cdot33+43\cdot33-33\cdot57\)
\(=43\cdot57-33\cdot57\)
\(=57\cdot\left(43-33\right)\)
\(=57\cdot10=570\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) x = 19 20 x = 19 20 b ) x = 83 12 x = − 37 12
c ) x = 31 12 x = − 25 12 d ) x = 13 4 x = − 7 12
![](https://rs.olm.vn/images/avt/0.png?1311)
\(43+\left(9-21\right)=317\left(x+317\right)\)
\(\Rightarrow317-\left(x+317\right)=43+\left(9-21\right)\)
\(\Rightarrow317-\left(x+317\right)=43+\left(-12\right)\)
\(\Rightarrow317-\left(x+317\right)=31\)
\(\Rightarrow x+317=317-31\)
\(\Rightarrow x+317=286\)
\(\Rightarrow x=286-317\)
\(\Rightarrow x=-31\)
Vay x = -31
\(b.\left(15-x\right)+\left(x-12\right)=7-\left(-5+x\right)\)
\(\Rightarrow15-x+x-12=7+5+x\)
\(\Rightarrow15-12=12-x\)
\(\Rightarrow3=12-x\)
\(\Rightarrow12-x=3\)
\(\Rightarrow x=12-3\)
\(\Rightarrow x=9\)
Vay x = 9
....
a) 43+(9-21) = 317-(x+317)
43+(-12) = 317-(x+317)
317-(x+317) = 31
x+317 = 317-31=286
x = 286-317=(-31)
Tạm thời câu b mình chưa nghĩ ra nha.
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a. => x+1 \(\in\)Ư(43) = {-43; -1; 1; 43}
=> x \(\in\){ -42; -2; 0; 42}
b. (2-x)(x+5) > 0
+) 2-x > 0 và x+5 > 0
- 2-x > 0 => x < 2 (1)
- x+5 > 0 => x > -5 (2)
Từ (1) và (2) => x \(\in\){-4; -3; -2; -1; 0; 1}
+) 2-x < 0 và x+5 < 0
- 2-x < 0 => x > 2 (1)
- x+5 < 0 => x < -5 (2)
Từ (1) và (2) => x \(\in\)\(\phi\).
Vậy x \(\in\){ -4; -3; -2; -1; 0; 1 }.
a x 5 + a - 5=43
=>6 x a=48
=>a=48:6
=>a=8
Vậy a=8
a-8