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a) \(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow80x=480\Rightarrow x=6\)
b) \(\Rightarrow15x+25-8x+12=5x+6x+36+1\)
\(\Rightarrow4x=0\Rightarrow x=0\)
c) \(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x+2\right)-2=0\)
\(\Rightarrow x+2-2=0\)
\(\Rightarrow x=0\)
\(\left(x+3\right)+1=7\)
\(\Rightarrow x+3+1=7\)
\(\Rightarrow x+4=7\)
\(\Rightarrow x=3\)
\(\left(3x-4\right)+4=12\)
\(\Rightarrow3x-4+4=12\)
\(\Rightarrow3x=12\)
\(\Rightarrow x=4\)
\(\left(5x+4\right)-1=13\)
\(\Rightarrow5x+4-1=13\)
\(\Rightarrow5x+3=13\)
\(\Rightarrow5x=10\)
\(\Rightarrow x=2\)
\(\left(4x-8\right)-3=5\)
\(\Rightarrow4x-8-3=5\)
\(\Rightarrow4x-11=5\)
\(\Rightarrow4x=16\)
\(\Rightarrow x=4\)
\(8-\left(2x+4\right)=2\)
\(\Rightarrow8-2x-4=2\)
\(\Rightarrow4-2x=2\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
\(7+\left(5x+2\right)=14\)
\(\Rightarrow7+5x+2=14\)
\(\Rightarrow9+5x=14\)
\(\Rightarrow5x=5\)
\(\Rightarrow x=1\)
\(5-\left(3x-11\right)=1\)
\(\Rightarrow5-3x+11=1\)
\(\Rightarrow16-3x=1\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)
\(\Leftrightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Leftrightarrow156-56x=24x-324\)
\(\Leftrightarrow-80x+480=0\Leftrightarrow x=-6\)
b, \(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x-12\right)+1\)
\(\Leftrightarrow15x+25-8x+12=5x+6x-36+1\)
\(\Leftrightarrow7x+37=11x-35\)
\(\Leftrightarrow-4x+72=0\Leftrightarrow x=18\)
c, \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Leftrightarrow10x-16-12x+15=12x-16+11\)
\(\Leftrightarrow-2x-1=12x-5\)
\(\Leftrightarrow-14x+4=0\Leftrightarrow x=\frac{2}{7}\)
d, \(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(\Leftrightarrow5x-3\left[4x-15x+6\right]=182\)
\(\Leftrightarrow5x-3\left(-11x+6\right)=182\)
\(\Leftrightarrow5x+33x-18-182=0\)
\(\Leftrightarrow38x-200=0\Leftrightarrow x=\frac{100}{19}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
![](https://rs.olm.vn/images/avt/0.png?1311)
a. |3x-6|=0
=> 3x-6=0
=> 3x=6
=> x=6:3
=> x=2
b. |7-2x| \(\ge0\)
mà |7-2x|=-8
=> không tồn tại x
c. |5x+6|=14
=> 5x+6=14 hoặc 5x+6=-14
=> 5x=14-6 hoặc 5x=-14-6
=> 5x=8 hoặc 5x=-20
=> x=8/5 hoặc x=-4
a) => 3x - 6= 0
=> 3x = 6
=> x = 2
b) |7 - 2x| \(\ge\) 0.
Mà đề cho |7 - 2x| = -8
=> x \(\in\) rỗng
c) |5x + 6| = 14
=> 5x + 6 = 14 hoặc 5x + 6 = -14
=> 5x = 8 hoặc 5x = -20
=> x = 8/5 hoặc x = -4
![](https://rs.olm.vn/images/avt/0.png?1311)
20) -5-(x + 3) = 2 - 5x ⇔ -5 - x - 3 = 2 -5x ⇔ 4x = 10 ⇔ x = \(\frac{5}{2}\)
Vậy...
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\(x^2-x\left(x+2\right)=6\)
\(\Leftrightarrow x^2-x^2-2x=6\)
<=> -2x = 6
<=> x = -3
\(3x\left(x-2\right)+2x\left(2-x\right)=x^2-8\)
\(\Leftrightarrow3x\left(x-2\right)-2x\left(x-2\right)=x^2-8\)
\(\Leftrightarrow\left(x-2\right)\left(3x-2x\right)=x^2-8\)
\(\Leftrightarrow\left(x-2\right)x=x^2-8\)
\(\Leftrightarrow x^2-2x=x^2-8\)
\(\Leftrightarrow2x=8\)
<=> x = 4
a/ \(x^2-x\left(x+2\right)=6\)
<=> \(x^2-x^2-2x=6\)
<=> \(-2x=6\)
<=> \(x=-3\)
b/ \(3x\left(x-2\right)+2x\left(2-x\right)=x^2-8\)
<=> \(3x^2-6x+4x-2x^2=x^2-8\)
<=> \(3x^2-2x-2x^2-x^2+8=0\)
<=> \(-2x+8=0\)
<=> \(-2x=-8\)
<=> \(x=4\)
c/ \(3\left(5x-1\right)-x\left(x+1\right)+x^2=14\)
<=> \(15x-3-x^2-x+x^2=14\)
<=> \(14x-3=14\)
<=> \(-3=14-14x\)
<=> \(14\left(1-x\right)=-3\)
<=> \(1-x=\frac{-3}{14}\)
<=> \(-x=\frac{-3}{14}-1\)
<=> \(x=\frac{3}{14}+1\)
<=> \(x=\frac{17}{14}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)4(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
<=>72 - 20x - 36x +84 = 30x - 240 - 6x 84
<=> -80x = -480
<=> x = 6
b) 5(3x+5)-4(2x-3) =5x+3(2x+12)+1
<=> 15x + 25 - 8x + 12 = 5x + 6x + 36 + 1
<=> 15x + 25 - 8x + 12 - 5x - 6x - 36 - 1 = 0
<=> -4x = 0
<=> x = 0
c) 2(5x-8)-3(4x-5)=4(3x-4)+11
= 10x - 16 - 12x + 15 = 12x - 16 + 11
= -14x = -4
= x =\(\frac{2}{7}\)
d) 5x-3{4x-2[4x-3(5x-2)]}=182
= 5x - 3 . [4x - 2(4x - 15x + 6)]
= 5x - 3 . (4x - 8x + 30x - 12)
= 5x - 12x + 24x - 90x + 36
= -73x + 36 = 182
=> -73x = 182 - 36 = 146
=> x = 146 : (-73) = -2
~Hok tốt~
![](https://rs.olm.vn/images/avt/0.png?1311)
Mấy cái này chuyển vế đổi dấu là xong í mà :3
1,
16-8x=0
=>16=8x
=>x=16/8=2
2,
7x+14=0
=>7x=-14
=>x=-2
3,
5-2x=0
=>5=2x
=>x=5/2
Mk làm 3 cau làm mẫu thôi
Lúc đăng đừng đăng như v :>
chi ra khỏi ngt nản
từ câu 1 đến câu 8 cs thể làm rất dễ,bn tham khảo bài của bn muwaa r làm những câu cn lại
5x - 8 = 3x + 14 => 5x = 3x + 14 + 8 = 3x + 22 => 5x - 3x = 22 => 2x = 22 => x = 22 : 2 = 11.