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a, -75 - (x + 20) + 95 = 0
=> - 75 - x - 20 + 95 = 0
=> -x = 0 + 75 + 20 - 95
=> -x = 0
=> x = 0
vậy_
b, 12 - x = 5 - (-3)
=> 12 - x = 8
=> x = 12 - 8
=> x = 4
vậy_
c, 10 - (3 - x) = 7
=> 3 - x = 10 - 7
=> 3 - x = 3
=> x = 3 - 3
=> x = 0
vậy_
d, 17- (x + 3) = 2
=> x + 3 = 17 - 2
=> x + 3 = 15
=> x = 15 - 3
=> x = 12
vậy_
e, 12 - x(x-1) = 3
=> x(x - 1) = 12 - 3
=> x(x - 1) = 9
=> x2 - x = 9
đến đây chju nhé
a) y : 10 + y x 3,9 = 4,8
y x 0,1 + y x 3,9 = 4,8
y x ( 0,1 + 3,9 ) = 4,8
y x 4 = 4,8
y = 1,2
b)y : 0,25 + y x 11 = 24
y x 4 + y x 11 = 24
y x ( 4 + 11 ) = 24
y x 15 = 24
y = 1,6
c) 75% x y + 3/4 x y + y = 30
3/4 x y + 3/4 x y + y x 1 = 30
y x ( 3/4 + 3/4 + 1 ) = 30
y x 2,5 = 30
y = 12
\(y:0,25+y.11=24\)
\(\Leftrightarrow y.4+y.11=24\)
\(\Leftrightarrow y.\left(4+11\right)=24\)
\(\Leftrightarrow y.15=24\)
\(\Leftrightarrow y=\frac{24}{15}=\frac{8}{5}\)
a) \(\frac{4}{5}=\frac{28}{35}\)
b) \(\frac{12}{15}=\frac{72}{90}\)
c) \(\frac{125}{300}=\frac{5}{12}\)
d) \(\frac{6}{9}=\frac{36}{54}\)
/HT\
a) \(\frac{4}{5}=\frac{28}{35}\) \(\text{X}=28\)
b) \(\frac{12}{15}=\frac{72}{90}\) \(\text{X}=90\)
c) \(\frac{125}{300}=\frac{5}{12}\) \(\text{X}=12\)
d) \(\frac{6}{9}=\frac{36}{54}\) \(\text{X}=6\)
a 25 + 8 + 12 + 25 = 70 b 87 + [ - 750 ] + 2018 - 13 + 750 = 2842 c [ 45 + 12 - 13 ] - [ 45 - 13 + 12 ] = 90 minh tinh gom bn ah
\(a.\left[x\cdot\left(x+1\right)\right]:2=136\\ x\cdot\left(x+1\right)=136\cdot2\\ x\cdot\left(x+1\right)=2\cdot2\cdot2\cdot17\cdot2\\ x\cdot\left(x+1\right)=\left(2\cdot2\cdot2\cdot2\right)\cdot17\\ x\cdot\left(x+1\right)=16\cdot17\\ =>x=16\\ b.\left[x\cdot\left(x+1\right)\right]:2=300\\ x\cdot\left(x+1\right)=3\cdot2\cdot2\cdot5\cdot5\cdot2\\ x\cdot\left(x+1\right)=\left(3\cdot2\cdot2\cdot2\right)\cdot\left(5\cdot5\right)\\ x\cdot\left(x+1\right)=24\cdot25\\ =>x=24\\ c.\left[x\cdot\left(x+1\right)\right]:2=561\\ x\cdot\left(x+1\right)=2\cdot3\cdot11\cdot17\\ x\cdot\left(x+1\right)=\left(17\cdot2\right)\cdot\left(3\cdot11\right)\\ x\cdot\left(x+1\right)=34\cdot33\\ =>x=33\)
\(12,45\times x-0,45\times x+x=3,9.\)
\(\Leftrightarrow x\times\left(12,45-0,45+1\right)=3,9.\)
\(\Leftrightarrow x\times13=3,9.\)
\(\Leftrightarrow x=0,3.\)
Vậy \(x=0,3.\)