2016x72+2016x29-2016
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PT
2
29 tháng 11 2021
TL
= 2016 x ( 72 + 29 -1 )
= 2016 x 100 = 201 600
Khi nào rảnh vào kênh H-EDITOR xem vid nha!!! Thanks!
10 tháng 12 2016
a, - { -(2016 +2015) - [ - (2016 - 2015) - (2016+2015) ] }
= -{-(2016+2015)-[-0-0]}
= -{-4031-0-0}
=-4031
LH
1
6 tháng 5 2016
Ta có:A=\(\frac{2016^{2016}+2}{2016^{2016}-1}\)>1
=>A<\(\frac{2016^{2016}+2-2}{2016^{2016}-1-2}\)=\(\frac{2016^{2016}}{2016^{2016}-3}\)=B
=>A<B(công thức nếu \(\frac{a}{b}\)>1 thì \(\frac{a}{b}\)<\(\frac{a-n}{b-n}\)(nEN)
CM công thức:
Ta có \(\frac{a}{b}\)>1=>a>b=>a=b+n(nEN)
Ta so sánh \(\frac{a}{b}\) và \(\frac{a-n}{b-n}\)(nEN)
Mà a*(b-n)=ab-an=ab-(b+n)*n=ab-(bn+n2)=ab-bn-n2
b*(a-n)=ba-bn
Vì ab-bn-n2<ba-bn
=>\(\frac{a}{b}\)<\(\frac{a-n}{b-n}\)
LT
0
2 tháng 9 2017
\(P=\dfrac{3^{2016}-6^{2016}+9^{2016}-12^{2016}+15^{2016}-18^{2016}}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\dfrac{\left(3^{2016}-6^{2016}\right)+\left(9^{2016}-12^{2016}\right)+\left(15^{2016}-18^{2016}\right)}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\dfrac{3^{2016}\left(1-2^{2016}\right)+3^{2016}\left(3^{2016}-4^{2016}\right)+3^{2016}\left(5^{2016}-6^{2016}\right)}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\dfrac{3^{2016}\left(1-2^{2016}+3^{2016}-4^{2016}+5^{2016}-6^{2016}\right)}{-\left(1^{2016}-2^{2016}+3^{2016}-4^{2016}+5^{2016}-6^{2016}\right)}\)
\(=-3^{2016}\).
Vậy \(P=-3^{2016}\)
TT
1
29 tháng 6 2016
\(2^{2016}+4^{2016}+6^{2016}+...+20^{2016}=2^{2016}\left(1+2^{2016}+3^{2016}+...+10^{2016}\right)\)
Do đó:
\(A=\frac{1^{2016}+2^{2016}+3^{2016}+...+10^{2016}}{2^{2016}+4^{2016}+6^{2016}+...+20^{2016}}=\frac{1}{2^{2016}}\)
NT
12
T
4 tháng 6 2019
#)Giải :
3 x 2016 + 9 x 2016 + 20 x 2016 + 28 x 2016 + 38 x 2016 + 2016 + 2016
= ( 3 + 9 + 20 + 28 + 38 + 1 + 1 ) x 2016
= 100 x 2016
= 201600
2 tháng 9 2017
\(P=\frac{3^{2016}-6^{2016}+9^{2016}-12^{2016}+15^{2016}-18^{2016}}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\frac{\left(1.3\right)^{2016}-\left(2.3\right)^{2016}+\left(3.3\right)^{2016}-\left(4.3\right)^{2016}+\left(5.3\right)^{2016}-\left(6.3\right)^{2016}}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\frac{1^{2016}.3^{2016}-2^{2016}.3^{2016}+3^{2016}.3^{2016}-4^{2016}.3^{2016}+5^{2016}.3^{2016}-6^{2016}.3^{2016}}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=\frac{-3^{2016}\left(-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}\right)}{-1^{2016}+2^{2016}-3^{2016}+4^{2016}-5^{2016}+6^{2016}}\)
\(=-3^{2016}\)
S
3 tháng 1 2018
2016 × 35 + 2016 × 65
= 2016 × (35+65)
= 2016 × 100
= 201600
2016 × 99 + 2016
= 2016 × 99 + 2016 × 1
= 2016 × (1+99)
= 2016 × 100
= 201600
2016 × 102 - 2016 × 2
= 2016 × (102-2)
= 2016 × 100
= 201600
2016 × 101 - 2016
= 2016 × 101 - 2016 × 1
= 2016 × (101-1)
= 2016 × 100
= 201600
3 tháng 1 2018
2016 x 35 + 2016 x 65
= 2016 x ( 35 + 65 )
= 2016 x 100
= 201600
2016 x 99 + 2016
= 2016 x 99 + 2016 x 1
= 2016 x ( 99 + 1 )
= 2016 x 100
= 201600
2016 x 102 - 2016 x 2
= 2016 x ( 102 - 2 )
= 2016 x 100
= 201600
2016 x 101 - 2016
= 2016 x 101 - 2016 x 1
= 2016 x ( 101 - 1 )
= 2016 x 100
= 201600
TN
7 tháng 4 2016
\(A=\frac{2016^{2016}+2}{2016^{2016}-1}=\frac{2016^{2016}-1+3}{2016^{2016}-1}=\frac{2016^{2016}-1}{2016^{2016}-1}+\frac{3}{2016^{2016}-1}=1+\frac{3}{2016^{2016}-1}\)
\(B=\frac{2016^{2016}}{2016^{2016}-3}=\frac{2016^{2016}-3+3}{2016^{2016}-3}=\frac{2016^{2016}-3}{2016^{2016}-3}+\frac{3}{2016^{2016}-3}=1+\frac{3}{2016^{2016}-3}\)
ta thấy:20162016-1>20162016-3
=>\(\frac{3}{2016^{2016}-1}<\frac{3}{2016^{2016}-3}\)
=>\(1+\frac{3}{2016^{2016}-1}<1+\frac{3}{2016^{2016}-3}\)
=>A<B
7 tháng 4 2016
A = 20162016 + 2/20162016-1 = 20162016 - 1 + 3/20162016 - 1
= 20162016 - 1/20162016 - 1 + 3/20162016 - 1
= 1 + 3/20162016 - 1 (không biết ghi hỗn số)
B = 20162016/20162016 -3 = 20162016 - 3 + 3/20162016 - 3
= 20162016 - 3/20162016 - 3 + 3/20162016 - 3
= 1 + 3/20162016 - 3
So sánh : 1 + 3/20162016 - 1 và 1 + 3/20162016 - 3
Ta có : 1 + 3/20162016 - 1 < 1 + 3/20162016 - 3
=> A < B
2016x72+2016x29-2016
Đáp án :
2016 x 72 + 2016 x 29 - 2016
bằng 201600
Nh bạn
^ HT ^