\(M=\dfrac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)
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KT
1
16 tháng 12 2020
\(M=\dfrac{40^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)
\(=\dfrac{\left(2^3.5\right)^{20}-2^{20}+\left(2.3\right)^{20}}{\left(2.3\right)^{20}-3^{20}+\left(3^2\right)^{20}}\)
\(=\dfrac{2^{60}.5^{20}-2^{20}+2^{20}.3^{20}}{2^{20}.3^{20}-3^{20}+3^{20}}\)
\(=\dfrac{2^{20}\left(2^{30}.5^{20}-1+3^{20}\right)}{3^{20}\left(2^{20}-1+3^{20}\right)}\)
có nhầm đề k nhỉ ?
VN
0
ST
1
4 tháng 1 2022
\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{\left(3^2\cdot5\right)^{10}\cdot5^{20}}{\left(3\cdot5^2\right)^{15}}=\dfrac{3^{20}\cdot5^{10}\cdot5^{20}}{3^{15}\cdot5^{30}}=3^5=243\\ \dfrac{6^6+6^3+3^3+3^6}{-73}=\dfrac{46656+216+27+729}{-73}=-\dfrac{47628}{73}\\ \dfrac{27^7+3^{15}}{9^9-27}=\dfrac{\left(3^3\right)^7+3^{15}}{\left(3^2\right)^9-3^3}=\dfrac{3^{21}+3^{15}}{3^{18}-3^3}=\dfrac{3^{15}\left(3^6+1\right)}{3^3\left(3^{15}-1\right)}=\dfrac{3^5\cdot730}{3^{15}-1}\\ \dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}=1024\)
NT
1
DG
19 tháng 3 2020
\(\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}=\frac{\left(2^2\right)^{20}-2^{20}+\left(3.2\right)^{20}}{\left(3.2\right)^{20}-3^{20}+\left(3^2\right)^{20}}=\frac{2^{20}.2^{20}-2^{20}.1+3^{20}.2^{20}}{3^{20}.2^{20}-3^{20}.1+3^{20}.3^{20}}=\frac{2^{20}.\left(2^{20}-1+3^{20}\right)}{3^{20}.\left(2^{20}-1+3^{20}\right)}=\frac{2^{20}}{3^{20}}=\left(\frac{2}{3}\right)^{20}=\frac{40}{60}=\frac{2}{3}\)
M=\(\dfrac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)
M=\(\dfrac{\left(4-2+6\right)^{20}}{\left(6-3+9\right)^{20}}\)
M=\(\dfrac{8^{20}}{12^{20}}\)
M=\(\dfrac{8}{12}\)
M=\(\dfrac{2}{3}\)