A=\(\frac{27^2.64.125}{25.9^3.5^4}\)=
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\(A=\frac{2^2}{1.3}\cdot\frac{3^2}{2.4}....\frac{999^2}{998.1000}\)
\(A=\frac{2^2.3^2....999^2}{1.3.2.4.998.100}=\frac{\left(2.3.....999\right)\left(2.3....999\right)}{\left(1.2....998\right)\left(3.4....1000\right)}\)
\(A=999\cdot\frac{1}{500}=\frac{999}{500}\)( khúc này mk làm tắt, bn bỏ dấu ở trên rồi bỏ từng tử)
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a) ( 1/2-1/3-1/6).(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0.(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0+3/4.x = 9/10
3/4.x = 9/10
x = 9/10: 3/4
x = 6/5
b) x + ( 3/1.3+3/3.5+...+3/13.15) = 11/5
x + 3/2. ( 1-1/3 + 1/3 - 1/5 + ...+ 1/13 - 1/15) = 11/5
x + 3/2. ( 1-1/15) = 11/5
x + 3/2.14/15 = 11/5
x + 7/5 = 11/5
x = 11/5 - 7/5
x = 4/5
a) Tử số = 3^6.45^4−15^13.5^−9=3^6.(5.3^2)^4−(3.5)^13.5^−9=3^6.5^4.3^8−3^13.5^13.5^−9=3^14.5^4−3^13.5^4=3^13.5^4(3−1)=2.3^13.5^4
Mẫu số = 27^4.25^3+45^6=3^12.5^6+3^12.5^6=2.3^12.5^6
Phân số = 2.3^13.5^4/2.3^12.5^6=3/25
.........................
= \(\frac{1}{2}\). ( \(\frac{2}{1.3}\) + \(\frac{2}{3.5}\) + \(\frac{2}{5.7}\) ... + \(\frac{2}{x.\left(x+2\right)}\) )
= \(\frac{1}{2}\) . ( 1 - \(\frac{1}{3}\) + \(\frac{1}{3}\) - \(\frac{1}{5}\) + \(\frac{1}{5}\) - \(\frac{1}{7}\) + ... + \(\frac{1}{x}\)- \(\frac{1}{x+2}\) )
= ................
Bạn tự làm tiếp nhé ! Chúc bạn học tốt :)
A) \(\frac{1}{2}\cdot\left(\frac{2}{9}+\frac{3}{7}-\frac{5}{27}\right)\)
\(=\frac{1}{2}\cdot\frac{1}{2}\)
\(=\frac{1}{4}\)
B) \(\left(\frac{-5}{28}+1.75+\frac{8}{35}\right):\left(-3\frac{9}{20}\right)\)
\(=\left(\frac{-5}{28}+\frac{7}{4}+\frac{8}{35}\right):\frac{-69}{20}\)
\(=\frac{14}{5}:\frac{-69}{20}\)
\(=\frac{-56}{69}\)
\(\frac{5,4:0,4\times1420+4,5\times780\times3}{3+6+9+12+15+18+21+24+27}\)
\(=\frac{13,5\times1420+13,5\times780}{\left(3+27\right)+\left(6+24\right)+\left(9+21\right)+\left(12+18\right)+15}\)
\(=\frac{13,5\times\left(1420+780\right)}{30+30+30+30+15}\)
\(=\frac{13,5\times2200}{135}\)
\(=\frac{29700}{135}\)
\(=220\)
\(A=\frac{27^2.64.125}{25.9^3.5^4}\)
\(A=\frac{3^3.2^6.5^3}{5^2.3^6.5^4}\)
\(A=\frac{2^6.5^3}{5^6.3^3}\)
\(A=\frac{2^6}{5^3.3^3}\)
\(A=\frac{64}{125.27}=\frac{64}{3375}\)
\(A=\frac{27^2.64.125}{25.9^3.5^4}\)
\(=\frac{\left(3^3\right)^2.2^6.5^3}{5^2.\left(3^2\right)^3.5^4}\)
\(=\frac{3^6.2^6.5^3}{5^2.3^6.5^4}\)
\(=\frac{2^6}{5^3}\)