BÀI :1 TÍNH
A) 2\(\frac{1}{18}\) + 3\(\frac{5}{6}\)+1\(\frac{2}{3}\)=MẤY
B)5\(\frac{3}{7}\)+(2\(\frac{5}{21}\) -1\(\frac{2}{3}\))=MẤY
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VM
17 tháng 1 2020
b) \(\frac{\frac{2}{3}+\frac{5}{7}+\frac{4}{21}}{\frac{5}{6}+\frac{11}{7}-\frac{7}{21}}\)
\(=\frac{\frac{29}{21}+\frac{4}{21}}{\frac{101}{42}-\frac{7}{21}}\)
\(=\frac{\frac{11}{7}}{\frac{29}{14}}\)
\(=\frac{22}{29}.\)
Chúc bạn học tốt!
11 tháng 6 2016
Mình sửa lại đề xíu.
a) \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}=\frac{3}{4}+\frac{1}{4}+\frac{18}{21}+\frac{3}{21}+\frac{19}{32}+\frac{13}{32}=1+1+1=3\)
b) \(4\frac{2}{5}+5\frac{6}{9}+2\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}=4+\frac{2}{5}+\frac{3}{5}+5+\frac{2}{3}+\frac{1}{3}+2+\frac{3}{4}+\frac{1}{4}\)
\(=4+1+5+1+2+1=14.\)
c) \(\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+...+\frac{2}{41\cdot43}=\frac{5-3}{3\cdot5}+\frac{7-5}{5\cdot7}+\frac{9-7}{7\cdot9}+...+\frac{43-41}{41\cdot43}\)
\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{41}-\frac{1}{43}=\frac{1}{3}-\frac{1}{43}=\frac{43-3}{3\cdot43}=\frac{40}{129}.\)
24 tháng 10 2017
a, 7/5 : x + 3/2 = 16/3
7/5 : x = 16/3 - 3/2
7/5 : x = 23/6
x = 7/5 : 23/6
x = 42/115
b, x : 1/5 + 1/7 = 3/5 . 18/21
x : 1/5 + 1/7 = 18/35
x : 1/5 = 18/35 - 1/7
x : 1/5 = 13/35
x = 13/35 . 1/5
x = 13/175
c, x - 1 và 1/3 : 2 = 5/7
x - 4/3 : 2 = 5/7
x - 4/3 = 5/7 . 2
x - 4/3 = 10/7
x = 10/7 + 4/3
x = 58/21
d, x + 2 và 3/5 . 1/6 = 35/36
x + 13/5 . 1/6 = 35/36
x + 13/5 = 35/36 : 1/6
x + 13/5 = 35/6
x = 35/6 - 13/5
x = 97/30
e, ( x + 3/2 ) : 2 = 7/10 + 1/5
( x + 3/2 ) : 2 = 9/10
x + 3/2 = 9/10 . 2
x + 3/2 = 9/5
x = 9/5 - 3/2
x = 3/10
HQ
Hà Quang Minh
Giáo viên
16 tháng 9 2023
a)
\(\begin{array}{l}\frac{1}{9} - 0,3.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{10}}.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{2.5}}.\frac{5}{{3.3}} + \frac{1}{3}\\ = \frac{1}{9} - \frac{1}{6} + \frac{1}{3}\\ = \frac{2}{{18}} - \frac{3}{{18}} + \frac{6}{{18}}\\ = \frac{5}{{18}}\end{array}\)
b)
\(\begin{array}{l}{\left( {\frac{{ - 2}}{3}} \right)^2} + \frac{1}{6} - {\left( { - 0,5} \right)^3}\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{2}} \right)^3\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{8}} \right)\\ = \frac{4}{9} + \frac{1}{6} + \frac{1}{8}\\ = \frac{{32}}{{72}} + \frac{{12}}{{72}} + \frac{9}{{72}}\\ = \frac{{53}}{{72}}\end{array}\)
\(a,2\frac{1}{18}+3\frac{5}{6}+1\frac{2}{3}\)
\(=2+\frac{1}{18}+3+\frac{5}{6}+1+\frac{2}{3}\)
\(=(2+3+1)+(\frac{1}{18}+\frac{5}{6}+\frac{2}{3})\)
\(=6+(\frac{1}{18}+\frac{15}{18}+\frac{12}{18})\)
\(=6+\frac{28}{18}\)
\(=6+\frac{14}{9}=7\frac{5}{9}=\frac{68}{9}\)
\(b,5\frac{3}{7}+(2\frac{5}{21}-1\frac{2}{3})\)
\(=5+\frac{3}{7}+2+\frac{5}{21}-1-\frac{2}{3}\)
\(=(5+2-1)+(\frac{3}{7}+\frac{5}{21}-\frac{2}{3})\)
\(=6+(\frac{9}{21}+\frac{5}{21}-\frac{14}{21})\)
\(=6+0=6\)
Chúc bạn học tốt
a) \(2\frac{1}{8}+3\frac{5}{6}+1\frac{2}{3}\)
\(=2\frac{3}{24}+3\frac{20}{24}+1\frac{16}{24}\)
\(=\left(2+3+1\right)+\frac{3+20+16}{24}\)
\(=6+\frac{13}{8}\)
\(=7\frac{5}{8}=\frac{61}{8}\)
b)\(5\frac{3}{7}+\left(2\frac{5}{21}-1\frac{2}{3}\right)\)
\(=5\frac{9}{21}+\left(2\frac{5}{21}-1\frac{14}{21}\right)\)
\(=5\frac{9}{21}+2\frac{5}{21}-1-\frac{14}{21}\)
\(=\left(5+2-1\right)+\frac{9+5-14}{21}\)
\(=6+0=6\)