20^5:4^2:___=25.4^3
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) (125 - x) + 25 = 98
125 - x = 98 - 25
125 - x = 73
x = 125 - 73
x = 52
b) 100 : (x + 20) = 68 : 34
100 : (x + 20) = 2
x + 20 = 100 : 2
x + 20 = 50
x = 50 - 20
x = 30
c) (3x + 12) . 5 = 25 . 4 - 10
(3x + 12) . 5 = 100 - 10
(3x + 12) . 5 = 90
3x + 12 = 90 : 5
3x + 12 = 18
3x = 18 - 12
3x = 6
x = 6 : 2
x = 3
d) 210 : (2x - 3) - 20 = 10
210 : (2x - 3) = 10 + 20
210 : (2x - 3) = 30
2x - 3 = 210 : 30
2x - 3 = 70
2x = 70 + 3
2x = 73
x = 73/2
a, ( 125 - x ) + 25 = 98
⇒ 125 - x = 73
⇒ x = 52.
Vậy..
b, 100 : ( x + 20 ) = 68 : 34
⇒ 100 : ( x + 20 ) = 2
⇒ x + 20 = 50
⇒ x = 30
Vậy...
c, ( 3 . x + 12 ) . 5 = 25 . 4 - 10
⇒ ( 3 . x + 12 ) . 5 = 90
⇒ 3 .x + 12 = 18
⇒ 3x = 6
⇒ x = 2.
Vậy...
d, 210 : ( 2 .x - 3 ) - 20 = 10
⇒ ( 2 .x - 3 ) - 20 = 21
⇒ 2x - 3 = 41
⇒ 2x = 44
⇒ x = 22.
Vậy..
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow20+8\left(x+3\right)=100\\ \Leftrightarrow8\left(x+3\right)=80\\ \Leftrightarrow x+3=10\\ \Leftrightarrow x=7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(18+25\times4-4^3\)
\(=18+100-64\)
\(=118-64\)
\(=54\)
b) \(275-\left(49+125\div5^3\right)\)
\(=275-\left(49+125\div125\right)\)
\(=275-\left(49+1\right)\)
\(=275-49-1\)
\(=226-1\)
\(=225\)
c) \(2015+\left(8\times15-\left(18-8\right)^2\right)\)
\(=2015+\left(8\times15-\left(10\right)^2\right)\)
\(=2015+\left(8\times15-100\right)\)
\(=2015+\left(120-100\right)\)
\(=2015+20\)
\(=2035\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 165:11.999 + 85.999 = (15.11):11.999 + 85.999 = [(15.11):11].999 + 85.999
= 15.(11:11).999 + 85.999 = 15.999 + 85.999 = (15+85).999 = 99900
b, 25.4 + 25:5 – 4.(30 – 5) – 5 = 25.4 + 25:5 – 4.25 – 5 = (25.4 – 4.25) + (25:5 – 5) = 0 + 0 = 0
![](https://rs.olm.vn/images/avt/0.png?1311)
`\(=\frac{5.5.4^{15}.9^9-2^9.6^{18}.6^2}{5.3.4^{12}.2.9^9.3-2^9.2^2.6^{18}.11}\)
\(=\frac{5.4^3-6^2}{3.2.3-2^2.11}\)
\(=\frac{320-36}{18-44}\)
\(=\frac{-284}{26}=\frac{-142}{13}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a: \(\left(6x-39\right):7=3\)
\(\Leftrightarrow6x-39=21\)
hay x=10
![](https://rs.olm.vn/images/avt/0.png?1311)
x . 15 : 2 : 3 = 5
x . 15 : 2 = 5 . 3
x . 15 : 2 = 15
x . 15 = 15 x 2
x . 15 = 30
=> x = 2.
25 . 4 + (150.x) = 200
100 + (150.x) = 200
150 . x = 200 - 100
150 . x = 100
=> x = 0,6666...
k cho mk nhé
20^5:4^2:125=25.4^3
hok tốt