A) \(3^2:3^4+2^4.2\) B) \(3^5-5^3+2^4-4^2\) C) \(31.6+69.67\)
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bài này dễ mà bạn bạn chỉ cần đổi ra rồi tính bình thường là đc mà
Bài 1:
\(A=2^2\cdot3-4\\ =4\cdot3-4\\ =4\cdot\left(3-1\right)\\ =4\cdot2\\ =8\\ B=16-2^3\cdot2\\ =16-16\\ =0\\ C=4^2-4\cdot2\\ =4\cdot\left(4-2\right)\\ =4\cdot2\\ =8\\ D=3^3-3\cdot3^2\\ =3^3-3^3\\ =0\)
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a)\(3^7:3^4+2^4.2=3^{7-4}+2^{4+1}=3^3+2^5=27+32=59\)
b)\(3^5-5^3+2^4-4^2=3^5-5^3+2^4-\left(2^2\right)^2=3^5-5^3+2^4-2^4=3^5-5^3=243-125=118\)
c)\(31.67+69.67=67.\left(31+69\right)=67.100=6700\)
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a, 1/2+1/2.(-3/5)
=1/2[1+(-3/5)]
=1/2.2/5
=1/5
b,1/3-(1/3.2/3-3/9)
=1/3-(2/9-3/9)
=1/3+1/9
=4/9
c,(-2 và 1/3+1/(5/4-7/3)
=(-2/3)+(-12/13)
=-62/39
d,2015/2017.3/4+3/4.2/2017+1/4
=3/4(2015/2017+2/2017)+1/4
=3/4+1/4
=1
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a) \(\left(-\dfrac{2}{3}+\dfrac{3}{7}\right):\dfrac{4}{5}+\left(-\dfrac{1}{3}+\dfrac{4}{7}\right):\dfrac{4}{5}\)
\(=\left(-\dfrac{5}{21}\right):\dfrac{4}{5}+\left(\dfrac{5}{21}\right):\dfrac{4}{5}\)
\(=\left(-\dfrac{5}{21}+\dfrac{5}{21}\right):\dfrac{4}{5}\)
\(=0:\dfrac{4}{5}\)
\(=0\)
b) \(\dfrac{5}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right)\)
\(=\dfrac{5}{9}:\left(-\dfrac{3}{22}\right)+\dfrac{5}{9}:\left(-\dfrac{3}{5}\right)\)
\(=\dfrac{5}{9}:\left[\left(-\dfrac{3}{22}\right)+\left(-\dfrac{3}{5}\right)\right]\)
\(=\dfrac{5}{9}:\left(-\dfrac{81}{110}\right)\)
\(=-\dfrac{550}{729}\)
c) \(4^2.4^3:4^{10}\)
\(=\dfrac{4^5}{4^{10}}\)
\(=\dfrac{1}{4^5}\)
\(=\dfrac{1}{256}\)
d) \(\left(0,6\right)^5:\left(0,2\right)^6\)
\(=\dfrac{\left(0,2\cdot3\right)^5}{\left(0,2\right)^6}\)
\(=\dfrac{\left(0,2\right)^5\cdot3^5}{\left(0,2\right)^6}\)
\(=\dfrac{243}{0,2}\)
\(=1215\)
Mai mốt bạn đăng một lần ít thôi nha tại giờ khuya quá nên mình chỉ làm đến đây thôi =))
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\(\text{1)}4.2^3-36:9\Rightarrow\text{4*2^3-36/9}\)
\(\text{2)}52.63+52.18-19.52\Rightarrow\text{52*63+52*18-19*52}\)
\(\text{3)}5^3.5^2.\left[42-\left(15-5\right)^2\right]\Rightarrow\text{5^3*5^2*(42-(15-5)^2}\left(\text{do trong excel không dùng dấu [ ]}\right)\)
\(\text{4)}\frac{1}{2}.\frac{1}{3}+\frac{1}{4}:\frac{1}{5}+\left(\frac{1}{2}\right)^3\Rightarrow\text{1/2*1/3+(1/4)/(1/5)+(1/2)^3}\)
giúp mình với :(((((
3^2:3^4+2^4.2=9:81+16.2
=1/9+32
=1/9+288/9
=289/9
3^5-5^3+2^4-4^2=243-125+16-8
=118+16-8
=134-8
=126
31.6+69.67=186+69.67
=186+4623
=4809