9024 : 25x+2==1824
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18 tháng 10 2021
\(\Rightarrow25^{x+2}=\left(\dfrac{90}{18}\right)^{24}=5^{24}=25^{12}\\ \Rightarrow x+2=12\\ \Rightarrow x=10\)
23 tháng 9 2021
\(90^{24}:25^{x+2}=18^{24}\\ \Leftrightarrow\left(5^2\right)^{x+2}=\dfrac{90^{24}}{18^{24}}=5^{24}\\ \Leftrightarrow5^{2x+4}=5^{24}\Leftrightarrow2x+4=24\Leftrightarrow x=10\left(D\right)\)
PT
1
PT
1
PT
1
7 tháng 8 2017
\(\left[1824-\left(526+2x\right)\right]+318=1420\)
\(\left[1824-\left(526+2x\right)\right]=1420-318\)
\(\left[1824-\left(526+2x\right)\right]=1102\)
\(526+2x=1824-1102\)
\(526+2x=722\)
\(2x=722-526\)
\(2x=196\)
\(x=196\div2\)
\(x=98\)
Vậy x = 98
PT
1
DG
1
XO
20 tháng 7 2019
D = \(\frac{1}{2}+\frac{1}{14}+\frac{1}{35}+...+\frac{1}{434}\)
= \(2.\left(\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+...+\frac{1}{868}\right)\)
= \(2.\frac{1}{3}.\left(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+...+\frac{3}{868}\right)\)
= \(\frac{2}{3}.\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{28.31}\right)\)
= \(\frac{2}{3}.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{28}-\frac{1}{31}\right)\)
= \(\frac{2}{3}.\left(1-\frac{1}{31}\right)\)
= \(\frac{2}{3}.\frac{30}{31}\)
= \(\frac{20}{31}\)
E = \(\frac{2}{15}+\frac{3}{40}+\frac{11}{152}+\frac{13}{608}+\frac{25}{1824}+\frac{30}{4959}\)
= \(\frac{2}{3.5}+\frac{3}{5.8}+\frac{11}{8.19}+\frac{13}{19.32}+\frac{25}{32.57}+\frac{30}{57.87}\)
= \(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{19}+\frac{1}{19}-\frac{1}{32}+\frac{1}{32}-\frac{1}{57}+\frac{1}{57}-\frac{1}{87}\)
= \(\frac{1}{3}-\frac{1}{87}\)
= \(\frac{28}{87}\)
HN
0
x= 25 mũ 21 nhé
hok tốt
<=> 924.1024:(52)x+2=224.924
<=>1024:52x+4:224=924:924
<=>524:52x.54=1
<=>520:52x=1
<=>520=52x
<=>20=2x
<=>x=10
Vậy x=10