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20 tháng 11 2016

\(\frac{2^{12}.3^5-\left(2^2\right)^6.3^6}{2^{12}.\left(3^2\right)^3+\left(2^3\right)^4.3^3}\)

\(\frac{2^{12}.3^5.\left(1-3^{ }\right)}{2^{12}.3^3.\left(3^3-1\right)}\)

\(\frac{2^{12}.3^5.\left(-2\right)}{2^{12}.3^3.8}\)

\(\frac{3^2.\left(-1\right)}{4}\)

\(\frac{-9}{4}\)

VẬy.......................

nhớ tk cho mình nha

24 tháng 2 2019

\(Q=\frac{2^{12}.3^5-4^6.81}{\left(2^2.3\right)^6+8^4.3^5}=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}\)

\(=\frac{2^{12}.3^4.\left(3-1\right)}{2^{12}.3^5.\left(3+1\right)}=\frac{2}{3.4}=\frac{1}{6}\)

24 tháng 2 2019

Q = \(\frac{2^{12}.3^5-4^6.81}{\left(2^2.3\right)^6+8^4.3^5}\)

    = \(\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}\)

    = \(\frac{2^{12}.3^4.\left(3-1\right)}{2^{12}.3^5.\left(3+1\right)}\)

    = \(\frac{2}{3.4}=\frac{1}{6}\)

13 tháng 1 2018

\(\dfrac{2^{12}.3^5-4^6.3^6}{2^{12}.9^3+8^4.3^5}=\dfrac{2^{12}.3^5-\left(2^2\right)^6.3^6.3}{2^{12}.\left(3^2\right)^3+\left(2^3\right)^4.3^5}.\)

\(=\dfrac{2^{12}.3^5-2^{12}.3^6}{2^{12}.3^6+2^{12}.3^5}=\dfrac{2^{12}\left(3^5-3^6\right)}{2^{12}\left(3^5+3^6\right)}=\dfrac{3^5-3^6}{3^5+3^6}=-\dfrac{486}{972}=-\dfrac{1}{2}.\)

Vậy..........