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26 tháng 8 2018

\(2\dfrac{1}{547}.\dfrac{3}{211}-\dfrac{546}{547}.\dfrac{1}{211}-\dfrac{4}{547.211}\)

\(=\left(2+\dfrac{1}{547}\right).3.\dfrac{1}{211}-\left(1-\dfrac{1}{547}\right).\dfrac{1}{211}-4.\dfrac{1}{547}.\dfrac{1}{211}\)

Đặt \(a=\dfrac{1}{547};b=\dfrac{1}{211}\)

Thay \(a=\dfrac{1}{547};b=\dfrac{1}{211}\) vào biểu thức trên , ta được :

\(\left(2+a\right).3b-\left(1-a\right)b-4ab\)

\(=6b+3ab-b+ab-4ab\)

\(=5b\)

\(=5.\dfrac{1}{211}\)

\(=\dfrac{5}{211}\)

Vậy g/t biểu thức trên là : \(\dfrac{5}{211}\)

11 tháng 3 2018

- Bằng \(\dfrac{5}{211}\)

11 tháng 3 2018

gọi 1/547=a, 1/211=b ta đc:

\(2a.3b-546a.b-4ab< =>6ab-546ab-4ab=-544ab=\dfrac{-544}{547.211}\)

a: \(M=\dfrac{631}{315}\cdot\dfrac{1}{651}-\dfrac{1}{105}\cdot\dfrac{2603}{651}-\dfrac{4}{315\cdot651}+\dfrac{4}{105}\)

\(=\dfrac{1}{315\cdot651}\cdot\left(631-4\right)-\dfrac{1}{105}\left(\dfrac{2603}{651}-4\right)\)

\(=\dfrac{1}{105}\cdot\dfrac{1}{1953}\cdot627+\dfrac{1}{105\cdot651}\)

\(=\dfrac{1}{105\cdot651}\left(\dfrac{1}{3}\cdot627+1\right)=\dfrac{1}{105\cdot651}\cdot210=\dfrac{2}{651}\)

b: \(N=\dfrac{1095}{547}\cdot\dfrac{3}{211}-\dfrac{546}{547\cdot211}-\dfrac{4}{547\cdot211}\)

\(=\dfrac{1}{547\cdot211}\left(1095\cdot3-546-4\right)\)

\(=\dfrac{1}{547\cdot211}\cdot2735=\dfrac{5}{211}\)

a: \(=\dfrac{\left(2\cdot547+1\right)\cdot3}{547\cdot211}-\dfrac{546}{547\cdot211}-\dfrac{4}{547\cdot211}\)

\(=\dfrac{2735}{547\cdot211}=\dfrac{5}{211}\)

b: x=7 nên x+1=8

\(x^{15}-8x^{14}+8x^{13}-8x^{12}+...-8x^2+8x-5\)

\(=x^{15}-x^{14}\left(x+1\right)+x^{13}\left(x+1\right)-x^{12}\left(x+1\right)+...-x^2\left(x+1\right)+x\left(x+1\right)-5\)

\(=x^{15}-x^{15}-x^{14}+x^{14}-...-x^3-x^2+x^2+x-5\)

=x-5=7-5=2

22 tháng 9 2020

=>\(B=\left(2\cdot\frac{1}{547}\cdot\frac{3}{211}\right)-\left(\frac{546}{547}\cdot\frac{1}{211}\right)-\left(\frac{4}{547\cdot211}\right)\)

=>\(B=\frac{6}{547\cdot211}-\frac{546}{547\cdot211}-\frac{4}{547\cdot211}\)

=>\(B=\frac{6}{115417}-\frac{546}{115417}-\frac{4}{115417}\)

=>\(B=\frac{-544}{115417}\)

27 tháng 7 2015

M = \(2.\frac{1}{547}.\frac{3}{211}-\frac{546}{547}.\frac{1}{211}-\frac{1}{247.211}\)

M = \(\frac{6}{547.211}-\frac{546}{547.211}-\frac{4}{547.211}\)

M = \(\frac{-544}{547.211}\)

27 tháng 7 2015

\(M=2.\frac{1}{547}.\frac{3}{211}-\frac{546}{547}.\frac{1}{211}-\frac{4}{547.211}\)

\(M=\left(2.\frac{1}{547}.\frac{3}{211}\right)-\left(\frac{546}{547}.\frac{1}{211}\right)-\left(\frac{4}{547.211}\right)\)

\(M=\frac{6}{547.211}-\frac{546}{547.211}-\frac{4}{547.211}\)

\(M=\frac{6}{115417}-\frac{546}{115417}-\frac{4}{115417}\)

\(M=\frac{-540}{115417}-\frac{4}{115417}\)

\(M=\frac{-544}{115417}\)

29 tháng 7 2019

đề bài hơi khó hiểu nha

Giải:

A=1/10+1/40+1/88+1/154+1/238+1/340

A=1/2.5+1/5.8+1/8.11+1/11.14+1/14.17+1/17.20

A=1/2-1/5+1/5-1/8+1/8-1/11+1/11-1/14+1/14-1/17+1/17-1/20

A=1/2-1/20

A=9/20

D=1/3+1/6+1/12+1/24+1/48

D=1/3+1/2.3+1/3.4+1/4.6+1/6.8

D=1/3+1/2-1/3+1/3-1/4+1/2.(2/4.6+2/6.8)

D=1/3+1/2-1/4+1/2.(1/4-1/6+1/6-1/8)

D=1/3+1/4+1/2.(1/4-1/8)

D=1/3+1/4+1/2.1/8

D=1/3+1/4+1/16

D=31/48

F=0,5-1/3-0,4-4/7-1/6+4/35-1/41

F=1/2-1/3-2/5-4/7-1/6+4/35-1/41

F=1/6-(-6/35)-1/6+4/35-1/41

F=(1/6-1/6)+(6/35+4/35)-1/41

F=0+2/7-1/41

F=2/7+1/41

F=75/287

Chúc bạn học tốt!

24 tháng 4 2021

Cảm ơn nhìu <3