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Đặt \(A=\frac{9+\frac{9}{11}+\frac{18}{23}-\frac{27}{37}}{8+\frac{8}{11}+\frac{16}{23}-\frac{24}{37}}-\frac{2+\frac{16}{29}-\frac{24}{13}-\frac{32}{11}}{3+\frac{24}{29}-\frac{36}{13}-\frac{48}{11}}\)\(=\frac{9\left(1+\frac{1}{11}+\frac{2}{23}-\frac{3}{37}\right)}{8\left(1+\frac{1}{11}+\frac{2}{23}-\frac{3}{37}\right)}-\frac{2\left(1+\frac{8}{29}-\frac{12}{13}-\frac{16}{11}\right)}{3\left(1+\frac{8}{29}-\frac{12}{13}-\frac{16}{11}\right)}\)
\(=\frac{9}{8}-\frac{2}{3}\)(do \(1+\frac{1}{11}+\frac{2}{23}-\frac{3}{37};1+\frac{8}{29}-\frac{12}{13}-\frac{16}{11}\ne0\))
\(=\frac{27}{24}-\frac{16}{24}=\frac{11}{24}.\)
Vậy A = \(\frac{11}{24}.\)
\(\left(\frac{37}{13}+\frac{25}{16}-\frac{9}{16}+\frac{15}{13}\right)\div\frac{3}{5}\)
\(=\left(4+1\right)\div\frac{3}{5}\)
\(=5\div\frac{3}{5}\)
\(=\frac{25}{3}\)
\(\frac{6}{2}+\frac{9}{24}=3+\frac{3}{8}=\frac{24}{8}+\frac{3}{8}=\frac{27}{8}\)
\(\frac{29}{16}+\frac{16}{32}=\frac{29}{16}+\frac{1}{2}=\frac{29}{16}+\frac{8}{16}=\frac{29+8}{16}=\frac{37}{16}\)
\(\frac{6}{2}+\frac{9}{24}=3+\frac{3}{8}=3\frac{3}{8}\)
\(\frac{29}{16}+\frac{16}{32}=\frac{29}{16}+\frac{8}{16}=\frac{37}{16}\)
-1/5 . (9/8 + 16/32 - 12/46) - 9/17
= -1/5 . (9/8 + 1/2 - 6/23) - 9/17
= -1/5 . (9/8 + 4/8 - 6/23) - 9/17
= -1/5 . (13/8 - 6/23) - 9/17
= -1/5 . 251/184 - 9/17
= -251/920 - 9/17
= -4267/15640 - 8280/15640
= -12547/15640
\(D=\frac{-1}{5}.\left(\frac{9}{8}+\frac{16}{32}-\frac{12}{46}\right)-\frac{9}{17}\)
\(D=\frac{-1}{5}.\frac{251}{184}+\frac{-9}{17}\)
\(D=\frac{-251}{920}+\frac{-9}{17}\)
\(D=\frac{-12547}{15640}\)
\(D=\frac{-1}{5}\cdot\left[\frac{9}{8}+\frac{16}{32}+\frac{12}{46}\right]-\frac{9}{17}\)
\(D=\frac{-1}{5}\cdot\left[\frac{9}{8}+\frac{1}{2}-\frac{6}{23}\right]-\frac{9}{17}\)
\(D=\frac{-1}{5}\cdot\left[\frac{9}{8}+\frac{4}{8}-\frac{6}{23}\right]-\frac{9}{17}\)
\(D=\frac{-1}{5}\cdot\left[\frac{15}{8}-\frac{6}{23}\right]-\frac{9}{17}\)
\(D=\frac{-1}{5}\cdot\left[\frac{345}{184}-\frac{48}{184}\right]-\frac{9}{17}\)
\(D=\frac{-1}{5}\cdot\frac{297}{184}-\frac{9}{17}\)
Tự tính
\(B=\frac{3+\frac{8}{12}+\frac{9}{13}-\frac{12}{17}}{4+\frac{8}{12}+\frac{12}{13}-\frac{16}{17}}+\frac{4+\frac{16}{60}-\frac{24}{213}-\frac{32}{11}}{5+\frac{20}{61}-\frac{36}{213}-\frac{40}{11}}\)
\(\Leftrightarrow B=\frac{3\left(1+\frac{8}{12}+\frac{3}{13}-\frac{4}{17}\right)}{4\left(1+\frac{8}{12}+\frac{3}{13}-\frac{4}{17}\right)}+\frac{4\left(1+\frac{4}{60}-\frac{6}{213}-\frac{8}{11}\right)}{5\left(1+\frac{4}{60}+\frac{6}{213}-\frac{8}{11}\right)}\)
\(\Leftrightarrow B=\frac{3}{4}+\frac{4}{5}\)
\(\Leftrightarrow B=\frac{15}{20}+\frac{16}{20}\)
\(\Leftrightarrow B=\frac{31}{20}\)
a) \(\frac{55}{32}\)
b) \(\frac{90}{48}\)
c) \(\frac{76}{15}\)
d) \(\frac{552}{119}\)
\(\frac{9}{16}+\frac{37}{32}=\frac{18}{32}+\frac{37}{32}=\frac{55}{32}\)
\(\frac{126}{48}-\frac{12}{16}=\frac{21}{8}-\frac{6}{8}=\frac{15}{8}\)
\(\frac{19}{15}\times\frac{32}{8}=\frac{19}{15}\times4=\frac{76}{15}\)
\(\frac{23}{17}:\frac{7}{24}=\frac{23}{17}.\frac{24}{7}=4\frac{76}{119}\)