2011+5[300-17)mũ 2]
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(2011+5\left[300-\left(17-7\right)^2\right]\)
\(=2011+5\left[300-10^2\right]\)
\(=2011+1000=3011\)
\(2011+5.\left[300-\left(17-7\right)^2\right]\)
\(=2011+5.\left[300-\left(10\right)^2\right]\)
\(=2011+5.\left[300-100\right]\)
\(=2011+5.200\)
\(=2011+1000\)
\(=3011\)
![](https://rs.olm.vn/images/avt/0.png?1311)
2011 + 5.[300 - (17 - 7)2]
= 2011 + 5.(300 - 102)
= 2011 + 5.(300 - 100)
= 2011 + 5.200
= 2011 + 1000
= 3011
bạn gặp đúng người đấy.Kết quả đúng nhất là 3011,nếu sai mình chịu gì cũng được
![](https://rs.olm.vn/images/avt/0.png?1311)
e) 2011 + 5[300 – (17 – 7)2 ]
= 2011 + 5[300 - 100]
= 2011 + 5 . 200
= 2011 + 1000
= 3011
=2011+5[300-10^2]
=2011+5[300-100]
=2011+5*200
=2011+1000
=3011
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2011+5\left[300-\left(17-7^2\right)\right]\)
\(=2011+5\left[300-\left(17-49\right)\right]\)
\(=2011+5\left[300-\left(-32\right)\right]\)
\(=2011+5.332\)
\(=2011+1660\)
\(=3671\)
\(2011+5\left[300-\left(17-7^2\right)\right]\)
\(=2011+5\left[300-\left(17-49\right)\right]\)
\(=2011+5\left[300-\left(-32\right)\right]\)
\(=2011+5.332\)
\(=2011+1660\)
\(=3671\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2011+5\left[300-\left(17-7\right)^2\right]\)
\(=2011+5\left[300-10^2\right]\)
\(=2011+5\left[300-100\right]\)
\(=2011+5.200\)
\(=2011+1000\)
\(=3011\)
học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
- 2011+5[300-(17-7)2]
- =2011+5[300-100]
- =2011+5+200
- =2011+205
=2216
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=2011+5\cdot\left[300-10^2\right]\)
\(=2011+5\cdot200\)
=1011
b: \(=695-\left[200+10^2\right]\)
=695-300
=395
a) =2011+5.200
=3011
b)=695-300
=395
c)1=29-5.4
=109
d)=2010-2000:400
=2010-5
=2005
2011 + 5 . 2832 = 2011 + 5 . 80089
= 2011 + 400445
= 402456