tìm x,biết a,\(\left|X-\dfrac{2}{5}\right| \dfrac{1}{2}=\dfrac{3}{4}\) b,\(\left|X-\dfrac{17}{10}\right|=\dfrac{23}{10}\) c,\(\left|x \dfrac{3}{5}\right|-\dfrac{1}{2}=\dfrac{1}{2}\) d,\(\left|2x-5...

#Toán lớp 10

1

DH

Dương Hạ Chi

13 tháng 7 2017

What? Lớp 10? Mí bài nỳ dễ mak! Trên lp cs hc mak k giải đc thì thui lun!

TT

trần thị anh thư

13 tháng 7 2017

tui mới lớp 7 mà

a)\(\left(3\dfrac{1}{2}+2x\right).3\dfrac{2}{3}=5\dfrac{1}{3}\) b) \(3-\left(17-x\right)=-12\)c) \(\dfrac{2}{3}x+\dfrac{1}{2}=\dfrac{1}{10}\) d) \(\dfrac{3}{4}-2.\left|2x-\dfrac{2}{3}\right|=2\)e) \(\left(-0,6x-\dfrac{1}{2}\right).\dfrac{3}{4}-\left(-1\right)=\dfrac{1}{3}\) ...

MN

Miru nèe

22 tháng 6 2021

#Toán lớp 6

4

T

꧁_͏ͥ͏_͏ͣ͏_͏ͫ͏ ¡亗ᵛᶰシ๖ۣۜT๖ۣۜR๖ۣۜÂ๖ۣ...

22 tháng 6 2021

Giải:

a) \(\left(3\dfrac{1}{2}+2x\right).3\dfrac{2}{3}=5\dfrac{1}{3}\)

\(\left(\dfrac{7}{2}+2x\right).\dfrac{11}{3}=\dfrac{16}{3}\)

\(\dfrac{7}{2}+2x=\dfrac{16}{3}:\dfrac{11}{3}\)

\(\dfrac{7}{2}+2x=\dfrac{16}{11}\)

\(2x=\dfrac{16}{11}-\dfrac{7}{2}\)

\(2x=\dfrac{-45}{22}\)

\(x=\dfrac{-45}{22}:2\)

\(x=\dfrac{-45}{44}\)

b) \(3-\left(17-x\right)=-12\)

\(3-17+x=-12\)

\(x=-12-3+17\)

\(x=2\)

c) \(\dfrac{2}{3}x+\dfrac{1}{2}=\dfrac{1}{10}\)

\(\dfrac{2}{3}x=\dfrac{1}{10}-\dfrac{1}{2}\)

\(\dfrac{2}{3}x=\dfrac{-2}{5}\)

\(x=\dfrac{-2}{5}:\dfrac{2}{3}\)

\(x=\dfrac{-3}{5}\)

d) \(\dfrac{3}{4}-2.\left|2x-\dfrac{2}{3}\right|=2\)

\(2.\left|2x-\dfrac{2}{3}\right|=\dfrac{3}{4}-2\)

\(2.\left|2x-\dfrac{2}{3}\right|=\dfrac{-5}{4}\)

\(\left|2x-\dfrac{2}{3}\right|=\dfrac{-5}{4}:2\)

\(\left|2x-\dfrac{2}{3}\right|=\dfrac{-5}{8}\)

Vì giá trị tuyệt đối của 1 số nguyên ko bao giờ là số âm nên \(x\in\varnothing\)

e) \(\left(-0,6x-\dfrac{1}{2}\right).\dfrac{3}{4}-\left(-1\right)=\dfrac{1}{3}\)

\(\left(-0,6x-\dfrac{1}{2}\right).\dfrac{3}{4}=\dfrac{1}{3}+\left(-1\right)\)

\(\left(-0,6x-\dfrac{1}{2}\right).\dfrac{3}{4}=\dfrac{-2}{3}\)

\(-0,6x-\dfrac{1}{2}=\dfrac{-2}{3}:\dfrac{3}{4}\)

\(-0,6x-\dfrac{1}{2}=\dfrac{-8}{9}\)

\(-0,6x=\dfrac{-8}{9}+\dfrac{1}{2}\)

\(-0,6x=\dfrac{-7}{18}\)

\(x=\dfrac{-7}{18}:-0.6\)

\(x=\dfrac{35}{54}\)

f) \(\left(3x-1\right).\left(\dfrac{-1}{2}x+5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}3x-1=0\\\dfrac{-1}{2}x+5=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=10\end{matrix}\right.\)

g) \(60\%.x+\dfrac{2}{3}=\dfrac{1}{3}.6\dfrac{1}{3}\)

\(\dfrac{3}{5}.x+\dfrac{2}{3}=\dfrac{1}{3}.\dfrac{19}{3}\)

\(\dfrac{3}{5}.x+\dfrac{2}{3}=\dfrac{19}{9}\)

\(\dfrac{3}{5}.x=\dfrac{19}{9}-\dfrac{2}{3}\)

\(\dfrac{3}{5}.x=\dfrac{13}{9}\)

\(x=\dfrac{13}{9}:\dfrac{3}{5}\)

\(x=\dfrac{65}{27}\)

Chúc bạn học tốt!

K

Kậu...chủ...nhỏ...!!!

22 tháng 6 2021

f)câu khó nhất

=>3x-1=0 và -1/2x+5=0

=>x=1/3 và x=10

1. \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\) 2. \(x-\dfrac{3\left(x+30\right)}{15}-24\dfrac{1}{2}=\dfrac{7x}{10}-\dfrac{2\left(10x+2\right)}{5}\) 3. \(14\dfrac{1}{2}-\dfrac{2\left(x+3\right)}{5}=\dfrac{3x}{2}-\dfrac{2\left(x-7\right)}{3}\) 4. \(\dfrac{x+1}{3}+\dfrac{3\left(2x+1\right)}{4}=\dfrac{2x+3\left(x+1\right)}{6}+\dfrac{7+12x}{12}\) 5. \(\dfrac{3\left(2x-1\right)}{4}-\dfrac{3x+1}{10}+1=\dfrac{2\left(3x+2\right)}{5}\) 6....

WH

원회으Won Hoe Eu

13 tháng 2 2019

#Toán lớp 8

0

NT

Nguyễn Thu Huyền

1 tháng 9 2023

Tìm...

a.,\(\dfrac{4}{5}+5\dfrac{1}{2}\text{x }\left(4,5-2\right)=\dfrac{7}{10}\) b,125%x\(\dfrac{17}{4}:\left(1\dfrac{5}{16}-0,5\right)+2008\)c,\(\dfrac{5}{11}+\left(\dfrac{16}{11}+1\right)\) ...

#Toán lớp 7

3

T

Toru

1 tháng 9 2023

\(a,3-x=x+1,8\)

\(\Rightarrow-x-x=1,8-3\)

\(\Rightarrow-2x=-1,2\)

\(\Rightarrow x=0,6\)

\(b,2x-5=7x+35\)

\(\Rightarrow2x-7x=35+5\)

\(\Rightarrow-5x=40\)

\(\Rightarrow x=-8\)

\(c,2\left(x+10\right)=3\left(x-6\right)\)

\(\Rightarrow2x+20=3x-18\)

\(\Rightarrow2x-3x=-18-20\)

\(\Rightarrow-x=-38\)

\(\Rightarrow x=38\)

\(d,8\left(x-\dfrac{3}{8}\right)+1=6\left(\dfrac{1}{6}+x\right)+x\)

\(\Rightarrow8x-3+1=1+6x+x\)

\(\Rightarrow8x-3=7x\)

\(\Rightarrow8x-7x=3\)

\(\Rightarrow x=3\)

\(e,\dfrac{2}{9}-3x=\dfrac{4}{3}-x\)

\(\Rightarrow-3x+x=\dfrac{4}{3}-\dfrac{2}{9}\)

\(\Rightarrow-2x=\dfrac{10}{9}\)

\(\Rightarrow x=-\dfrac{5}{9}\)

Đúng(3)

T

Toru

1 tháng 9 2023

\(g,\dfrac{1}{2}x+\dfrac{5}{6}=\dfrac{3}{4}x-\dfrac{1}{2}\)

\(\Rightarrow\dfrac{1}{2}x-\dfrac{3}{4}x=-\dfrac{1}{2}-\dfrac{5}{6}\)

\(\Rightarrow-\dfrac{1}{4}x=-\dfrac{4}{3}\)

\(\Rightarrow x=\dfrac{16}{3}\)

\(h,x-4=\dfrac{5}{6}\left(6-\dfrac{6}{5}x\right)\)

\(\Rightarrow x-4=5-x\)

\(\Rightarrow x+x=5+4\)

\(\Rightarrow2x=9\)

\(\Rightarrow x=\dfrac{9}{2}\)

\(k,7x^2-11=6x^2-2\)

\(\Rightarrow7x^2-6x^2=-2+11\)

\(\Rightarrow x^2=9\Rightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

\(m,5\left(x+3\cdot2^3\right)=10^2\)

\(\Rightarrow5\left(x+24\right)=100\)

\(\Rightarrow x+24=20\)

\(\Rightarrow x=-4\)

\(n,\dfrac{4}{9}-\left(\dfrac{1}{6^2}\right)=\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}\)

\(\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}=\dfrac{4}{9}-\dfrac{1}{36}\)

\(\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2+\dfrac{5}{12}=\dfrac{5}{12}\)

\(\Rightarrow\dfrac{2}{3}\left(x-\dfrac{2}{3}\right)^2=0\)

\(\Rightarrow x-\dfrac{2}{3}=0\Rightarrow x=\dfrac{2}{3}\)

#\(Urushi\text{☕}\)

Đúng(3)

M

mtruc.owo

24 tháng 6 2021

#Toán lớp 5

2

Y

Yeutoanhoc

24 tháng 6 2021

`a)4/5+5 1/2 xx (4,5-2)+7/10`

`=4/5+11/2*2,5+7/10`

`=0,8+2,2+0,7`

`=3+0,7=3,7`

`b)125%xx 17/4:(1 5/16-0,5)+2008`

`=1,25xx4,25:13/16+2008`

`=85/13+2008`

`=2014 7/13`

`c)5/11+(16/11+1)`

`=5/11+1+5/11+1`

`=2+10/11=32/11`

`d)3/17+11/4+5/8+14/17+3/8`

`=3/17+14/17+5/8+3/8+11/4`

`=1+1+11/4`

`=19/4`

Đúng(3)

D

๖ۣۜDũ๖ۣۜN๖ۣۜG

24 tháng 6 2021

a)

\(\dfrac{4}{5}+5\dfrac{1}{2}x\left(4,5-2\right)=\dfrac{7}{10}\)

<=> \(\dfrac{11}{2}x\times2,5=\dfrac{7}{10}-\dfrac{4}{5}=\dfrac{-1}{10}\)

<=> \(\dfrac{55}{4}x=\dfrac{-1}{10}< =>x=\dfrac{-2}{275}\)

b) \(125\%\times\dfrac{17}{4}:\left(1\dfrac{5}{16}-0,5\right)+2008\)

= \(\dfrac{85}{16}:\left(\dfrac{21}{16}-\dfrac{1}{2}\right)+2008=\dfrac{85}{16}:\dfrac{13}{16}+2008=\dfrac{26189}{13}\)

c) \(\dfrac{5}{11}+\left(\dfrac{16}{11}+1\right)\)

= \(\dfrac{21}{11}+1=\dfrac{32}{11}\)

d) \(\left(\dfrac{3}{17}+\dfrac{14}{17}\right)+\left(\dfrac{5}{8}+\dfrac{3}{8}\right)+\dfrac{11}{4}\)

= 1 + 1 + \(\dfrac{11}{4}\) = \(\dfrac{19}{4}\)

Tìm x biết: a) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\) b) \(x-\dfrac{1}{8}=\dfrac{5}{8}\)c) \(-\dfrac{1}{2}-\left(\dfrac{3}{2}+x\right)=-2\) ...

NH

Nguyễn Hữu Bình

18 tháng 4 2022

#Toán lớp 6

1

O

★彡✿ทợท彡★

18 tháng 4 2022

a) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)

Th1 : \(x-\dfrac{1}{2}=0\)

\(x=0+\dfrac{1}{2}\)

\(x=\dfrac{1}{2}\)

Th2 : \(-3-\dfrac{x}{2}=0\)

\(\dfrac{x}{2}=-3\)

\(x=\left(-3\right)\cdot2\)

\(x=-6\)

Vậy \(x\) = \(\left(\dfrac{1}{2};-6\right)\)

b) \(x-\dfrac{1}{8}=\dfrac{5}{8}\)

\(x=\dfrac{5}{8}+\dfrac{1}{8}\)

\(x=\dfrac{3}{4}\)

c) \(-\dfrac{1}{2}-\left(\dfrac{3}{2}+x\right)=-2\)

\(\dfrac{3}{2}+x=-\dfrac{1}{2}-\left(-2\right)\)

\(\dfrac{3}{2}+x=\dfrac{3}{2}\)

\(x=\dfrac{3}{2}-\dfrac{3}{2}\)

\(x=0\)

d) \(x+\dfrac{1}{3}=\dfrac{-12}{5}\cdot\dfrac{10}{6}\)

\(x+\dfrac{1}{3}=-4\)

\(x=-4-\dfrac{1}{3}\)

\(x=-\dfrac{13}{3}\)

KJ

❖ Khang/GD❄ 『ʈєɑɱ❖Hoàng๖ۣۜGia☆』

28 tháng 2 2022

Tìm x biết:

\(a,\left(x-\dfrac{3}{4}\right)+50\%=\dfrac{1}{6}\)

\(b,\dfrac{1}{2}x-\dfrac{5}{6}x=\dfrac{7}{2}\)

\(c,\left(4-x\right)\left(3x+5\right)=0\)

\(d,\dfrac{x}{16}=\dfrac{50}{32}\)

\(e,\left(2x-3\right)+\dfrac{3}{2}=-\dfrac{1}{4}\)

#Toán lớp 6

1

NL

Nguyễn Lê Phước Thịnh

28 tháng 2 2022

a: =>x-3/4=1/6-1/2=1/6-3/6=-2/6=-1/3

=>x=-1/3+3/4=-4/12+9/12=5/12

b: =>x(1/2-5/6)=7/2

=>-1/3x=7/2

hay x=-21/2

c: (4-x)(3x+5)=0

=>4-x=0 hoặc 3x+5=0

=>x=4 hoặc x=-5/3

d: x/16=50/32

=>x/16=25/16

hay x=25

e: =>2x-3=-1/4-3/2=-1/4-6/4=-7/4

=>2x=-7/4+3=5/4

hay x=5/8

Tìm x : a) \(\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\) b) \(\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\) c) \(\dfrac{x+2014}{2}+\dfrac{2x+4028}{7}=\dfrac{x+2009}{5}+\dfrac{x+2020}{6}\) d)\(\dfrac{3}{\left(x+2\right)\left(x+5\right)}+\dfrac{5}{\left(x+5\right)\left(x+10\right)}+\dfrac{7}{\left(x+10\right)\left(x+18\right)}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\) Help me , bn nào giải đc bài nò thì giải nha !!!...

TN

Triều Nguyễn Quốc

14 tháng 7 2018

#Toán lớp 7

1

NL

Nguyễn Lê Phước Thịnh

25 tháng 7 2022

a: =>4x-6-9=5-3x-3

=>4x-15=-3x+2

=>7x=17

hay x=17/7

b: \(\Leftrightarrow\dfrac{2}{3x}-\dfrac{1}{4}=\dfrac{4}{5}-\dfrac{7}{x}+2\)

=>2/3x+21/3x=4/5+2+1/4=61/20

=>23/3x=61/20

=>3x=23:61/20=460/61

hay x=460/183

Giải các phương trình sau...

SG

Sách Giáo Khoa

3 tháng 5 2017

#Toán lớp 8

1

NT

Nguyen Thuy Hoa

4 tháng 7 2017

Phương trình đưa được về dạng ax + b = 0

DT

ĐOÀN THỊ MINH HIỀN

26 tháng 9 2021

\(b,\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=-\left(\dfrac{7}{5}+\dfrac{7}{10}.x\right)\)

\(c,\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)

\(d,\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)

\(e,2\left(x-1\right)=\left(x-1\right)^2\)

#Toán lớp 7

2

NH

Nguyễn Hoàng Minh

26 tháng 9 2021

\(b,\Rightarrow\dfrac{x}{2}-\dfrac{3x}{5}-\dfrac{13}{5}=-\dfrac{7}{5}-\dfrac{7x}{10}\\ \Rightarrow\dfrac{1}{2}x-\dfrac{3}{5}x+\dfrac{7}{10}x=\dfrac{6}{5}\\ \Rightarrow\dfrac{3}{5}x=\dfrac{6}{5}\Rightarrow x=2\\ c,\Rightarrow\dfrac{2x-3}{3}-\dfrac{5-3x}{6}=-\dfrac{1}{3}+\dfrac{3}{2}=\dfrac{7}{6}\\ \Rightarrow\dfrac{4x-6-5+3x}{6}=\dfrac{7}{6}\\ \Rightarrow7x-11=7\Rightarrow x=\dfrac{18}{7}\\ d,\Rightarrow\dfrac{2}{3x}+\dfrac{7}{x}=\dfrac{4}{5}+2+\dfrac{3}{12}=\dfrac{61}{20}\\ \Rightarrow\dfrac{23}{3x}=\dfrac{61}{20}\\ \Rightarrow183x=460\\ \Rightarrow x=\dfrac{460}{183}\\ e,\Rightarrow2\left(x-1\right)-\left(x-1\right)^2=0\\ \Rightarrow\left(x-1\right)\left(2-x+1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)

Đúng(2)

NL

Nguyễn Lê Phước Thịnh

26 tháng 9 2021

e: Ta có: \(\left(x-1\right)^2=2\left(x-1\right)\)

\(\Leftrightarrow\left(x-1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)

Giải phương trình :a,\(\dfrac{2x 1}{6}-\dfrac{x-2}{4}=\dfrac{3-2x}{3}-x\)b,\(\dfrac{3\left(2x 1\right)}{4}-5-\dfrac{3x 2}{10}=\dfrac{2\left(3x-1\right)}{5}\)\(c,\dfrac{x 1}{2009} \dfrac{x 3}{2007}=\dfrac{x 5}{2005} \dfrac{x 7}{2003}\)\(d,\dfrac{392-x...

KH

Kamato Heiji

5 tháng 3 2021

#Toán lớp 8

7

NL

Nguyễn Lê Phước Thịnh

5 tháng 3 2021

a) Ta có: \(\dfrac{2x+1}{6}-\dfrac{x-2}{4}=\dfrac{3-2x}{3}-x\)

\(\Leftrightarrow\dfrac{2\left(2x+1\right)}{12}-\dfrac{3\left(x-2\right)}{12}=\dfrac{4\left(3-2x\right)}{12}-\dfrac{12x}{12}\)

\(\Leftrightarrow4x+2-3x+6=12-8x-12x\)

\(\Leftrightarrow x+8-12+20x=0\)

\(\Leftrightarrow21x-4=0\)

\(\Leftrightarrow21x=4\)

\(\Leftrightarrow x=\dfrac{4}{21}\)

Vậy: \(S=\left\{\dfrac{4}{21}\right\}\)

Đúng(2)

AH

Akai Haruma

Giáo viên

5 tháng 3 2021

Hình như em viết công thức bị lỗi rồi. Em cần chỉnh sửa lại để được hỗ trợ tốt hơn!