54°F = ?°C
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VT
1
CM
10 tháng 8 2018
a ) x = 21 55 ; b ) x = − 11 26 ; c ) x = 11 18 ; d ) x = 1
d ) x = − 1 ; e ) x = 11 7 ; f ) x = 20
H
4 tháng 2 2023
\(a,\dfrac{52}{32}=\dfrac{13}{8}\\ \dfrac{55}{65}=\dfrac{11}{13}\\ MSC:104\\ =>\dfrac{13}{8}=\dfrac{13.13}{8.13}=\dfrac{169}{104}\\ \dfrac{11}{13}=\dfrac{11.8}{13.8}=\dfrac{88}{104}\)
\(b,\dfrac{72}{64}=\dfrac{9}{8}\\ \dfrac{54}{81}=\dfrac{2}{3}\\ MSC:24\\ \dfrac{9}{8}=\dfrac{9.3}{8.3}=\dfrac{27}{24}\\ \dfrac{2}{3}=\dfrac{2.8}{3.8}=\dfrac{16}{24}\\ c,\dfrac{24}{36}=\dfrac{2}{3}\\ \dfrac{12}{30}=\dfrac{2}{5}\\ MSC:15\\ \dfrac{2}{3}=\dfrac{2.5}{3.5}=\dfrac{10}{15}\\ \dfrac{2}{5}=\dfrac{2.3}{3.5}=\dfrac{6}{15}\)
\(d,\dfrac{80}{40}=2\\ \dfrac{45}{63}=\dfrac{5}{7}\\ MSC:7\\ 2=\dfrac{14}{7}\\ e,\dfrac{150}{50}=3\\ \dfrac{100}{200}=\dfrac{1}{2}\\ MSC:2\\ 3=\dfrac{6}{2}\\ f,\dfrac{54}{81}=\dfrac{2}{3}\\ \dfrac{69}{93}=\dfrac{23}{21}\\ MSC:21\\ \dfrac{2}{3}=\dfrac{2.7}{3.7}=\dfrac{14}{21}\)
NT
Nguyễn thành Đạt
CTVHS
4 tháng 2 2023
\(a.\dfrac{52}{32}\text{=}\dfrac{13}{8};\dfrac{55}{65}\text{=}\dfrac{11}{13}\)
\(\dfrac{13.13}{13.8}\text{=}\dfrac{169}{104};\dfrac{11.8}{13.8}\text{=}\dfrac{88}{104}\)
\(c.\dfrac{24}{36}\text{=}\dfrac{2}{3};\dfrac{12}{30}\text{=}\dfrac{2}{5}\)
\(\dfrac{2.5}{3.5}\text{=}\dfrac{10}{15};\dfrac{2.3}{5.3}\text{=}\dfrac{6}{15}\)
\(b.\dfrac{72}{64}\text{=}\dfrac{9.3}{8.3}\text{=}\dfrac{27}{24};\dfrac{54}{81}\text{=}\dfrac{2.8}{3.8}\text{=}\dfrac{16}{24}\)
\(d.\dfrac{80}{40}\text{=}\dfrac{2.63}{63}\text{=}\dfrac{126}{63};\dfrac{45}{63}\)
\(e.\dfrac{150}{50}\text{=}\dfrac{3.2}{2}\text{=}\dfrac{6}{2};\dfrac{100}{200}\text{=}\dfrac{1}{2}\)
\(f.\dfrac{54}{81}\text{=}\dfrac{2.31}{3.31}\text{=}\dfrac{62}{93};\dfrac{69}{93}\)
CM
2 tháng 4 2018
a, 8 2 . 32 4 = 2 3 2 . 2 5 4 = 2 3 . 2 . 2 5 . 4 = 2 6 . 2 20 = 2 6 + 20 = 2 26
b, 27 4 . 9 3 . 243 = 3 3 4 . 3 2 3 . 3 5 = 3 3 . 4 . 3 2 . 3 . 3 5 = 3 12 . 3 6 . 3 5 = 3 12 + 6 + 5 = 3 23
c, 13 2 - 12 2 = 169 - 144 = 25 = 5 2
d, 6 2 + 8 2 = 36 + 64 = 100 = 10 2
e, 5 3 + 5 4 + 125 2 . 5 3 = 5 3 + 5 4 + 5 3 . 2 . 5 3 = 5 3 + 5 4 + 5 6 . 5 3 = 5 3 . 1 + 5 + 5 3 . 5 3 = 5 6 . 131
f, 1 3 + 2 3 + 3 3 + 4 3 + 5 3 = 1 + 8 + 27 + 64 + 125 = 225 = 15 2
Giải:
54o F = \(\dfrac{54^oF-32^oF}{1,8^oF}.\)
= \(\dfrac{22^oF}{1,8^oF}.\)
= \(12,222222....^oC.\left(\approx13^oC\right).\)
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54o F = 12.2222222 o C