Tính
a,A = [3 × (-7)^7 -10× (-7)^7] : (-7)^6
b,B= (-11)^9 : [ 5 × (-11)^5 - 16 × (-11)^5
c,C= (-125)×25×(-32)
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a) \(4^8\cdot4^4=\left(2^2\right)^8\cdot\left(2^2\right)^4=2^{16}\cdot2^8=2^{16+8}=2^{24}\)
b) \(5^{12}\cdot7-5^{11}\cdot10\)
\(=5^{11}\cdot\left(5\cdot7-10\right)=5^{11}\cdot\left(35-10\right)=5^{11}\cdot25\)
\(=5^{11}\cdot5^2=5^{11+2}=5^{13}\)
d) \(27^{16}:9^{10}\)
\(=\left(3^3\right)^{16}:\left(3^2\right)^{10}=3^{48}:3^{20}=3^{48-20}=3^{28}\)
e) \(125^3:25^4=\left(5^3\right)^3:\left(5^2\right)^4=5^9:5^8=5^{9-8}=5\)
f) \(24^4:3^4-32^{12}:16^{12}\)
\(=\left(24:4\right)^4-\left(32:16\right)^{12}\)
\(=6^4-2^{12}\)
\(=2^4\cdot\left(3^4-2^8\right)=2^4\cdot-175=-2800\)
\(a,\dfrac{5^{16}\cdot27^7}{125^5\cdot9^{11}}=\dfrac{5^{16}\cdot\left(3^3\right)^7}{\left(5^3\right)^5\cdot\left(3^2\right)^{11}}\)
\(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)
\(b,\left(-0,2\right)^2\cdot5-\dfrac{2^{13}\cdot27^3}{4^6\cdot9^5}\)
\(=0,04\cdot5-\dfrac{2^{13}\cdot\left(3^3\right)^3}{\left(2^2\right)^6\cdot\left(3^2\right)^5}\)
\(=0,2-\dfrac{2^{13}\cdot3^9}{2^{12}\cdot3^{10}}\)
\(=0,2-\dfrac{2}{3}\)
\(=-\dfrac{7}{15}\)
\(c,\dfrac{5^6+2^2\cdot25^3+2^3\cdot125^2}{26\cdot5^6}\)
\(=\dfrac{5^6+2^2\cdot\left(5^2\right)^3+2^3\cdot\left(5^3\right)^2}{5^6\cdot26}\)
\(=\dfrac{5^6+4\cdot5^6+8\cdot5^6}{5^6\cdot26}\)
\(=\dfrac{5^6\left(1+4+8\right)}{5^6\cdot26}\)
\(=\dfrac{13}{26}\)
\(=\dfrac{1}{2}\)
#\(Toru\)
\(a,\dfrac{5^{16}.27^7}{125^5.9^{11}}=\dfrac{\left(5^2\right)^8.9^7.3^7}{25^5.5^5.9^{11}}\\ =\dfrac{25^8.9^7.\left(3^2\right)^3.3}{25^5.\left(5^2\right)^2.5.9^{11}}=\dfrac{25^8.9^7.9^3.3}{25^5.25^2.5.9^{11}}\\ =\dfrac{25^8.9^{10}.3}{25^7.5.9^{11}}=\dfrac{25^7.9^{10}.25.3}{25^7.9^{10}.5.9}\\ =\dfrac{25.3}{5.9}=\dfrac{5.5.3}{5.3.3}=\dfrac{5}{3}\)
a) \(27^7\div9^{10}\)
\(=\left(3^3\right)^7\div\left(3^2\right)^{10}\)
\(=3^{3\times7}\div3^{2\times10}\)
\(=3^{21}\div3^{20}\)
\(=3^1\)
\(=3\)
b) \(125^6\div25^7\)
\(=\left(5^3\right)^6\div\left(5^2\right)^7\)
\(=5^{3\times6}\div5^{2\times7}\)
\(=5^{18}\div5^{14}\)
\(=5^4\)
\(=625\)
c) \(5^{15}\div5^3\)
\(=5^{12}\)
\(=244140625\)
d) \(11^7\div11^3\)
\(=11^4\)
\(=14641\)
e) \(125\div5^2\)
\(=5^2\div5^2\)
\(=5^1\)
\(=5\)
g) \(169\div13^2\)
\(=13^2\div13^2\)
\(=13^1\)
\(=13\)
\(a.=5-3+12-4-16\)
\(=-2\)
\(b.=-6-\left(-12\right)+7-10\)
\(=6+7-10\)
\(=3\)
a. - 7 - 9 = - (7 + 9) = - 16
b. - 15 - 8 = - (15 + 8) = - 23
c. - 28 - 32 = - (28 + 32) = - 60
d. - 43 - 32 = - (43 + 32) = - 75
e. - 5 - 9 - 11
= - (5 + 9 + 11)
= - (14 + 11)
= - 25
f. - 6 - 8 - 13
= - (6 + 8 + 13)
= - (14 + 13)
= - 27
g. - 3 - 7 - 25
= - (3 + 7 + 25)
= - (10 + 25)
= - 35
h. - 7 - 4 - 15
= - (7 + 4 + 15)
= - (11 + 15)
= - 26
a: =-1+17/20=-3/20
b: =(28/60-33/60)*(-25/3)
=(-1/12)*(-25/3)=1/12*25/3=25/36
c: \(=\dfrac{1}{3}\cdot\dfrac{1}{3}=\dfrac{1}{9}\)
A= 13;21;34
B= 37;70;135
C= 64;128;256
D= 22;29;37
E= 53;68;75
F= 127;255;511
G= 49;64;81
H= 324;841;2209
I= chịu
k cho mk nha!
a, A={x thuộc các số nguyên tố |2<hoặc bằng x<hoặc bằng 7}
oặc A={x thuộc R |(x^2-5*x+6)*(x^2-12*x+35)=0}
b,B={x thuộc Z | -3<hoặc bằng x<hoặc bằng 3}
c,C={5*x thuộc Z |-1<hoặc bằng x<hoặc bằng 3}
Cái này bạn tự tính đi!