240 - 9x + 7x +x = 235
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\(x+120=240\)
\(x=240-120\)
\(x=120\)
\(9x+3=102\)
\(9x=102-3\)
\(9x=99\)
\(x=99\div9\)
\(x=11\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x^3-9x+7x^2-63=0\)
\(\Rightarrow\left(x^3+7x^2\right)-9x-63=0\)
\(\Rightarrow x^2\left(x+7\right)-9\left(x+7\right)=0\)
\(\Rightarrow\left(x^2-9\right)\left(x+7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x^2-9=0\\x+7=0\end{cases}\Rightarrow\orbr{\begin{cases}x^2=9\\x=-7\end{cases}\Rightarrow}\orbr{\begin{cases}x=\pm3\\x=-7\end{cases}}}\)
Vậy ...
x3−9x+7x2−63=0x3−9x+7x2−63=0
⇒(x3+7x2)−9x−63=0⇒(x3+7x2)−9x−63=0
⇒x2(x+7)−9(x+7)=0⇒x2(x+7)−9(x+7)=0
⇒(x2−9)(x+7)=0⇒(x2−9)(x+7)=0
⇒{x2−9=0x+7=0⇒{x2=9x=−7⇒{x=±3x=−7⇒{x2−9=0x+7=0⇒{x2=9x=−7⇒{x=±3x=−7
Vậy ...
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a: \(\dfrac{x^2-5x+6}{x^2+7x+12}:\dfrac{x^2-4x+4}{x^2+3x}\)
\(=\dfrac{\left(x-2\right)\left(x-3\right)}{\left(x+3\right)\left(x+4\right)}\cdot\dfrac{x\left(x+3\right)}{\left(x-2\right)^2}\)
\(=\dfrac{x\left(x-3\right)}{\left(x-2\right)\left(x+4\right)}\)
b: \(\dfrac{x^2+2x-3}{x^2+3x-10}:\dfrac{x^2+7x+12}{x^2-9x+14}\)
\(=\dfrac{\left(x+3\right)\left(x-1\right)}{\left(x+5\right)\left(x-2\right)}\cdot\dfrac{\left(x-2\right)\left(x-7\right)}{\left(x+3\right)\left(x+4\right)}\)
\(=\dfrac{\left(x-1\right)\left(x-7\right)}{\left(x+5\right)\left(x+4\right)}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
7x + 2x = 918
(7+2)x=918
9x=918
x = 102
3.(x-2)+150=240
3.(x-2) = 240 - 150 = 90
x - 2 = 90 : 3 = 30
x= 30 + 2
x=32
7x + 2x = 918
(7+2)x=918
9x=918
x = 102
3.(x-2)+150=240
3.(x-2) = 240 - 150 = 90
x - 2 = 90 : 3 = 30
x= 30 + 2
x=32
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x^2-5x+6=\left(x-2\right)\left(x-3\right)\)
\(x^2-7x+12=\left(x-2\right)\left(x-5\right)\)
\(x^2+x-12=\left(x-5\right)\left(x+6\right)\)
\(x^2-9x+20=\left(x-4\right)\left(x-5\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
x+9x+7x+5x=2244
x.1+9.x+7.x+5.x=2244
x.(1+9+7+5)=2244
x.22=2244
x=2244:22
x=102
![](https://rs.olm.vn/images/avt/0.png?1311)
x + 9x + 7x + 5x = 2244
1x + 9x + 7x + 5x = 2244
x(1+9+7+5) = 2244
x.22 = 2244
=> x = 102
\(240-9x+7x+x=235\)
\(240-x=235\)
\(x=240-235\)
\(x=5\)
Vậy x = 5
Ta có: 240 -9x +7x +x = 235
240 - (9x -7x -x ) = 235
240 - x = 235
=> x = 240 -235
=> x = 5