Tính bằng cách thuận tiện nhất
a)14,52:1,5-9,81:1,5=
=
=
b)5/9:4/7+13/9*7/4=
=
=
=
* là dấu nhân
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\(a.14,52\div1,5-9,81\div1,5\)
\(=\left(14,52-9,81\right)\div1,5\)
\(=4,71\div1,5=3,14\)
\(b.\frac{5}{9}:\frac{4}{7}+\frac{13}{9}\times\frac{7}{4}\)
\(=\frac{5}{9}\times\frac{7}{4}+\frac{13}{9}\times\frac{7}{4}\)
\(=\left(\frac{5}{9}+\frac{13}{9}\right)\times\frac{7}{4}\)
\(=\frac{18}{9}\times\frac{7}{4}\)
\(=2\times\frac{7}{4}\)
\(=\frac{7}{2}\)
14,52:1,5-9,81:1,5=( 14,52-9,81 ) : 1,5
=4,71:1,5
=3,14
con thứ 2 thì mình chịu, bạn tự làm nha.
học tốt lên nhé. mình chỉ biết làm luôn thôi nhé.
\(\dfrac{8}{13}+\dfrac{4}{9}+\dfrac{1}{3}+\dfrac{5}{13}+3\)
\(=1+\dfrac{7}{9}+3\)
\(=4+\dfrac{7}{9}=\dfrac{43}{9}\)
`39/16 : 5/8 - 7/16 : 5/8`
`=39/16 xx 8/5- 7/16 xx 8/5`
`=8/5 xx (39/16 - 7/16)`
`= 8/5 xx2`
`= 16/5`
__
` 4/3 xx 9/8 - 4/3 xx 3/8`
`=4/3 -(9/8 - 3/8)`
`= 4/3 xx 3/4`
`=1`
\(a,\\ \dfrac{39}{16}:\dfrac{5}{8}-\dfrac{7}{16}:\dfrac{5}{8}\\ =\dfrac{39}{16}\cdot\dfrac{8}{5}-\dfrac{7}{16}\cdot\dfrac{8}{5}\\ =\dfrac{8}{5}\cdot\left(\dfrac{39}{16}-\dfrac{7}{16}\right)=\dfrac{8}{5}\cdot2=\dfrac{16}{5}\\ b,\\ \dfrac{4}{3}\cdot\dfrac{9}{8}-\dfrac{4}{3}\cdot\dfrac{3}{8}=\dfrac{3}{2}-\dfrac{1}{2}=1\)
Bài 4:
a: \(=\dfrac{11}{21}\left(\dfrac{7}{4}+\dfrac{5}{4}\right)=\dfrac{11}{21}\cdot3=\dfrac{11}{7}\)
b: \(=\dfrac{6}{13}\left(\dfrac{23}{14}-\dfrac{9}{14}\right)=\dfrac{6}{13}\)
Bài 4:
a: =11/21(7/4+5/4)=11/21x3=11/7
b: =6/13(23/14-9/14)=6/13
\(=\dfrac{5}{9}\times\dfrac{7}{4}+\dfrac{13}{9}\times\dfrac{7}{4}\\ =\left(\dfrac{5}{9}+\dfrac{13}{9}\right)\times\dfrac{7}{4}\\ =2\times\dfrac{7}{4}\\ =\dfrac{7}{2}\)
\(=\dfrac{5}{9}\times\dfrac{7}{4}+\dfrac{13}{9}\times\dfrac{7}{4}=\dfrac{7}{4}\times\left(\dfrac{5}{9}+\dfrac{13}{9}\right)=\dfrac{7}{4}\times2=\dfrac{7}{2}\)
a) 14,25 : 1,5 - 9,81 : 1,5 = (14,25 - 9,81) : 1,5
= 4,44 : 1,5
= 2,96
b) \(\frac{5}{9}\): \(\frac{4}{7}+\frac{13}{9}\) * \(\frac{7}{4}\) = \(\frac{5}{9}\cdot\frac{7}{4}+\frac{13}{9}\cdot\frac{7}{4}\)
= \(\left(\frac{5}{9}+\frac{13}{9}\right)\cdot\frac{7}{4}\)
= 2 \(\cdot\frac{7}{4}\)
= \(\frac{7}{2}\)