Rút gọn: A = \(\frac{1999\times2001-1}{1998\times1999\times2000}\times\frac{7}{5}:\frac{14}{15}\)
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
DT
0
NT
6
5 tháng 5 2016
\(\frac{1999.2001-1}{1998+1999.2000}=\frac{1999.2001-\left(1999-1998\right)}{1998+1999.2000}=\frac{1999.2001-1999+1998}{1998+1999.2000}=\frac{1999.\left(20001-1\right)+1998}{1998+1999.2000}=\frac{1999.2000+1998}{1998+1999.2000}=1\)=> đáp án là 7/5
HP
5
16 tháng 8 2017
Ttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttat ca nhan voi 7/5 nua
HP
2
11 tháng 6 2015
\(A=\frac{1999\times2001-1}{1998+1999\times2000}=\frac{1999\times2000+1999-1}{1998+1999\times2000}=\frac{1999\times2000+1998}{1998+1999\times2000}=1\)
LT
1
6 tháng 9 2016
\(\frac{-1}{2000\cdot1999}-\frac{1}{1999\cdot1998}-\frac{1}{1998\cdot1997}\)
\(=-\left(\frac{1}{2000\cdot1999}+\frac{1}{1999\cdot1998}+\frac{1}{1998\cdot1997}\right)\)
\(=-\left(\frac{1}{1997\cdot1998}+\frac{1}{1998\cdot1999}+\frac{1}{1999\cdot2000}\right)\)
\(=-\left(\frac{1}{1997}-\frac{1}{1998}+\frac{1}{1998}-\frac{1}{1999}+\frac{1}{1999}-\frac{1}{2000}\right)\)
\(=-\left(\frac{1}{1997}-\frac{1}{2000}\right)\)
\(=-\frac{3}{3994000}\)
IA
25 tháng 3 2020
1, =\(\frac{2\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}-\frac{1}{11}\right)}{4\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{9}-\frac{1}{11}\right)}=\frac{1}{2}\)
2, A=\(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{99}{100}\)
= \(\frac{1\cdot2\cdot3\cdot....\cdot99}{2\cdot3\cdot4\cdot...\cdot100}=\frac{1}{100}\)
Vậy ......
hok tốt
25 tháng 5 2016
A=3/4x8/9x15/16x24/25x...x899/900
A=1.3/22 x 2.4/33 x 3.5/42 x 4.6/55 x ... x 29.31/302
A=1.2.3.4...29/2.3.4.5...30 x 3.4.5.6...31/2.3.4.5...30
A=1/30 x 31/2
A=31/60
\(\frac{1999.2001-1}{1998.1999.2000}.\frac{7}{5}:\frac{14}{15}\)=\(\frac{1.7.15}{1998.5.14}=\frac{1.1.3}{1998.1.2}=\frac{3}{3996}=\frac{1}{1332}\)
\(A=\frac{1999\times\left(2000+1\right)-1}{1998\times1999\times2000}\times\frac{7}{5}\times\frac{15}{14}=\frac{1999\times2000+1999-1}{1998\times1999\times2000}\times\frac{7}{5}\times\frac{5\times3}{7\times2}\)
\(A=\frac{1999\times2000+1998}{1998\times1999\times2000}\times\frac{3}{2}=\frac{3999998\times3}{3\times666\times1999\times2000\times2}=\frac{1999999\times2}{666\times1999\times2000\times2}=\frac{1999999}{666\times1999\times2000}=...\)
Em xem lại đề: có thể đề là:
A = \(\frac{1999\times2001-1}{1998+1999\times2000}\times\frac{7}{5}:\frac{14}{15}\)= \(\frac{1999\times2000+1999-1}{1998\times1999\times2000}\times\frac{7}{5}\times\frac{5\times3}{7\times2}\)= \(\frac{1999\times2000+1998}{1998+1999\times2000}\times\frac{3}{2}=1\times\frac{3}{2}=\frac{3}{2}\)