11/3:2 +2/3=? 3/4x3/3:2/7
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6: \(-x^2y\left(xy^2-\dfrac{1}{2}xy+\dfrac{3}{4}x^2y^2\right)\)
\(=-x^3y^3+\dfrac{1}{2}x^3y^2-\dfrac{3}{4}x^4y^3\)
7: \(\dfrac{2}{3}x^2y\cdot\left(3xy-x^2+y\right)\)
\(=2x^3y^2-\dfrac{2}{3}x^4y+\dfrac{2}{3}x^2y^2\)
8: \(-\dfrac{1}{2}xy\left(4x^3-5xy+2x\right)\)
\(=-2x^4y+\dfrac{5}{2}x^2y^2-x^2y\)
9: \(2x^2\left(x^2+3x+\dfrac{1}{2}\right)=2x^4+6x^3+x^2\)
10: \(-\dfrac{3}{2}x^4y^2\left(6x^4-\dfrac{10}{9}x^2y^3-y^5\right)\)
\(=-9x^8y^2+\dfrac{5}{3}x^6y^5+\dfrac{3}{2}x^4y^7\)
11: \(\dfrac{2}{3}x^3\left(x+x^2-\dfrac{3}{4}x^5\right)=\dfrac{2}{3}x^3+\dfrac{2}{3}x^5-\dfrac{1}{2}x^8\)
12: \(2xy^2\left(xy+3x^2y-\dfrac{2}{3}xy^3\right)=2x^2y^3+6x^3y^3-\dfrac{4}{3}x^2y^5\)
13: \(3x\left(2x^3-\dfrac{1}{3}x^2-4x\right)=6x^4-x^3-12x^2\)
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P = \(\frac{5.3^{11}+4.3^{12}}{3^9.5^2-3^9.2^2}\)
= \(\frac{\left(5+4.3\right).3^{11}}{3^9.\left(5^2-2^2\right)}\)
=\(\frac{17.3^{11}}{3^9.21}\)
= \(\frac{17.3^2}{7.3}\)
= \(\frac{17.3}{7}=\frac{51}{7}\)
11/3 : 2 + 2/3 = 11/3 x 2/1 + 2/3 = 11/3 x 1/2 +2/3 = 11/6 + 2/3 = 11/6 + 4/6 = 15/6
3/4 x 3/2 : 2/7 = 9/6 : 2/7 = 3/2 : 2/7 = 3/2 x 7/2 = 21/4
Đúng rồi đó bn k cho mik đi
11/3 : 2 + 2/3 = 11/3 : 2/1 + 2/3 = 11/3 x 1/2 + 2/3 = 11/6 + 2/3 = 11/6 +4/6 = 15/6
3/4 x 3/3 : 2/7 = 3/4 x 1 : 2/7 = 3/4 x 7/2 = 21/12
k cho mik nha !