Cho: a-4b=5 ; a.b=\(-\dfrac{3}{2}\)
a) A=16ab2-4a2b
b) B= a2+16b2
c) D= a+4b
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\(1=\left(1.a+2.2b\right)^2\le\left(1^2+2^2\right)\left(a^2+4b^2\right)=5\left(a^2+4b^2\right)\)
\(\Rightarrow a^2+4b^2\ge\frac{1}{5}\)
Dấu "=" khi \(a=b=\frac{1}{5}\)
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Ta có:
\(a^2+4b^2=a^2+\frac{16b^2}{4}\ge\frac{\left(a+4b\right)^2}{5}=\frac{1}{5}\)
Dấu \("="\) xảy ra khi: \(\left\{{}\begin{matrix}a=\frac{1}{2}\\b=\frac{1}{8}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Áp dụng BĐT Cauchy-Schwarz ta có:
\(\left(1+4\right)\left(a^2+4b^2\right)\ge\left(a+4b\right)^2\)
\(\Rightarrow5\left(a^2+4b^2\right)\ge\left(a+4b\right)^2\)
\(\Rightarrow5\left(a^2+4b^2\right)\ge\left(a+4b\right)^2=1^2=1\)
\(\Rightarrow5\left(a^2+4b^2\right)\ge1\Rightarrow a^2+4b^2\ge\dfrac{1}{5}\)
Đẳng thức xảy ra khi \(a=b=\dfrac{1}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt \(T=a^2+4b^2\)(1)
Vì a+4b=1 => a=1-4b
Thế vào (1) ta được: \(T=\left(1-4b\right)^2+4b^2=20b^2-8b+1\)
<=> \(T=20\left(b^2-2\cdot\frac{1}{5}\cdot b+\frac{1}{25}\right)+\frac{1}{5}=20\left(b-\frac{1}{5}\right)^2+\frac{1}{5}\)
=> \(T\ge\frac{1}{5}\left(đpcm\right)\)
trả lời
anh ơi cái anyf dùng bất đẳng thức
(ax+by)^2<= (a^2+b^2)(x^2+y^2) cũng được nhỉ
cách này nhanh hơn đó ạ
hok tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt \(\dfrac{a}{b}=\dfrac{c}{d}=k\)
\(\Leftrightarrow\left\{{}\begin{matrix}a=bk\\c=dk\end{matrix}\right.\)
Ta có: \(\dfrac{4a+3c}{4b+3d}=\dfrac{4bk+3dk}{4b+3d}=k\)
\(\dfrac{4a-3c}{4b-3d}=\dfrac{4bk-3dk}{4b-3d}=k\)
Do đó: \(\dfrac{4a+3c}{4b+3d}=\dfrac{4a-3c}{4b-3d}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
tham khảo
4a + 5 < 4b+5
<=> 4a +5 - 5 < 4b+5 - 5
<=> 4a < 4b
<=> a < b
\(\cdot a-4b=5\Leftrightarrow\left(a-4b\right)^2=a^2-8ab+16b^2=25\Leftrightarrow a^2+16b^2=25+8\cdot\left(-\dfrac{3}{2}\right)=13\\ \cdot a-4b=5\Leftrightarrow4b-a=-5\)
\(a,A=ab\left(4b-a\right)=-\dfrac{3}{2}\cdot\left(-5\right)=\dfrac{15}{2}\)
\(b,B=a^2+16b^2=13\left(cm.trên\right)\)
\(c,D=a+4b\)
Ta có \(\left(a+4b\right)^2=a^2+8ab+16b^2=13+8\cdot\left(-\dfrac{3}{2}\right)=1\)
\(\Rightarrow D=a+4b=1\)