Biết rằng t/x=4/3 ; y/z=3/2; z/x=1/6. Tìm tỉ số t/y
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Lời giải:
$\frac{y}{z}.\frac{z}{x}=\frac{3}{2}.1$
$\Rightarrow \frac{y}{x}=\frac{3}{2}$
Suy ra:
$\frac{t}{y}=\frac{t}{x}.\frac{x}{y}=\frac{4}{3}.\frac{2}{3}=\frac{8}{9}$
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Biết rằng t/x =4/3, y/z =3/2 , z/x =1/6 , hãy tìm tỉ số t/y là đúng nhé
\(\frac{t}{x}=\frac{4}{3},\frac{y}{z}=\frac{3}{2},\frac{z}{y}=\frac{1}{6}(gt)\)
Mặt khác \(\frac{t}{y}=\frac{t}{x}\cdot\frac{x}{z}\cdot\frac{z}{y}=\frac{4}{3}\cdot\frac{6}{1}\cdot\frac{2}{3}=\frac{16}{3}\)
Vậy : ...
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\(\frac{t}{x}=\frac{4}{3}\Rightarrow\frac{x}{t}=\frac{3}{4}\)
Mà \(\frac{y}{z}=\frac{3}{2};\frac{z}{x}=\frac{1}{6}\)
\(\Rightarrow\frac{x}{t}.\frac{y}{z}.\frac{z}{x}=\frac{3}{4}.\frac{3}{2}.\frac{1}{6}\)
\(\Rightarrow\frac{y}{t}=\frac{9}{48}=\frac{3}{16}\)
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\(2+\left\{-3-\left[-4+\left(-5+\left|x\right|\right)\right]\right\}=3-\left[4-\left(-5+6\right)\right]\)
\(\Leftrightarrow2+\left\{-3-\left[-4+\left(-5+\left|x\right|\right)\right]\right\}=0\)
\(\Leftrightarrow-3-\left[-4+\left(-5+\left|x\right|\right)\right]=0-2=-2\)
\(\Leftrightarrow-4+\left(-5+\left|x\right|\right)=\left(-2\right)+\left(-3\right)=-5\)
\(\Leftrightarrow-5+\left|x\right|=\left(-5\right)-\left(-4\right)=-1\)
\(\Leftrightarrow\left|x\right|=\left(-1\right)-\left(-5\right)=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=4\end{matrix}\right.\)
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\(\dfrac{-5}{6}\)- x=\(\dfrac{7}{12}\)+\(\dfrac{-8}{12}\)=\(\dfrac{-15}{12}\)
\(\Rightarrow\)x=\(\dfrac{-5}{6}\)-\(\dfrac{-15}{12}\)=\(\dfrac{-10}{12}\)-\(\dfrac{-15}{12}\)=\(\dfrac{-25}{12}\)
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1, ta co \(\frac{x}{5}=\frac{y}{6}=\frac{x}{20}=\frac{y}{24}\)
\(\frac{y}{8}=\frac{z}{7}=\frac{y}{24}=\frac{z}{21}\)
=>\(\frac{x}{20}=\frac{y}{24}=\frac{z}{21}=\frac{x+y-z}{20+24-21}=\frac{69}{23}=3\)
=>\(x=3\cdot20=60\)
\(y=3\cdot24=72\)
\(z=3\cdot21=63\)
3. ta co \(\frac{x}{15}=\frac{y}{7}=\frac{z}{3}=\frac{t}{1}=\frac{x+y-z+t}{15-7+3-1}=\frac{10}{10}=1\)
=> \(x=1\cdot15=15\)
\(y=1\cdot7=7\)
\(z=1\cdot3=3\)
\(t=1\cdot1=1\)