Giúp tôi giải toán

Giải hay làm văn vậy bạn ? 

trông thấy mà sợ lunnnnnnnnnnnnnnnnnnnnnnn

Ngô Tùng Lâm giải nhiuuuuuuuuuuuuuuuuuuu wa trời

b. \(4x^2+4x-7=0\)

\(\Leftrightarrow\left(2x\right)^2+2.2x+1-8=0\)

\(\Leftrightarrow\left(2x+1\right)^2-8=0\)

\(\Leftrightarrow\left(2x+1-\sqrt{8}\right)\left(2x+1+\sqrt{8}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}2x+1-\sqrt{8}=0\\2x+1+\sqrt{8}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{\sqrt{8}-1}{2}\\x=\frac{-\sqrt{8}-1}{2}\end{cases}}\)

k mình nha bn <3 thanks nhìu hen

aを見つける= 175度はどれくらい尋ねるaを見つける= 175度はどれくらい尋ねる

A.  7 + 48 : x = 45 : 5 = 9 => 48 : x = 9 - 7 = 2 => x = 48 : 2 = 24.

cho cái j

1) 120 + ( 999 - 9x) : 6) = 20

                999 - 9x : 6    = 140

                  999- 9x        = 840

                           9x       = 999 - 840

                           x          = 17 dư 7

a) \(2^x\)\(-\)\(64\)\(=\)\(2^6\)

    \(2^x\)\(-\)\(2^6\)\(=\)\(2^6\)

           \(2^x\)          \(=\)\(2^6\)\(+\)\(2^6\)

           \(2^x\)          \(=\) \(64\)\(+\)\(64\)

            \(2^x\)         \(=\)        \(128\)

  \(\Rightarrow\) \(2^x\)          \(=\)         \(2^7\)

b) \(\left(7x-11\right)\)\(^3\)\(=\)\(2^5\)\(.\)\(5^2\)\(+\)\(200\)

    \(\left(7x-11\right)\)\(^3\)\(=\)\(32\)\(.\)\(25\)\(+\)\(200\)

    \(\left(7x-11\right)\)\(^3\)\(=\)           \(1000\)

    \(\left(7x-11\right)\)\(^3\)\(=\)            \(10^3\)

\(\Rightarrow\)\(7x-11\)\(=\)\(10\)

               \(7x\)       \(=\)\(10+11\)

               \(7x\)        \(=\)    \(21\)

                  \(x\)        \(=\) \(21\)\(:\)\(7\)

                 \(x\)         \(=\)      \(3\)

a) \(2^x-64=2^6\)

\(2^x=2^6+64\)

\(2^x=64+64\)

\(2^x=128\)

\(2^x=2^7\)

\(\Rightarrow x=7\)

vay \(x=7\)

b) \(\left(7x-11\right)^3=2^5.5^2+200\)

\(\left(7x-11\right)^3=800+200\)

\(\left(7x-11\right)^3=1000\)

\(\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

vay \(x=3\)

a, 2^x-64=2⁶

=> 2^x-64=64

=> 2^x=64-64

=> 2^x=0

=> x=0

b, (7x-11)³=2⁵.5²+200

=> (7x-11)³=32.25+200

=> (7x-11)³=1000

=> (7x-11)³=10³

=> 7x-11=10

=> 7x=10+11

=> 7x=21

=> x=21:7

=> x=3

(6.x-72):2-84=5628:28

(6.x-72):2-84=201

(6.x-72):2=201-84=117

6.x-72=117:2

6.x-72=58,5

6.x=58,5+72=130,5

x=130,5:6=21,75

\(\left(2x+1\right)^4-10^0=80\)

\(\left(2x+1\right)^4-1=80\)

\(\left(2x+1\right)^4=81\)

\(\left(2x+1\right)^4=3^4\)

\(\Rightarrow2x+1=3\)

\(\Rightarrow2x=2\)

\(\Rightarrow x=1\)

vay \(x=1\)

mk giup ban roi, gio ban giup lai mk di

nho k cho mk day

(​2.x + 1)⁴​ -10⁰​= 80

(​2.x + 1)⁴​ -1=80

(​2.x + 1)⁴​=80+1=81

2x^4+1=81

2x^4=81-1=80

x^4=80:4=20

=>

Ta có:

\(\left(2.x+1\right)^4-10^0=80\)

\(\Leftrightarrow\left(2.x+1\right)^4-1=80\)

\(\Leftrightarrow\left(2.x+1\right)^4-81=0\)

\(\Leftrightarrow\left[\left(2.x+1\right)^2\right]^2-9^2=0\)

\(\Leftrightarrow\left[\left(2.x+1\right)^2-9\right].\left[\left(2.x+1\right)^2+9\right]=0\)

\(\Leftrightarrow\left[\left(2.x+1\right)^2-3^2\right].\left[4x^2+4x+10\right]=0\)

\(\Leftrightarrow\left[\left(2.x-1-3\right).\left(2.x-1+3\right)\right].\left[4x^2+4x+10\right]=0\)

\(\Leftrightarrow\left[\left(2.x-4\right).\left(2.x+2\right)\right].\left[4x^2+4x+10\right]=0\)

\(\Leftrightarrow\left(2.x-4\right).\left(2.x+2\right).\left[4x^2+4x+10\right]=0\)

Tự làm tiếp nha có 2 nghiệm

a) x=2

b)x=2

c)x=2

a) \(2^x=16\)

\(2^x=2^4\)

\(\Rightarrow x=4\)

vay \(x=4\)

b) \(4^x=64\)

\(4^x=4^3\)

\(\Rightarrow x=3\)

vay \(x=3\)

c) \(15^x=225\)

\(15^x=15^2\)

\(\Rightarrow x=2\)

vay \(x=2\)

d) \(2^x-15=17\)

\(2^x=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

vay \(x=5\)

e) \(2^x-64=2^6\)

\(2^x=2^6+64\)

\(2^x=128\)

\(2^x=2^7\)

\(\Rightarrow x=7\)

vay \(x=7\)

f) \(\left(7x-11\right)^3=2^5.5^2+200\)

\(\left(7x-11\right)^3=800+200\)

\(\left(7x-11\right)^3=1000\)

\(\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

vay \(x=3\)

a, x=4

b, x=3

c, x=2

d, =2

4x:17=0

4x=0

x=0

Mình ghi rõ ràng rồi đó . Đầy đủ các bước luôn

4x : 17 = 0

4x        = 0 . 17

4x.       = 0

 x.        = 0 : 4

 x.        = 0

Để (2x-4)^7=(2x-4)^3 thì 2x - 4 = 0 hoặc 2x - 4 = 1

Th1:  2x - 4 = 0

         2x      = 0 + 4 = 4

           x      = 4 : 2

           x      = 2

TH2:    2x - 4 = 1

            2x      = 1 + 4 = 5

              x = 2,5

Vậy x =  2 hoặc x = 2,5

Bạn xem lại đề 

7^3 = 343

6^3 = 216

Vậy làm sao làm được bạn 

theo minh thi :[a]x+0

Ta có ví dụ :

Nếu x = 0 thì x . x = x sẽ bằng 0 x 0 = 0 ( sai )

Nếu x = 1 thì x . x = x sẽ bằng 1 x 1 = 1 ( đúng )

=> Chọn ý B

\(2x-3=x-\left(\frac{-1}{2}\right)\)

\(\Rightarrow2x-3=x+\frac{1}{2}\)

\(\Rightarrow2x=x+\frac{1}{2}+3\)

\(\Rightarrow2x-x=\frac{1}{2}+3\)

\(\Rightarrow x=\frac{7}{2}\)

ủa cái đó là x-x

2x-x+\(\frac{1}{2}\)=3

2x-x=3-\(\frac{1}{2}\)

2x-x=\(\frac{5}{2}\)

x-x=\(\frac{5}{2}\): 2

x-x=\(\frac{5}{4}\)

(1+2+3+4+....+19+20)-0=0

[(20-1):1+1]-0=0

20-X=0

      X=20-0(TÌM SỐ TRỪ)

       X=20

1 + 2 + 3 + 4 + ... + 19 + 20 - x = 0

\(\Rightarrow\)1 + 2 + 3 + 4 + ... + 19 + 20 = x

\(\Rightarrow\)(20 + 1) . 20 : 2 = x

\(\Rightarrow\)x = 210

x=210