Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{75}{100}=\frac{3}{4}=\frac{6}{8}< \frac{7}{8}\)
\(\frac{7}{8}< 1< \frac{3}{2}\)
\(\frac{60}{108}=\frac{5}{9}=\frac{15}{27}>\frac{15}{37}\)
\(\frac{15}{37}=\frac{30}{74}< \frac{31}{74}< \frac{31}{54}\)
\(\frac{0}{16}=\frac{0}{21}\)
Xét \(1-\frac{1965}{1967}=\frac{2}{1967}>\frac{2}{1975}=1-\frac{1973}{1975}\Rightarrow\frac{1965}{1967}< \frac{1973}{1975}\)
Đáp án :
a) 4/7 < 7/4
b) 13/14 > 13/15
c)11/12 > 9/10
Học tốt !!!!!!!!!!
a) \(\dfrac{12}{14}=\dfrac{1200}{1400}=\dfrac{1400-200}{1400}=1-\dfrac{200}{1400}\)
\(\dfrac{1212}{1414}=\dfrac{1414-200}{1414}=1-\dfrac{200}{1414}\)
vì \(\dfrac{200}{1414}< \dfrac{200}{1400}\)
Nên \(1-\dfrac{200}{1400}< 1-\dfrac{200}{1414}\)
Vậy \(\dfrac{12}{14}< \dfrac{1212}{1414}\)
Các bài sau tương tự
a. 6/7 = 6x9/7x9=54/63
7/9=7x7/9x7=49/63
do 54/73>49/63 => 6/7>7/9
b.8/11=8x9/11x9=72/99
15/9=15x11/9x11=165/99
do 72/99<165/99=>8/11<15/9
ta có: \(\frac{73}{75}>\frac{73}{79}>\frac{77}{79}\Rightarrow\frac{73}{75}>\frac{77}{79}\)
ta có: \(\frac{53}{100}< \frac{47}{100}\)
ta có: \(\frac{48}{47}>1;\frac{84}{85}< 1\Rightarrow\frac{48}{47}>\frac{84}{85}\)
A. 13/5 = 2 + 3/5 ; 15/7 = 2 + 1/7
3/5 > 1/7 => 13/5 > 15/7
B. 2012/1999 = 1 + 13/1999 ; 1999/1986 = 1 + 13/1986
13/1999 < 13/1986 => 2012/1999 < 1999/1986
C. 33/17 = 1 + 16/17
37/18 = 2 + 1/18
=> 33/17 < 37/18 => 17/33 > 18/37
D. 405/203 = 1 + 202/203
203/101 = 2 + 1/101
=> 405/203 < 203/101 => 203/405 > 101/203
a) Ta có: \(\dfrac{15}{7}>1\) (tử lớn hơn mẫu)
\(\dfrac{9}{14}< 1\) (tử nhỏ hơn mẫu)
Vậy: \(\dfrac{15}{7}>\dfrac{9}{14}\)
b) Ta có:
\(\dfrac{899}{900}=1-\dfrac{1}{900}\)
\(\dfrac{1235}{1236}=1-\dfrac{1}{1236}\)
Mà: \(\dfrac{1}{900}>\dfrac{1}{1236}\)
Vậy: \(\dfrac{1235}{1236}>\dfrac{899}{900}\)
c) Ta có:
\(\dfrac{77}{75}=1+\dfrac{2}{75}\)
\(\dfrac{37}{35}=1+\dfrac{2}{35}\)
Mà: \(\dfrac{2}{75}< \dfrac{2}{35}\)
Vậy: \(\dfrac{37}{35}>\dfrac{77}{75}\)
\(\left\{{}\begin{matrix}\dfrac{15}{7}=\dfrac{30}{14}\\\dfrac{9}{14}< \dfrac{30}{14}\end{matrix}\right.\Rightarrow\dfrac{15}{7}>\dfrac{9}{14}\)
\(\left\{{}\begin{matrix}\dfrac{899}{900}=\dfrac{899.1236}{900.1236}=\dfrac{\text{1111164}}{900.1236}\\\dfrac{1235}{1236}=\dfrac{1235.900}{900.1236}=\dfrac{\text{1111500}}{900.1236}>\dfrac{\text{1111164}}{900.1236}\end{matrix}\right.\Rightarrow\dfrac{1235}{1236}>\dfrac{899}{900}\)
\(\left\{{}\begin{matrix}\dfrac{77}{75}=\dfrac{539}{525}\\\dfrac{37}{35}=\dfrac{555}{525}>\dfrac{539}{525}\end{matrix}\right.\Rightarrow\dfrac{77}{73}< \dfrac{37}{35}\)