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1/2=1/1.2
1/6=1/2.3
1/12=1/3.4
1/20=1/4.5
1/30=1/5.6
1/42=1/6.7
ta có 1/1.2+1/2.3+1/3.4+1/4.5+1/5.6+1/6.7
= 1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7
=1/1-1/7
=6/7
D=1/2-1/32=15/32
E=1/1X2+1/2X3+1/3X4+1/4X5+1/5X6
E=1/1-1/6=5/6
K MÌNH NHA
1/2 +1/(2.3) +1/(3.4) + 1/(4.5) + 1/(5.6) + 1/(6.7)
=(2-1)/2 + (3-2)/(2.3) +(4-3)/(3.4) + (5-4)/(4.5) + (6-5)/(5.6) + (7-6)/(6.7)
=1-1/2 +1/2-1/3+....+1/6-1/7
=1-1/7
=6/7
đặt biểu thức trên là A
\(\Rightarrow A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{6.7}\)
\(=\frac{2-1}{1.2}+\frac{3-2}{2.3}+....+\frac{7-6}{6.7}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-....+\frac{1}{6}-\frac{1}{7}\)
\(=1-\frac{1}{7}=\frac{6}{7}\)
1/2 + 1/6 + 1/12 + 1/20 +1/30
= 30/60 + 10/60 + 5/60 + 3/60 + 2/60
= (30+10+5+3+2)/60
= 50/60 = 5/6
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}\)
\(=1-\frac{1}{2}+\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{6}\)
\(=1-\frac{1}{6}\)
\(=\frac{5}{6}\)
1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90
=1/(1.2)+1/(2.3)+1/(3.4)+1/(4.5)
+1/(5.6)+1/(6.7)+1/(7.8)
+1/(8.9)+1/(9.10)
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5.+1/5-1/6...
+1/9-1/10
=1-1/10
=9/10
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{9.10}\)
\(=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{9x10}\)
\(=\frac{2-1}{1x2}+\frac{3-2}{2x3}+\frac{4-3}{3x4}+...+\frac{10-9}{9x10}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{10}{10}-\frac{1}{10}\)
\(=\frac{9}{10}\)
Tham khảo nha !!!
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}\)=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)= \(1-\frac{1}{6}=\frac{5}{6}\)
\(\frac{1}{2}\)+ \(\frac{1}{6}\)+ \(\frac{1}{12}\)+ \(\frac{1}{20}\)+ \(\frac{1}{30}\)+ \(\frac{1}{42}\)
= \(\frac{6}{7}\)
\(\frac{1}{1\cdot2}\) +\(\frac{1}{2\cdot3}\) +\(\frac{1}{3\cdot4}\) +\(\frac{1}{4\cdot5}\) +\(\frac{1}{5\cdot6}\) +\(\frac{1}{6\cdot7}\) =1-\(\frac{1}{7}\) =\(\frac{6}{7}\)