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Answer:
Bài 1:
\(\left(135-35\right).\left(-37\right)+37.\left(-42-58\right)\)
\(=100.\left(-37\right)+37.\left(-100\right)\)
\(=\left(-3700\right)+\left(-3700\right)\)
\(=-7400\)
\(-65.\left(87-17\right)-87.\left(17-65\right)\)
\(=\left(-65\right).87-\left(-65\right).17-87.17+87.65\)
\(=-\left(-65\right).17-87.17\)
\(=17.\left(65-87\right)\)
\(=-374\)
\([3.\left(-2\right)-\left(-8\right)].\left(-7\right)-\left(-2\right).\left(-5\right)\)
\(=[\left(-6\right)+8].\left(-7\right)-\left(-2\right).\left(-5\right)\)
\(=2.\left(-7\right)-10\)
\(=-24\)
Bài 2:
\(\left(-55\right).\left(-25\right).\left(-8\right)\)
\(=\left(-55\right).[\left(-25\right).\left(-8\right)]\)
\(=\left(-55\right).200\)
\(=-11000\)
\(\left(-1\right).\left(-2\right).\left(-3\right).\left(-4\right).\left(-5\right).10\)
\(=[\left(-1\right).10].[\left(-2\right).\left(-5\right)].[\left(-3\right).\left(-4\right)]\)
\(=\left(-10\right).10.12\)
\(=-1200\)
a) ( 135 − 35 ) . ( − 37 ) + 37 ( − 41 − 59 ) = − 100.37 + 37 − 100 = 37 − 100 − 100 = 37 − 200 = − 7400.
b) − 65 ( 87 − 17 ) − 87 ( 17 − 65 ) = − 65.87 + 65.17 − 87.17 + 87.65 = 87.65 − 65.87 + 17 65 − 87 = 0 + 17. − 22 = − 374.
c) 3 ( − 2 ) − ( − 8 ) . ( − 7 ) − ( − 2 ) . ( − 5 ) = − 6 + 8 . − 7 + 2 = 2. − 7 + 2 = − 12
A) ( 26-6).(-4)+31.(-7-13)=20.(-4)+31.(-20)=20.[-4+(-31)]=20.(-35)=-700
B)( -18).(55-24)-28.(44-68)=-18.31-28.(-24)=-588+672=84
C) (135+35).(-37)+37.(-42-58)=170.(-37)+37.(-100)=37.[-170+(-100)]=37.(-270)=-9990
D) -65.(87-17)-87.(71-65)=-65.60-87.6=-3900-522=-4422
E) [ 3.( -2)-(-8) ] . (-7).(-2).(-5)=2.(-7).(-2).(-5)=-14.(-2).(-5)=28.(-2)=-56
H) ( -25)+8+12+25=(-25+25)+(8+12)=0+20=20
K) 40 + 15 + (-10) + (-15)=(-15+15)+(-10+40)=0+30=30
F) -13+(-750)+(-17)+ 750=[-13+(-17)]+(-750+750)=-30+0=-30
J) ( -7) + ( -20 ) +35 + (-8)=-27+35+(-8)=8+(-8)=0
a) Ta có: \(\left(-65\right)\cdot\left(87-17\right)-87\cdot\left(17-65\right)\)
\(=-65\cdot87+65\cdot17-87\cdot17+87\cdot65\)
\(=17\left(65-87\right)=17\cdot\left(-22\right)=-374\)
b) Ta có: \(\left(135-35\right)\cdot\left(-37\right)+37\cdot\left(-42-58\right)\)
\(=\left(-100\right)\cdot37+37\cdot\left(-100\right)\)
\(=37\left(-100-100\right)=37\cdot\left(-200\right)=-7400\)
1. Thực hiện phép tính bằng cách hợp lí :
a) (-46) + (-125) + 46 + 25 = [(-46)+46] + [(-125)+25]
= 0+(-100) = -100
b) 25.(-15) + 25.(-5) + (-20).75 = 25.[(-15)+(-5)] + (-20).75
= 25.(-20) + (-20).75 = (-20).(25+75) = (-20).100 = -2000
c) (-151)+(-37)+(-42)+(-63)+142 =(-151)+[(-37)+(-63)]+[(-42)+142]
= (-151) + [(-100) + 100] = -151
d)32+(-149)+(-311)+(-89)+(-51) = 32+[(-149)+(-51)] + [(-311)+(-89)]
= 32+[(-200)+(-400)] = 32+(-600) = -568
e)-65.(87-17)-87.(17-65) = (-65).87 - (-65).17 - 87.17 + 87.65
= (-65).87 + 65.17 - 87.17 + 87.65 = [(-65).87+87.65] + 65.(17-87)
= 65.(-70) = -4550
g) -43.(53-16) - 53.(16-43) = (-43).53 - (-43).16 - 53.16 + 53.43
= (-43).53 + 43.16 - 53.16 + 53.43 = [(-43).53+53.43] + 16.(43-53)
= 16.(-10) = -160
a) (135 - 35) . (-37) + 37 . (-42 - 58)
= 100 . 0 . (-100)
= 0
b) -65 . (87 - 17) - 87 . (17 - 65)
= -65 . 70 - 87 . (-48)
= -4550 - 135
= -4415