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1: =72/90+65/90=137/90
2: =24/56-77/56=-53/56
3: =-7/10+4/5=1/10
4: =15/100-4/100=11/100
5: =4/6-5/6=-1/6
6: =10/40-15/40-76/40=-81/40
7: =-9/10+7/18
=-81/90+35/90=-46/90=-23/45
8: =27/90-55/90=-28/90=-14/45
9: =36/60-50/60-35/60=-49/60
10: =-4/9+5/6-3/8
=-32/72+60/72-27/72
=1/72
![](https://rs.olm.vn/images/avt/0.png?1311)
1) âm năm phần 12
2) âm mười bảy phần 9
3) -1
Đây là đáp án còn làm bài từ làm nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{9^3.25^3}{18^2.125^2}=\frac{\left(9.25\right)^3}{\left(18.125\right)^2}=\frac{225^3}{2250^2}=\frac{225^3}{225^2.10^2}=\frac{225}{100}=\frac{9}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1)
g) \(24+5x\text{=}7^5:7^3\)
\(24+5x\text{=}7^{5-3}\)
\(24+5x\text{=}7^2\text{=}49\)
\(5x\text{=}49-24\text{=}25\)
\(x\text{=}5\)
h) \(x:2^2\text{=}2^3\)
\(x\text{=}2^3.2^2\)
\(x\text{=}2^5\text{=}32\)
2)
a) \(2^{10}.8.2^3\text{=}2^{10}.2^3.2^3\text{=}2^{10+3+3}\text{=}2^{16}\)
\(b)3^5:27\text{=}3^5:3^3\text{=}3^{5-3}\text{=}3^2\)
\(c)5^2.125\text{=}5^2.5^3\text{=}5^{2+3}\text{=}5^5\)
\(d)6^6:36\text{=}6^6:6^2\text{=}6^{6-2}\text{=}6^4\)
1.
g) \(24+5x=7^5:7^3\left(=7^{5-3}\right)\) -> Trong ngoặc ko cần viết nha
\(24+5x=7^2=49\)
\(5x=49-24\)
\(5x=25\)
\(x=25:5\)
\(=>x=5\)
h) \(x:2^2=2^3\)
\(x=2^3.2^2\)
\(=>x=2^5\)
2.
a) \(2^{10}.8.2^3=2^{10}.\left(2^3\right)2^3=2^{10+3+3}=2^{16}\)
b) \(3^5:27=3^5:\left(3^3\right)=3^{5-3}=3^2\)
c) \(5^2.125=5^2.\left(5^3\right)=5^{2+3}=5^5\)
d) \(6^6:36=6^6:\left(6^2\right)=6^{6-2}=6^4\)
Công thức:
\(a^m.a^n=a^{m+n}\)
\(a^m:a^n=a^{m-n}\)
\(#Wendy.Dang\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`Answer:`
a. \(-\frac{17}{30}-\frac{11}{-15}+-\frac{7}{12}\)
\(=-\frac{17}{30}+\frac{11}{15}-\frac{7}{12}\)
\(=-\frac{17}{30}+\frac{22}{30}-\frac{7}{12}\)
\(=\frac{1}{6}-\frac{7}{12}\)
\(=-\frac{5}{12}\)
b. \(-\frac{5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)
\(=-\frac{5}{9}+\frac{5}{9}:\left(-\frac{5}{12}\right)\)
\(=\frac{5}{9}.\left(-1\right)+\frac{5}{9}.\left(-\frac{12}{5}\right)\)
\(=\frac{5}{9}.\left(-1-\frac{12}{5}\right)\)
\(=\frac{5}{9}.\frac{-17}{5}\)
\(=-\frac{17}{9}\)
c. \(-\frac{7}{25}.\frac{11}{13}+-\frac{7}{25}-\frac{2}{13}-\frac{18}{25}\)
\(=\frac{77}{325}-\left(\frac{7}{25}+\frac{18}{25}\right)-\frac{2}{13}\)
\(=\frac{77}{325}-1-\frac{2}{13}\)
\(=-\frac{452}{325}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1.\) \(\dfrac{7}{36}-\dfrac{8}{-9}+\dfrac{-2}{3}=\dfrac{7}{36}+\dfrac{8}{9}-\dfrac{2}{3}=\dfrac{7+32-24}{36}=\dfrac{5}{12}.\)
\(2.\) \(\dfrac{-1}{2}+\dfrac{3}{7}-\dfrac{1}{9}+\dfrac{-7}{18}+\dfrac{4}{7}=\dfrac{-9-2-7}{18}+\dfrac{4+3}{7}=\dfrac{-18}{18}+\dfrac{7}{7}=-1+1=0.\)
\(3.\) \(-\dfrac{10}{3}+\dfrac{13}{10}-\dfrac{1}{6}+\dfrac{1}{10}=\dfrac{13+1}{10}+\dfrac{-20-1}{6}=\dfrac{14}{10}+\dfrac{-21}{6}=\dfrac{7}{5}-\dfrac{7}{2}=-\dfrac{21}{10}.\)
\(4.\) \(\dfrac{10}{17}-\dfrac{5}{13}-\left(-\dfrac{7}{17}\right)-\dfrac{8}{13}+\dfrac{11}{25}=\dfrac{10+7}{17}+\dfrac{-5-8}{13}+\dfrac{11}{25}=\dfrac{17}{17}-\dfrac{13}{13}+\dfrac{11}{25}=\dfrac{11}{25}.\)
ủng hộ lên 0 điểm nha
\(\frac{9^3.25^3}{18^2.125^2}=\frac{9^3.5^6}{9^2.2^2.5^6}=\frac{9}{2^2}=\frac{9}{4}\)