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a)425-84-16=425-(84+16)=425-100=325.
b)821-73-27-21=(821-21)-(73+27)=800-100=700.
c)475-(75-36)=(475-75)+36=400+36=436.
d)573-(73-24)=(573-73)+24=500+24=524.
k nha có j kb vs mk
425-84-16=425-(84+16) 821-73-27-21=(821-21)-(73+27) 478-(75-36)=478-75+36 573-(73-24)=573-73+24
=425-100 =800-100 =403+36 =500+24
=325 =700 =439 =524
a) \(475-\left(75-36\right)\)
\(=475-75+36\)
\(=\left(475-75\right)+36\)
\(=400+36\)
\(=436\)
b)\(573-\left(73-24\right)\)
\(=573-73+24\)
\(=\left(573-73\right)+24\)
\(=500+24\)
\(=524\)
Like nha, thks
a)475-(75-36)
=475-75+36
=(475-75)+36
=400+36
=436
b)573-(73-24)
=573-73+24
=(573-73)+24
=500+24
=524
a 475 - ( 75 + 36 ) = 475 - 75 - 36
= 400 - 36
= 364
b 821 - 73 - 27 - 21
= ( 821 - 21 ) - ( 73 + 27 )
= 800 - 100
= 700
a ) 475 - ( 75 + 36 )
= 475 - ( 75 + 35 ) - 1
= ( 475 - 1 ) - 100
= 474 - 100 = 374
b ) 821 - 73 - 27 - 21
= ( 821 - 21 ) - ( 73 + 27 )
= 800 - 100
= 700
c ) \(\frac{37}{25}\div\frac{5}{4}\div\frac{74}{25}\)
\(=\frac{37\cdot2\cdot2\cdot25}{25\cdot5\cdot37\cdot2}\)
\(=\frac{2}{5}\)
1,
Ta có:
\(\dfrac{73}{75}=1-\dfrac{2}{75}\)
\(\dfrac{77}{79}=1-\dfrac{2}{79}\)
So sánh phân số \(\dfrac{2}{75}\) và \(\dfrac{2}{79}\)
Vì \(75< 79\) nên \(\dfrac{1}{75}>\dfrac{1}{79}\)
Vậy \(1-\dfrac{2}{75}< 1-\dfrac{2}{79}\)
Hay \(\dfrac{73}{75}< \dfrac{77}{79}\)
2,
Vì \(\dfrac{53}{100}>\dfrac{47}{100}>\dfrac{47}{106}\) nên \(\dfrac{53}{100}>\dfrac{47}{106}\)
3,
Ta có:
\(\dfrac{81}{79}=1+\dfrac{2}{79}\)
\(\dfrac{65}{63}=1+\dfrac{2}{63}\)
So sánh phân số \(\dfrac{2}{79}\) và \(\dfrac{2}{63}\)
Vì \(79>63\) nên \(\dfrac{81}{79}< \dfrac{65}{63}\)
Hay \(\Rightarrow1+\dfrac{2}{79}< 1+\dfrac{2}{63}\)
Vậy \(\dfrac{81}{79}< \dfrac{65}{63}\)
4,
\(\dfrac{48}{47}>1>\dfrac{84}{85}\)
Vậy \(\dfrac{48}{47}>\dfrac{84}{85}\)
ta có: \(\frac{73}{75}>\frac{73}{79}>\frac{77}{79}\Rightarrow\frac{73}{75}>\frac{77}{79}\)
ta có: \(\frac{53}{100}< \frac{47}{100}\)
ta có: \(\frac{48}{47}>1;\frac{84}{85}< 1\Rightarrow\frac{48}{47}>\frac{84}{85}\)
