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tham thảo nhé
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tham thảo nhé
\(2x-49=5.32\\ \Leftrightarrow2x-49=160\\ \Leftrightarrow2x=209\\ \Leftrightarrow x=\dfrac{209}{2}\)
\(200-\left(2x+6\right)=43\\ \Leftrightarrow2x+6=157\\ \Leftrightarrow2x=151\\ \Leftrightarrow x=\dfrac{151}{2}\)
\(135-5\left(x+4\right)=35\\ \Leftrightarrow5\left(x+4\right)=100\\ \Leftrightarrow x+4=20\\ \Leftrightarrow x=16\)
2x-1 | -1 | -35 | 1 | 35 | 5 | -5 |
2y+1 | 35 | 1 | -35 | -1 | -7 | 7 |
x | 0 | -17 | 1 | 18 | 3 | -2 |
y | -1 | 0 | -18 | -1 | -4 | 3 |
2x-1 | 7 | -7 | ||||
2y+1 | -5 | 5 | ||||
x | 4 | -3 | ||||
y | -3 | 2 |
a, Vì \(\left|x-1\right|\ge0\)\(\forall x\inℤ\); \(\left|y+2\right|\)\(\forall y\inℤ\)
\(\Rightarrow\left|x-1\right|+\left|y+2\right|\ge0\)\(\forall x,y\inℤ\)
Dấu " = " xảy ra <=> \(\hept{\begin{cases}x-1=0\\y+2=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=1\\y=-2\end{cases}}\)
Vậy...
b, Vì \(\left|x+35-40\right|=\left|x-5\right|\ge0\)\(\forall x\inℤ\)
\(\left|y+10-x\right|\ge0\)\(\forall x,y\inℤ\)
\(\Rightarrow\left|x-5\right|+\left|y+10-x\right|\ge0\)\(\forall x,y\inℤ\)
Dấu " = " xảy ra <=> \(\hept{\begin{cases}x-5=0\\y+10-x=0\end{cases}}\Rightarrow\hept{\begin{cases}x=5\\y-x=-10\end{cases}}\Rightarrow\hept{\begin{cases}x=5\\y-5=-10\end{cases}}\Rightarrow\hept{\begin{cases}x=5\\y=-5\end{cases}}\)
Vậy...
\(48⋮x\Rightarrow48\cdot3⋮x\Rightarrow144⋮x\)
\(80⋮x\Rightarrow80\cdot2⋮x\Rightarrow160⋮x\)\(\Rightarrow160-144⋮x\Rightarrow16⋮x\)
\(\Rightarrow x\in U\left(16\right)=\left\{1;2;4;8;16\right\}\)
Ma 6<x<18
\(\Rightarrow x=\left\{8;16\right\}\)
24+3(5-x)=24
=>3(5-x)=24-24
=>3(5-x)=0
=>5-x=0:3
=>5-x=0
=>x=5-0
=>x=5
24+3(5-x)=24
=>3(5-x)=24-24
=>3(5-x)=0
=>5-x=0:3
=>5-x=0
=>x=5-0
=>x=5
\(x+2x+3x+4x+35=-65\Rightarrow (1+2+3+4)x=-65-35\Rightarrow 10x = -100 \Rightarrow x=-10\)