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TM
0
SM
0
NT
0
18 tháng 6 2020
a, \(\left(2x-1\right)^3=8\)
\(\Leftrightarrow\left(2x-1\right)^3=2^3\)
\(\Leftrightarrow2x-1=2\Leftrightarrow2x=3\Leftrightarrow x=\frac{3}{2}\)
b, \(\left(x-1\right)^x+2=\left(x-1\right)^x+4\)
\(\Leftrightarrow\left(x-1\right)^x+2-\left(x-1\right)^x-4=0\)
\(\Leftrightarrow-2\ne0\)=> vô nghiệm
c, \(3^x-1+5.3^{3x}-1=162\)
Đề sai.
SV
8
SS
10 tháng 2 2018
a. -3
b. -71
c. -40
d. 358
e. ?i
f. 10
mình chỉ cho đáp án được thôi vì mình đang gấp nên ko thể trình bày được, câu e mình ko hiểu bạn ghi gì hết. bạn gửi lại câu e đi.
10 tháng 2 2018
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17 tháng 2 2016
3^x- 1 +5*3^x-1=162
=>3x-1.(1+5)=162
=> x-1=3
=> x=3+1
=> x=4
Vậy x=4
22 tháng 9 2016
\(3^{x-1}+5.3^{x-1}=162\)
\(3^{x-1}.1+5.3^{x-1}=162\)
\(3^{x-1}.\left(1+5\right)=162\)
\(3^{x-1}.6=162\)
\(3^{x-1}=162:6\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(x=3+1\)
\(x=4\)
Vậy \(x=4\)
HY
22 tháng 9 2016
Ý bạn là \(\left(3^x-1+5\right)\left(3^x-1\right)\)
Hay \(\left(3^{x-1}+5\right)\left(3^{x-1}\right)\)
AH
Akai Haruma
Giáo viên
18 tháng 1
Lời giải:
$3^{-1}.3^x+5.3^{x-1}=162$
$3^{x-1}+5.3^{x-1}=162$
$3^{x-1}(1+5)=162$
$3^{x-1}.6=162$
$3^{x-1}=27=3^3$
$\Rightarrow x-1=3$
$\Rightarrow x=4$
9 tháng 8 2016
3x-1+5.3x-1=162
<=>3x-1.(1+5)=162
=>3x-1.6=162
=>3x-1=162:6
=>3x-1=27
=>3x-1=33
=>x-1=3
=>x=3+1
=>x=4
Chúc bạn học giỏi nha!!!
K cho mik với nhé Nguyễn Trần Thanh Vy
9 tháng 8 2016
3X-1 + 5 * 3X-1 = 162
3X-1 * (5+1) = 162
3X-1 * 6 = 162
3X-1 = 27
=> 3X-1 = 33
=>X-1=3
=>X=4