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\(F=\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{4}\right)^9\div\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\)
\(F=\frac{\left(\frac{2.5}{5}\right)^7+\left(\frac{9.16}{4.3}\right)^3}{2^7.5^2+2^9}=\frac{2^7+12^3}{2^7.5^2+2^9}=\frac{2^7+2^6.3^3}{2^7.5^2+2^9}=\frac{2^6.\left(2+3^3\right)}{2^7.\left(5^2+2^2\right)}=\frac{2^6.29}{2^7.29}\)
\(F=\frac{1}{2}\)
\(A=\frac{7.5^3.4^2}{5^7.25}=\frac{7.5^3.2^4}{5^7.5^2}=\frac{7.5^3.2^4}{5^9}=\frac{7.16}{5^6}=\frac{112}{15625}\)
\(A=\)\(\frac{6}{7}+\frac{1}{7}\times\frac{2}{7}+\frac{1}{7}\times\frac{5}{7}=\frac{6}{7}+\frac{1}{7}\left(\frac{2}{7}+\frac{5}{7}\right)\)
\(=\frac{6}{7}+\frac{1}{7}\times1\)
\(=\frac{6}{7}+\frac{1}{7}\)
\(=1\)
Cách 1: \(B=\frac{4}{9}\times\frac{13}{3}-\frac{4}{3}\times\frac{40}{9}\)
\(=\frac{52}{27}-\frac{160}{27}\)
\(=-4\)
K cho mk nhé thks bn nhiều
~CHÚC BẠN HỌC TỐT~
\(\dfrac{\left(\dfrac{2}{7}\right)^7.7^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\)
\(=\dfrac{\dfrac{2^7}{7^7}.7^7+\left(\dfrac{9}{4}:\dfrac{3}{16}\right)^3}{2^7.5^2+2.256}\)
\(=\dfrac{2^7+\left(\dfrac{9}{4}.\dfrac{16}{3}\right)^3}{2^7.5^2+2.2^8}=\dfrac{2^7+\left(12\right)^3}{2^7.5^2+2.2^8}\)
\(=\dfrac{2^7+\left(2^2.3\right)^3}{2^7.5^2+2^9}=\dfrac{2^7+2^6.3^3}{2^7.\left(5^2+2^2\right)}\)
\(=\dfrac{2^6\left(2+27\right)}{2^7.\left(25+4\right)}=\dfrac{29}{2.29}=\dfrac{1}{2}\)