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b, 1/1*6 + 1/6*11 + 1/11*16 ............ +1/491*496 + 1/496*501
=1/6(1-1/6+1/6-1/11+...+1/491-1/496)
=1/6(1-1/496)
=1/6.495/496
=495/2976
\(S=\frac{1}{1\cdot6}+\frac{1}{6\cdot11}+\frac{1}{11\cdot16}+...+\frac{1}{496\cdot501}\)
\(S=\frac{1}{5}\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{496}-\frac{1}{501}\right)\)
\(S=\frac{1}{5}\left(1-\frac{1}{501}\right)\)
\(S=\frac{1}{5}\cdot\frac{500}{501}\)
\(S=\frac{100}{501}\)
14/15 + 3/11 + 1/15 + 3/11 + 10/12
= ( 3/11 + 3/11) + (14/15 + 1/15) + 5/6
= 6/11 + 1 + 5/6
= 6/11 + 5/6 +1
= 91/66 +1
=
Đ/S:
mình trình bày hơi xấu, xin lỗi nha
bạn tự tính 91/66 + 1 nha
\(a.32,5-3\cdot0,87=32,5-2,61=29,89\)
\(8,5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8,5\cdot\left(\dfrac{3}{2}+\dfrac{4}{4}\right):5\\ =8,5\cdot\left(\dfrac{6}{4}+\dfrac{4}{4}\right):5\\ =8,5\cdot\dfrac{10}{4}:5\\ =\dfrac{85}{4}:5\\ =\dfrac{17}{4}\)
\(b.30,96-6,45+14,4:3=30,96-6,45+4,8\\ =29,31\)
\(\dfrac{2}{5}\cdot\left(\dfrac{4}{5}-\dfrac{1}{2}\right)=\dfrac{2}{5}\cdot\left(\dfrac{8}{10}-\dfrac{5}{10}\right)\\ =\dfrac{2}{5}\cdot\dfrac{3}{10}=\dfrac{3}{25}\)
bài 2
\(a.2,5\cdot12,5\cdot8\cdot0,4=\left(2,5\cdot0,4\right)\left(12,5\cdot8\right)\\ =1\cdot100=100\)
b,\(\dfrac{12}{15}\cdot\dfrac{5}{6}\cdot\dfrac{3}{20}\cdot\dfrac{32}{5}=\dfrac{12\cdot5\cdot3\cdot32}{15\cdot6\cdot20\cdot5}\\ =\dfrac{3\cdot4\cdot5\cdot3\cdot4\cdot8}{3\cdot5\cdot2\cdot3\cdot5\cdot4\cdot5}=\dfrac{16}{25}\)
Bài 1:
a) \(32.5-3\cdot0.87=32.5-2.61=29.89\)
\(8.5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8.5\cdot\dfrac{5}{2}:5=\dfrac{17}{2}\cdot\dfrac{5}{2}:5=\dfrac{85}{4}\cdot\dfrac{1}{5}=\dfrac{17}{4}\)
\(=\frac{3}{4}+\frac{1}{2}+\frac{1}{4}+\frac{1}{2}=\frac{4}{4}+\frac{2}{2}=1+1=2\)
Ta có : 1/10+2/20+3/30+4/40+5/50+6/60+7/70+8/80+9/90
= 1/10+1/10+1/10+1/10+1/10+1/10+1/10+1/10+1/10
= 1/10 . 9
= 9/10
Vậy.......
Tk và kb với mik nha !!!
,r5 ơi mẹ ghi zậy ai hiểu chết liền
Nghĩa là dzậy nè:1/1x6 + 1/6x11 + 1/11x16 + ..... +1/491x496 + 1/496x501