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a)1001^2=(1000+1)^2=1000^2+2000+1^2=1000000+2001=1002001
b)=(30-0.1)*(30+0.1)=30^2-1^2=900-1=899
c)=(200-1)^2=200^2-400+1^2=40000-401=39599
d)=(84-16)*(84+16)=68*100=6800
e)=(313-312)*(313+312)=1*625=625
f)=(50-3)*(50+3)=50^2-3^2=550-9=541
Chúc bạn học tốt!
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a) \(1001^2=\left(1000+1\right)^2=1000^2+2.1000.1+1^2=1002001\)
b) \(29,9\times30,1=\left(30-0,1\right).\left(30+0,1\right)=30^2-\left(0,1\right)^2=899,99\)
c) \(\left(31,8\right)^2-2.31,8.21,8+\left(21,8\right)^2=\left(31,8-21,8\right)^2=10^2=100\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 10012 = 1002001
b) 29,9 . 30,1 = 899,99
c) (31,8 )2 - 2 . 31,8 . 21,8 + (21,8 )2 = 100
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`a, 126^2 - 152 . 126 + 5776.`
`= 126^2 - 2 . 76 . 126 + 76^2`
`= (126+76)^2 = 202^2 = 40804`
`b, 3^8 . 5^8 - (15^4-1)(15^4+1)`
`= 15^8 - 15^8 + 1`
`= 1`
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B1:
a) \(1001^2=\left(1000+1\right)^2\)
\(=1000^2+2.1000+1=1000000+2000+1\)
= \(1002001\)
b) \(29,9.30,1\)
= \(\left(30-0,1\right)\left(30+0,1\right)\)
= \(30^2-0,1^2=900-0,01=899,99\)
c) \(31,8^2-2.31,8.21,8+21,8^2\)
= \(\left(31,8-21,8\right)^2=10^2=100\)
B2:
a) \(x^3+8y^3=\left(x+2y\right)\left(x^2-2xy+4y^2\right)\)
b) \(a^6-b^3=\left(a^2\right)^3-b^3\)
= \(\left(a^2-b\right)\left(a^4+a^2b+b^2\right)\)
c) \(8y^3-125=\left(2y\right)^3-5^3\)
= \(\left(2y-5\right)\left(4y^2+10y+25\right)\)
d) \(8z^3+27=\left(2z\right)^3+3^3\)
= \(\left(2z+3\right)\left(4z^2-6z+9\right)\)
B3:
a) A = \(x^2-20x+101\)
= \(x^2-20x+100+1\)
= \(\left(x-10\right)^2+1\ge1\) với mọi x
MinA = 1 khi và chỉ khi x = 10
b) B = \(4a^2+4a+2\)
= \(4a^2+4a+1+1\)
= \(\left(2a+1\right)^2+1\ge1\) với mọi x
MinB = 1 khi và chỉ khi a = \(-\dfrac{1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`a)1001^2`
`=(1000+1)^2=1000000+2000+1`
`=1002001`
`b)29,9.30,1`
`=(30-0,1)(30+0,1)`
`=30^2-0,1^2`
`=900-0,01=899,99`
`c)199^2=(200-1)^2`
`=40000-400+1`
`=39601`
`d)84^2-16^2`
`=(84-16)(84+16)`
`=100.68`
`=6800`
`e)313^2-312^2`
`=(313-312)(313+312)`
`=625`
`f)47.53`
`=(50-3)(50+3)`
`=2500-9=2491`
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
\(A=x^2+6x+9+x^2-10x+25\)
\(=2x^2+4x+34\)
\(=2\left(x^2+2x+17\right)\)
\(=2\left(x+1\right)^2+32>=32\forall x\)
Dấu '=' xảy ra khi x=-1
1) \(1001^2=\left(1000+1\right)^2=1000^2-1^2=1000000-1=999999\)
2) \(29,9.30,1=\left(30-0,1\right).\left(30+0,1\right)=30^2-0,1^2=900-0,01=899,99\)