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1. Tính tổng:
a) (-37) + 14 + 26 + 37 = 40
b) (-24) + 6 + 10 + 24 = 16
c) 15 + 23 + (-25) + (-23) = -10
d) 60 + 33 + (-50) + (-33) = 10
e) (-16) + (-209) + (-14) + 209 = -30
f) -32 + {-54 : [(-2)8 + 7] . (-2)2} = -32 + {-54 : [(-256) + 7] . 4} = -32 + {-54 : (-249) . 4} = -32 + {-54 : (-996)} = -32 + 0 = -32
2. Thực hiện phép tính:
a) (36 + 79) + (145 - 79 - 36) = 115 + 30 = 145
b) 10 - [12 - (-9 - 1)] = 10 - [12 - (-10)] = 10 - [12 + 10] = 10 - 22 = -12
c) (38 - 29 + 43) - (43 + 38) = 52 - 81 = -29
d) 271 - [(-43) + 271 - (-17)] = 271 - [-43 + 271 + 17] = 271 - [245] = 26
3. Tính hợp lý:
a) 31 . (-18) + 31 . (-81) - 31 = -558 + (-2511) - 31 = -3100
b) (-12) . 47 + (-12) . 52 + (-12) = -564 + (-624) + (-12) = -1200
c) 13 . (23 + 22) - 3 . (17 + 28) = 13 . 45 - 3 . 45 = 585 - 135 = 450
d) -48 + 48 . (-78) + 48 . (-21) = -48 + (-3744) + (-1008) = -4800
1. Tính tổng:
a) (-37) + 14 + 26 + 37 = 40
b) (-24) + 6 + 10 + 24 = 16
c) 15 + 23 + (-25) + (-23) = -10
d) 60 + 33 + (-50) + (-33) = 10
e) (-16) + (-209) + (-14) + 209 = -30
f) -32 + {-54 : [(-2)8 + 7] . (-2)2} = -32 + {-54 : [(-256) + 7] . 4} = -32 + {-54 : (-249) . 4} = -32 + {-54 : (-996)} = -32 + 0 = -32
2. Thực hiện phép tính:
a) (36 + 79) + (145 - 79 - 36) = 115 + 30 = 145
b) 10 - [12 - (-9 - 1)] = 10 - [12 - (-10)] = 10 - [12 + 10] = 10 - 22 = -12
c) (38 - 29 + 43) - (43 + 38) = 52 - 81 = -29
d) 271 - [(-43) + 271 - (-17)] = 271 - [-43 + 271 + 17] = 271 - [245] = 26
3. Tính hợp lý:
a) 31 . (-18) + 31 . (-81) - 31 = -558 + (-2511) - 31 = -3100
b) (-12) . 47 + (-12) . 52 + (-12) = -564 + (-624) + (-12) = -1200
c) 13 . (23 + 22) - 3 . (17 + 28) = 13 . 45 - 3 . 45 = 585 - 135 = 450
d) -48 + 48 . (-78) + 48 . (-21) = -48 + (-3744) + (-1008) = -4800
\(125-\left(-75\right)+32-\left(48+32\right)\)
\(=125-\left(-75\right)+32-80\)
\(=125+75+32-80\)
\(=200+32-80\)
\(=232-80\)
\(=152\)
\(-63+415-37-115\)
\(=352-57-115\)
\(=315-115\)
\(=200\)
\(13.\left(-2\right)^2+37.4+4.\left(-150\right)\)
\(=13.2^2+37.4+4.-150\)
\(=13.4+37.4+4.-150\)
\(=4.\left(13+37+-150\right)\)
\(=4.-100\)
\(=-400\)
\(-15.x+4=79\)
\(\Leftrightarrow-15.x=79-4\)
\(\Leftrightarrow-15.x=75\)
\(\Leftrightarrow x=75:-15\)
\(\Leftrightarrow x=-5\)
Vậy \(x=-5\)
\(15-\left(2+x\right)=23\)
\(\Leftrightarrow2+x=15-23\)
\(\Leftrightarrow2+x=-8\)
\(\Leftrightarrow x=-8-2\)
\(\Leftrightarrow x=-10\)
Vậy \(x=-10\)
\(\left(x+2\right)\left(x^2-1\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x^2-1^2\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x+1\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-1\right)=0\)
\(\Leftrightarrow x=\pm1\)
Vậy \(x\in\left\{\pm1\right\}\)
\(56:\left|x-4\right|=7\)
\(\Leftrightarrow\left|x-4\right|=56:7\)
\(\Leftrightarrow\left|x-4\right|=8\)
\(\Leftrightarrow\orbr{\begin{cases}x-4=8\\x-4=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8+4\\x=-8+4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=12\\x=-4\end{cases}}}\)
Vậy \(x\in\left\{12;-4\right\}\)
a) \(3.5^2+15.2^2-26\div2\)
= 3.25 + 15.4 - 13
= 75 + 60 - 13
= 135 - 13
= 122
b) \(5^3.2-100\div4+2^3.5\)
= 125.2 - 25 + 8.5
= 250 - 25 + 40
= 225 + 40
= 265
c)\(6^2\div9+50.2-3^3.33\)
= 36 : 9 + 100 - 9.33
= 4 + 100 - 297
= 104 - 297
= -193
d)\(3^2.5+2^3.10-81\div3\)
= 9.5 + 8.10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
e) \(5^{13}\div5^{10}-25.2^2\)
= 53 - 25.4
= 125 - 100
= 25
f) \(20\div2^2+5^9\div5^8\)
= 20 : 4 + 5
= 5 + 5
= 10
#)Giải :
Bài 1 :
\(A=\frac{15}{6.16}+\frac{15}{16.26}+\frac{15}{26.36}\)
\(A=3\left(\frac{5}{6.16}+\frac{5}{16.26}+\frac{5}{26.36}\right)\)
\(A=3\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)\)
\(A=3\left(\frac{1}{6}-\frac{1}{36}\right)\)
\(A=3.\frac{5}{36}\)
\(A=\frac{15}{36}\)
\(B=\frac{33}{6.16}-\frac{63}{16.26}+\frac{93}{26.36}\)
\(B=\frac{3.11}{6.16}-\frac{3.21}{16.26}+\frac{3.31}{26.36}\)
\(B=\frac{1}{2.16}.11+\frac{1}{2.16}.\frac{3.21}{13}+\frac{3.31}{26.36}\)
\(B=\frac{1}{32}.\frac{143-63}{13}+\frac{3.31}{26.12.3}\)
\(B=\frac{1}{32}.\frac{80}{13}+\frac{31}{36.12}\)
\(B=\frac{5}{26}+\frac{31}{26.12}=\frac{60+31}{26.12}=\frac{91}{26.12}=\frac{13.7}{13.2.12}=\frac{7}{24}\)
Bài 2 :
a)\(28.157-28.267+28.10\)
\(=28\left(157-267+10\right)\)
\(=28.-100\)
\(=-2800\)
b)\(\left(-5\right).4.\left(-2\right).23.\left(-25\right)\)
\(=\left[4.\left(-25\right)\right].\left[\left(-5\right).2\right].23\)
\(=\left(-100\right).\left(-10\right).23\)
\(=23000\)
2)
28 . 157 - 28 .267 + 28.10
=28.( 157 - 267 + 10 )
= 28 . -100
= -2800
3)
[(-2).(-5)]. 4 .-25.23
= 10 . -100 .23
=-23000
còn câu 1 mik suy nghĩ đã
a)-24+6+10+24
=(-24+24)+6+10=0+6+10=16
b)15+23+(-25)+(-23)
=[15+(-25)]+[23+(-23)]
=-10+0=-10
c)60+33+(-50)+(-33)
=[60+(-50)]+[33+(-33)]
=10+0=10
d)-16+(-209)+(-14)+209
=[-16+(-14)]+(-209+209)
=-30+0=-30
e)-12+(-13)+36+(-11)
=[-12+(-13)+(-11)]+36
=-36+36=0
f)-16+24+16-34
=(-16+16)+(24-34)
=0+(-10)=-10
g)25+37-48-25-37
=(25-25)+(37-37)-48
=0+0-48=-48
h)2575+37-2576-29
=(2575-2576)+(37-29)
=-1+8=7
a/ [(-24)+24]+6+10=0+6+10=16
b/ [15+(-25)]+[23+(-23)]=-10+0=-10
c/[60+(-50)]+[33+(-33)]=10+0=10
Mệt quá phú =_=" Sao nhìu quớ zậy? @_@ Lé mắt rùi
\(a.\left(-83\right)+302+83\\ =\left(-83+83\right)+302\\ =0+302\\ =302\\ b.14.\left(-7\right)-216:2\\ =-98-108\\ =-206\\ c.56.\left(-32\right)+\left(-68\right).56\\ =56.\left[\left(-32\right)+\left(-68\right)\right]\\ =57.\left(-100\right)\\ =-5700\\ d.2^3-6.\left[25-\left(33-28\right)^2\right]\\ =8-6\left[25-5^2\right]\\ =8-6\left[25-25\right]\\ =8-6.0\\ =8-0\\ =8\\ e.15.\left(-6\right)-420:\left(-4\right)\\ =-90-\left(-105\right)\\ =-90+105\\ =15\)
\(f.63.\left(-52\right)+\left(-48\right).63\\ =63.\left[\left(-52\right)+\left(-48\right)\right]\\ =63.\left(-100\right)\\ =-6300\)