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`#3107.101107`
`-3^2 + {-54 \div [-2^8 + 7] * (-2)^2}`
`= -9 + [-54 \div (-256 + 7) * 4]`
`= -9 + [-54 \div (-249) * 4]`
`= -9 + (18/83 * 4)`
`= -9 + 72/83`
`= -675/83`
______
`31 * (-18) + 31 * (-81) - 31`
`= 31 * (-18 - 81 - 1)`
`= 31 * (-100)`
`= -3100`
___
`(-12) * 47 + (-12) * 52 + (-12)`
`= (-12) * (47 + 52 + 1)`
`= (-12) * 100`
`= -1200`
___
`13 * (23 + 22) - 3 * (17 + 28)`
`= 13 * 45 - 3 * 45`
`= 45 * (13 - 3)`
`= 45 * 10`
`= 450`
____
`-48 + 48 * (-78) + 48 * (-21)`
`= 48 * (-1 - 78 - 21)`
`= 48 * (-100)`
`= -4800`
a,15+23+(-25)+(-23)=[ (-23)+23] +[(-25)+15] = 0+(-10)= -10
b,-23.63+23.21-58.23=23.(-63)+23.21-58.23=23.(-63+21-58)=23.(-100)=-2300
a)
15 + 23 + ( -25 ) + ( -23 )
= [ 15 + ( -25 ) ] + [ 23 + ( -23 ) ]
= -10 + 0
= -10.
b)
-23.63 + 23.21 - 58.23
= -23 . ( 63 - 21 + 58 )
= -23 . 100
= -2300.
-23.63+23.21-58.23
= 23. (-63) + 23.21 - 58.23
= 23.( -63 + 21-58)
= 23. (-100)
= -2300
-23.63+23.21-58.23=23.-63+23.21-58.23=23(-63+21-58)=23.-100=-2300
a, (18+29) +(158-18-29)
= 18+29+158-18-29
= (18-18) +(29-29)+ 158
= 158
b, (13-135+49)- (13+49)
= 13-135+49-13-49
= (13-13) +(49-49) -135
= 135
a, \(\left(18+29\right)+\left(158-18-29\right)\)
\(=18+29+158-18-29\)
\(=\left(18-18\right)+\left(29-29\right)+158\)
\(=158\)
b,
\(\left(13-135+49\right)-\left(13+49\right)\)
\(=13-135+49-13-49\)
= \(\left(13-13\right)+\left(49-49\right)-135\)
= \(-135\)
a, [ 13-17 ].[-10]+[-7]0
=-4.[-10]+1
=40+1
=41
b, 72.[28-49] + 28.[-49-72]
=72.[-21]+28.[-121]
=-1512+[-3388]
=-4900
c, -65.[87-17] - 87.[17-65]
=-65.70-87.[-48]
=4550-[-4276]
=8726
d, -23.63+23.21-58.23
=23.(-63)+23.21-58.23
=23.(-63+23-58)
=23.(-40-58)
=23.(-98)
=-2254
e, 25.134+25.[-34]
=25.[134+(-34)]
=25.100
=2500
a: \(A=\dfrac{7}{12}+\dfrac{5}{72}-\dfrac{11}{36}=\dfrac{42}{72}+\dfrac{5}{72}-\dfrac{22}{72}=\dfrac{25}{72}\)
b: \(B=\dfrac{8+5}{10}:\dfrac{-5}{13}=\dfrac{13}{10}\cdot\dfrac{13}{-5}=-\dfrac{169}{100}\)
c: \(C=\left(\dfrac{88}{132}-\dfrac{33}{132}+\dfrac{60}{132}\right):\left(\dfrac{55}{132}+\dfrac{132}{132}-\dfrac{84}{132}\right)\)
\(=\dfrac{88-33+60}{55+132-84}=\dfrac{115}{103}\)
\(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)
\(=\left(100+121+144\right):\left(169+196\right)\)
\(=365:365\)
\(=1\)
( - 12 ) . ( - 13 ) + 13 . ( - 29 )
= \(12.13+13.\left(-29\right)\)
=\(13.\left[12+\left(-29\right)\right]\)
=\(13.\left(-17\right)\)
=\(-221\)
a) (-12).(-13) + 13.(-29)
= 12.13 + 13.(-29)
= 13.(12 - 29)
= 13 . (-17)
=-221
b) -23.63 + 23.21 - 58.23
= -(23.63 - 23.21 + 58.23)
= -23.(63 - 21 + 58)
= -23.100
=-2300