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1: A=1-2002/2003=1/2003
=>Nghịch đảo là 2003
2: B=179/30-59/30+3/5=4+3/5=23/5
Nghịch đảo là 5/23
a) \(A=1-\dfrac{2002}{2003}\)
\(A=\dfrac{1}{2003}\)
b) \(B=\dfrac{179}{30}-\left(\dfrac{59}{30}-\dfrac{3}{5}\right)\)
\(B=\left(\dfrac{179}{30}-\dfrac{59}{30}\right)-\dfrac{3}{5}\)
\(B=\dfrac{120}{30}-\dfrac{3}{5}\)
\(B=4-\dfrac{3}{5}\)
\(B=\dfrac{17}{5}\)
c) \(C=\left(\dfrac{46}{5}-\dfrac{1}{11}\right).11\)
\(C=\dfrac{501}{55}.11\)
\(C=\dfrac{501}{5}\)
a) \(A=1-\dfrac{2002}{2003}=\dfrac{2003}{2003}-\dfrac{2002}{2003}=\dfrac{1}{2003}\)
b) \(B=\dfrac{179}{30}-\left(\dfrac{59}{30}-\dfrac{3}{5}\right)=\dfrac{179}{30}-\dfrac{59}{30}+\dfrac{3}{5}=4+\dfrac{3}{5}=\dfrac{23}{5}\)
c) \(C=\left(\dfrac{46}{5}-\dfrac{1}{11}\right)\cdot11=\dfrac{46}{5}\cdot11-\dfrac{1}{11}\cdot11=\dfrac{506}{5}-1=\dfrac{501}{5}\)
\(A=1-\frac{2015}{2016}=\frac{1}{2016}=>\frac{1}{A}=\frac{2016}{1}\)
\(B=\frac{179}{30}-\left(\frac{59}{30}-\frac{3}{5}\right)=\frac{179}{30}-\frac{59}{30}+\frac{3}{5}=40+\frac{3}{5}=\frac{203}{5}=>\frac{1}{B}=\frac{5}{203}\)
\(C=\left(\frac{46}{5}-\frac{1}{11}\right)=\frac{46.11}{5}-1=\frac{506}{5}-1=\frac{501}{5}=>\frac{1}{C}=\frac{5}{501}\)
(59-5^30)-(59+3^3-5^30)
=[(59-5^30)-(59-5^30)]+3^3
=0+9
=9
