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= A . ( \( {1 \over 3}\) - \( {1 \over 4}\) - \( {1 \over 12}\) ) = A . ( \( {1 \over 12}\) - \({1 \over 12}\) ) = A . 0 = 0
(-6,17 +3+5/9-2-36/97)*(1/3-1/4-1/12)=(-6,17+3+5/9-2-36/97)*(4/12-3/12-1/12)=(-6,17+3+5/9-2-36/97)*0=0
E=(-0,17+3+5/9-2-36/97).(1/12-1/12)=(-0,17+3+5/9-2-36/97).0=0
a=113/13-(24/7+53/13)=113/13-24/7-53/13=60/13-24/7=396/16
b=(64/9+37/11)-44/9=64/9+37/11-44/9=20/9+37/11=181/33
c=-5/7(2/11+9/11)+15/7=-5/7+15/7=10/7
d=0.7.22/3.20.0.375.5/28=0
e=(6,17+35/9-236/97)(1/3-0.25-1/12)=A.(1/3-1/4-1/12)=A.(1/12-1/12)=A.0=0
e=(6,17 + 3 5/9 - 2 36/97 ) . ( 1/3 - 0,25 - 1/12)=(6,17 + 3 5/9 - 2 36/97 ) .(1/3-1/12-0,25)
=(6,17 + 3 5/9 - 2 36/97 ) .(4/12-1/12-0,25)=(6,17 + 3 5/9 - 2 36/97 ) .(3/12-0,25)
=(6,17 + 3 5/9 - 2 36/97 ) .(1/4-0.25)=(6,17 + 3 5/9 - 2 36/97 ) .(0.25-0.25)
=(6,17 + 3 5/9 - 2 36/97 ) .0=0
Vậy E=0
\(\left(-6,17+3\frac{5}{9}-2\frac{36}{97}\right).\left(\frac{1}{3}-0,25-\frac{1}{12}\right)\)
\(=\left(-6,17+\frac{32}{9}-\frac{230}{97}\right).\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)\)
\(=\left(-6,17+\frac{32}{9}-\frac{230}{97}\right).\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)
\(=-4,985578465.0\)
\(=0\)
P/s: Hoq chắc :((
86,25 ban nha