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234 + 28 - ( -234 ) + ( -108 ) + 120=234+28+234-108+120
=234+(108+120)-28=234+(228-28)
=234+200=434
625 - ( 127 - 56 ) + ( 144 - 625 )=625-127+56+144-625
=127+(625-625)+(144+56)=127+0+200
=127+200=327
Cho mk xin lỗi bài mk sai nha bn
Lời giải:
$234+28-(-234)+(-108)+120=234+28+234-108+120$
$=234.2-(108-28)+120$
$=468-80+120=468+40=508$
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$625-(127-56)+(144-625)=625-127+56+144-625$
$=(625-625)+(144+56)-127$
$=0+200-127=73$
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\(a,234-\left(x-56\right)=789\)
\(\Leftrightarrow x-56=234-789\)
\(\Leftrightarrow x-56=-555\)
\(\Leftrightarrow x=\left(-555\right)+56=-499\)
Vậy x = -499
b) \(\frac{x+3}{-5}=\frac{x-15}{4}\)
\(\Leftrightarrow4\left(x+3\right)=-5\left(x-15\right)\)
\(\Leftrightarrow4x+12=-5x+75\)
\(\Leftrightarrow4x+12-\left(-5x\right)=75\)
\(\Leftrightarrow4x-\left(-5x\right)+12=75\)
\(\Leftrightarrow4x+5x=63\)
\(\Leftrightarrow9x=63\)
\(\Leftrightarrow x=7\)
Vậy x = 7
c) \(8\left(x-1\right)-7=2\left(x+2\right)+5\)
\(\Leftrightarrow8x-8-7=2x+4+5\)
\(\Leftrightarrow8x-8-7-2x+4=5\)
\(\Leftrightarrow8x-2x-8-7+4=5\)
\(\Leftrightarrow8x-2x=5-4+7+8\)
\(\Leftrightarrow4x=16\)
\(\Leftrightarrow x=4\)
Vậy x = 4
d) Đặt \(D=\frac{2x+3}{x-1}=\frac{2x-2+5}{x-1}=\frac{2\left(x-1\right)+5}{x-1}=2+\frac{5}{x-1}\)
=> \(5⋮x-1\)
=> \(x-1\inƯ\left(5\right)\)
=> \(x-1\in\left\{\pm1;\pm5\right\}\)
=> \(x\in\left\{2;0;6;-4\right\}\)
234+56.3=243+168=402
Cô Loan :D