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\(y:\dfrac{2}{3}=\dfrac{1}{3}+\dfrac{2}{3}\)
\(y:\dfrac{2}{3}=\dfrac{3}{3}=1\)
\(y=1\times\dfrac{2}{3}=\dfrac{2}{3}\)
Ta có: \(y:\dfrac{2}{3}=\dfrac{1}{3}+\dfrac{2}{3}\)
\(\Leftrightarrow y:\dfrac{2}{3}=1\)
\(\Leftrightarrow y=\dfrac{2}{3}\)
Vậy: \(y=\dfrac{2}{3}\)
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a) y = 5/14 : 6/7
y = 5/12
vậy y = 5/12
b) y = 4/9 x 2/3
y = 8/27
vậy t = 8/27
c) y = 1/2 - 3/10
y = 1/5
vậy y = 1/5
d) y = 5/6 - 1/3
y = 1/2
vậy y = 1/2
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\(\Leftrightarrow y\times\left(\dfrac{1}{7}+\dfrac{9}{21}+\dfrac{7}{3}\right)=\dfrac{5}{3}\)
\(\Leftrightarrow y\times\dfrac{61}{21}=\dfrac{5}{3}\)
\(\Leftrightarrow y=\dfrac{5}{3}:\dfrac{61}{21}=\dfrac{35}{61}\)
y x (1/7 +9/21 +7/3)= 5/3
y x 61/21 = 5/3
y = 5/3 : 61/21
y= 35/61
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12 - y = 1/3
y = 12 - 1/3
y = 35/3