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\(\dfrac{15}{19}\times\dfrac{38}{5}< x< \dfrac{67}{15}-\dfrac{56}{16}\\ \dfrac{5\times3\times19\times2}{19\times5}< x< \dfrac{67\times16-56\times15}{15\times16}\\ 3\times2< x< \dfrac{232}{240}\\ 6< x< \dfrac{232}{240}\) (*)
Mà : \(\dfrac{232}{240}< \dfrac{240}{240}=1\\ \)
Nên (*) là vô lí ( Do `6>232/240` )
Vậy \(x\in\varnothing\)
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a: (-14)+(-16)+24
=-14-16+24
=-30+24
=-6
b: |-25|x71+29x25
\(=25\cdot71+25\cdot29\)
\(=25\left(71+29\right)=25\cdot100=2500\)
c: \(=132:\left(41+28-5^2\right)\)
\(=132:\left(69-25\right)=132:44=3\)
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\(\dfrac{15}{19}\) \(\times\) \(\dfrac{38}{5}\) < \(x\) < \(\dfrac{67}{15}\) + \(\dfrac{56}{15}\)
\(\dfrac{5\times3\times2\times19}{19\times5}\) < \(x\) < \(\dfrac{41}{5}\)
6 < \(x\) <\(\dfrac{41}{5}\)
6 < \(x\) < 8,2
Vì \(x\) \(\in\) N nên \(x\) = 7
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Ta có:
-15/21=x/14=35/y=z/-56 =>x/14=35/y=z/-56=-5/7
=>x=-5*14/7=-10 ; y=35/(-5/7)=-49 ; z=-56*-5/7=40
(56+y) - (-4) =25
(56+y) =25 + (-4)
56+y =21
y = 21-56
y = -35
HT