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x+5 chia hết x-2
(x+5) - (x-2) chia hết x-2
x+5 - x+2 chia hết x-2
7 chia hết x-2
x-2 thuộc Ư(7)={-1;1;-7;7}
x thuộc {1;3;-5;9}
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\(\left(5^{2022}:5^{2021}\right):5^{2021}\)
\(=5^{2022-2021}:5^{2021}\)
\(=5^1:5^{2021}\)
\(=\dfrac{5}{5^{2021}}\)
\(=\dfrac{1}{5^{2021-1}}\)
\(=\dfrac{1}{5^{2020}}\)
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2019 . x + 1/2021 . x + 1/2023 . x - 1/2023 = 2019 + 1/2021
mọi người ơi trả lời nhanh giùm mình nhé
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=(1-2)-(3-4)+(5-6)-(7-8)+...+(2021-2022)-2023
=(-1)-(-1)+(-1)-...+(-1)-2023
=0-2023
=-2023
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\(A=1-3+3^2-3^3+...+3^{2021}-3^{2022}\)
\(3A=3-3^2+3^3-3^4+...+3^{2022}-3^{2023}\)
\(3A-A=\left(1-3+3^2-3^3+...+3^{2021}-3^{2022}\right)-\left(3-3^2+3^3-3^4+...+3^{2022}-3^{2023}\right)\)
\(2A=3^{2023}-1\)
\(\Rightarrow A=\left(3^{2023}-1\right)\div2\)
\(\text{cái này mình sợ sai nên bạn có thể nhờ cô chữa}\)
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2023/2022=1+1/2022
2022/2021=1+1/2021
mà 2022>2021
nên 2023/2022<2022/2021
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2020/2021<1
2021/2022<1
2022/2023<1
2023/2020=1+1/2020+1/2020+1/2020>1+1/2021+1/2022+1/2023
=>B>2020/2021+2021/2022+2022/2023+1/2021+1/2022+1/2023+1=4
\(x^{2022}=x^{2021}\\ =>x^{2022}-x^{2021}=0\\ =>x^{2021}\left(x-1\right)=0\\ =>\left[{}\begin{matrix}x^{2021}=0\\x-1=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
x2022=x2021
=> x2022-x2021=0
=> x2021.(x-1)=0
\(\Rightarrow\left[{}\begin{matrix}x^{2021}=0\\x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)