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`x+x:0,1+x:0,01=111`
`x+x.10+x.100=111`
`x.(1+10+100)=111`
`111x=111`
`x=1`
Vậy x cần tìm là `1`
x + x : 0,1 + x : 0,01 = 111
x.1+x.10+x.100=111
x.(1+10+100)=111
x.111=111
x=111:111
x=1
#YM
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\(x\) + \(x\): 0,25 + \(x\) : 0,5 + \(x\) : 0,125 = 40
\(x\) \(\times\) 1+ \(x\) \(\times\) 4 + \(x\) \(\times\) 2 + \(x\times\) 8 = 40
\(x\) \(\times\) ( 1 + 4 + 2 + 8) = 40
\(x\) \(\times\) 15 = 40
\(x\) = 40 : 15
\(x\) = \(\dfrac{8}{3}\)
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\(x\times95-x\times35-x\times55=225\\ x\times\left(95-35-55\right)=225\\ x\times5=225\\ x=225:5\\ x=45\)
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a) x + 5,28 = 9,19 b) x - 34,87 = 58,21 c) x + 37,66 = 80,94
x = 9,19 - 5,28 x = 58,21 + 34,87 x = 80,94 - 37,66
x = 3.91 x = 89.08 x = 43,28
a, x+5,28=9,19 c, x+37,66=80,84
x=3,91 x=43,18
b, x-34,87=58,21 d, 76,22-x=38,08
x=93,08 x=38,14
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\(x\times4+x\times2+x\times10+x+x\times100=23,4\)
\(x\times\left(4+2+10+100\right)=23,4\\ x\times116=23,4\\ x=\dfrac{23,4}{116}\approx0,2\)
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a)\(25,5+y-12,5=4.7\)
⇔\(13+y=28\)
⇔\(y=15\)
b)\(76,22-y-25,7=30+5,52\)
⇔\(50,52-y=35,52\)
⇔\(y=15\)
c)\(4,5-y+1,2=3,5\)
⇔\(5,7-y=3,5\)
⇔\(y=2,2\)
\(a,\Rightarrow10+y=28\\ \Rightarrow y=18\\ b,\Rightarrow50,52-y=35,52\\ \Rightarrow y=15\\ c,\Rightarrow5,7-y=3,5\\ \Rightarrow y=2,2\)