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\(x-\frac{x}{2}+\frac{x}{2}-\frac{x}{3}+...+\frac{x}{2006}-\frac{x}{2007}=\frac{2006}{2007}\)
\(x-\frac{x}{2007}=\frac{2006}{2007}\)
\(\frac{2007x-x}{2007}=\frac{2006}{2007}\)
\(\frac{2006x}{2007}=\frac{2006}{2007}\Rightarrow2006x=2006\)
=>x=1
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\(a,\dfrac{3}{8}=\dfrac{6}{x}\\ \Rightarrow x=6:\dfrac{3}{8}\\ \Rightarrow x=16\\ b,\dfrac{1}{9}=\dfrac{x}{27}\\ \Rightarrow x=\dfrac{1}{9}.27\\ \Rightarrow x=3\\ c,\dfrac{4}{x}=\dfrac{8}{6}\\ \Rightarrow x=4:\dfrac{4}{3}\\ \Rightarrow x=3\\ d,\dfrac{3}{x-5}=\dfrac{-4}{x+2}\\ \Rightarrow3\left(x+2\right)=-4\left(x-5\right)\\ \Rightarrow3x+6=-4x+20\\ \Rightarrow3x+6+4x-20=0\\ \Rightarrow7x-14=0\\ \Rightarrow7x=14\\ \Rightarrow x=2\)
a: =>6/x=3/8
hay x=16
b: =>x/27=1/9
nên x=3
c: =>4/x=4/3
nên x=3
d: =>3/x-5=-4/x+2
=>3x+2=-4x+20
=>7x=18
hay x=18/7
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\(\frac{1}{8}\cdot16^x=2^x\)
\(\Leftrightarrow\frac{1}{8}=\frac{2^x}{16^x}\)
\(\Leftrightarrow\left(\frac{2}{16}\right)^x=\frac{1}{8}\)
\(\Leftrightarrow\left(\frac{1}{8}\right)^x=\frac{1}{8}\)
Suy ra x=1
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\(\frac{x+1}{2}=\frac{8}{x+1}\)
\(\Rightarrow\left(x+1\right)^2=16\)
\(\Rightarrow x+1=4\) hoặc \(x+1=-4\)
*\(x+1=4\Rightarrow x=3\)
*\(x+1=-4\Rightarrow x=-5\)
Vậy \(\text{x = 3; x = -5}\)
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lx-2l+3l2-xl+l4x-8l=32
=>lx-2l+3l2-xl+4lx-2l=32
=>lx-2l(1+3+4)=32
=>lx-2l=32:8
=>lx-2l=4
=>x-2=-4;4
=>x=-2;6
Vậy x=-2;6
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\(\frac{x}{2}=\frac{8}{x}\)
\(\Rightarrow x\cdot x=2\cdot8\)
\(\Rightarrow x^2=16\)
\(\Rightarrow x=\orbr{\begin{cases}4\\-4\end{cases}}\)
\(\frac{x}{2}=\frac{8}{x}\\ \Rightarrow x\cdot x=8\cdot2\\ 2x=16\\ x=16:2\\ x=8\)
Vậy x=8