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\(a.\) \(\frac{1}{8}-\frac{7}{5}-\frac{2}{x}=\frac{-233}{120}\)
\(\frac{1}{8}-\frac{7}{5}+\frac{233}{120}=\frac{2}{x}\)
\(\frac{2}{3}=\frac{2}{x}\)
\(=>x=3\)
\(b.\frac{-12}{7}.\left(\frac{3}{4}-x\right).\frac{1}{4}=0\)
\(=>\frac{3}{4}-x=0\)
\(x=0+\frac{3}{4}\)
\(x=\frac{3}{4}\)
1. \(x=\frac{61}{42}\)
2. \(x=\frac{-36}{5}\)
3. \(x=\frac{13}{11}\)
4. \(x=\frac{1}{12}\)
5.\(x=\frac{-5}{2}\)
\(\frac{1}{8}\)-\(\frac{7}{5}\)-\(\frac{2}{x}\)=\(\frac{-233}{180}\)
\(\frac{1}{8}\)+\(\frac{-7}{5}\)+\(\frac{-2}{x}\)=\(\frac{-233}{180}\)
\(\frac{-51}{40}\)+\(\frac{-2}{x}\)=\(\frac{-233}{180}\)
\(\frac{-2}{x}\)=\(\frac{-233}{180}\)-\(\frac{-51}{40}\)
\(\frac{-2}{x}\)=\(\frac{-7}{360}\)
\(x\)=\(\frac{-2.360}{-7}\)
\(x\)=\(\frac{720}{7}\)
Lần này mình làm cẩn thận hơn rồi
a)\(\frac{5}{21}\)+\(\frac{-3}{7}\)<\(\frac{x}{21}\)<\(\frac{-2}{7}\)+\(\frac{8}{21}\)
\(\Rightarrow\)\(\frac{-4}{21}\)<\(\frac{x}{21}\)<\(\frac{2}{21}\)
\(\Rightarrow\)\(\frac{x}{21}\)\(\in\)\(\left\{\frac{-3}{21};\frac{-2}{21};\frac{-1}{21};\frac{0}{21};\frac{1}{21}\right\}\)
vậy x\(\in\)\(\left\{-3;-2;-1;0;1\right\}\)
1)
a) \(-\frac{8}{15}< \frac{x}{45}< -\frac{2}{5}\)
Lại có: \(-\frac{8}{15}=\frac{-24}{45};-\frac{2}{5}=\frac{-18}{45}\)
=> \(-\frac{24}{45}< \frac{x}{45}< -\frac{18}{45}\)
=> -24 < x < - 18
=> x \(\in\){ - 23; -22; -21; -20 ; -19 } ( thử lại thỏa mãn )
b) \(x=\frac{-4}{3}+\frac{-7}{5}=-\frac{4.5}{3.5}+\frac{-7.3}{5.3}=-\frac{41}{15}\)
c) \(\frac{83}{x}=\frac{13}{4}+\frac{9}{10}=\frac{83}{20}\)
=> x = 20 ( thử lại thỏa mãn)
d) \(x=\frac{10}{8}+\frac{-24}{48}+\frac{105}{-120}=-\frac{1}{8}\)
e) \(\left|x-\frac{1}{2}\right|=\left|-\frac{2}{7}\right|+\frac{5}{4}\)
\(\left|x-\frac{1}{2}\right|=\frac{2}{7}+\frac{5}{4}\)
\(\left|x-\frac{1}{2}\right|=\frac{43}{28}\)
TH1: \(x-\frac{1}{2}=\frac{43}{28}\)
\(x=\frac{57}{28}\)
TH2: \(x-\frac{1}{2}=-\frac{43}{28}\)
\(x=-\frac{29}{28}\)
a/ \(\frac{2}{3}+\frac{4}{35}< \frac{x}{105}< \frac{1}{7}+\frac{2}{5}+\frac{1}{3}\)
\(\Rightarrow\frac{82}{105}< \frac{x}{105}< \frac{92}{105}\)
\(\Rightarrow82< x< 92\)
\(\Rightarrow x=\left\{83;84;85;86;87;88;89;90;91\right\}\)
b/ \(-\frac{7}{15}+\frac{8}{60}+\frac{24}{90}\le\frac{x}{15}\le\frac{3}{5}+\frac{8}{30}+-\frac{4}{10}\)
\(\Rightarrow-\frac{1}{15}\le\frac{x}{15}\le\frac{7}{15}\)
\(\Rightarrow-1\le x\le7\)
\(\Rightarrow x=\left\{-1;0;1;2;3;4;5;6;7\right\}\)
\(\frac{2}{5}-\frac{3}{x}=\frac{1}{35}\)
\(\frac{3}{x}=\frac{2}{5}-\frac{1}{35}\)
\(\frac{3}{x}=\frac{14}{35}-\frac{1}{35}\)
\(\frac{3}{x}=\frac{13}{35}\)
\(\Leftrightarrow13x=3\times35\)
\(13x=105\)
\(x=\frac{105}{13}\)
\(\frac{1}{8}-\frac{7}{5}-\frac{2}{x}=\frac{-233}{120}\)
\(\frac{7}{40}-\frac{8}{40}-\frac{2}{x}=\frac{-233}{120}\)
\(\frac{-1}{40}-\frac{2}{x}=\frac{-233}{120}\)
\(\frac{2}{x}=\frac{-1}{40}-\left(\frac{-233}{120}\right)\)
\(\frac{2}{x}=\frac{-3}{120}+\frac{233}{120}\)
\(\frac{2}{x}=\frac{23}{12}\)
\(\Leftrightarrow23x=2\times12\)
\(23x=24\)
\(x=\frac{24}{23}\)
x=24/23 nha