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Ta co
\(3^x:9+5.3^x.3=408\)
\(3^x.\frac{1}{9}+15.3^x=408\)
\(3^x.\left(\frac{1}{9}+15\right)=408\)
\(3^x\cdot\frac{136}{9}=408\)
\(3^x=27\)
\(\Rightarrow3^x=3^3\)
\(\Rightarrow x=3\)
\(3x-2+5.3x+1=408\)
\(3x-2+15x+1=408\)
\(18x-1=408\)
\(18x=409\)
\(x=\frac{409}{18}\)
vậy \(x=\frac{409}{18}\)
3x - 2 + 5.3x + 1 = 408
3x - 2 + 15x +1 = 408
(3x + 15x) - (2 - 1) = 408
18x - 1 = 408
18x = 408 + 1
18x = 409
x = 409 : 18
x = 22,7(2)
3x-1+5.3x-1=162
=>3x-1.(1+5)=162
=>3x-1.6=162=>3x-1=162:6=27=33
=>x-1=3=>x=4
5x+5x+2=650
=>5x+5x.52=650
=>5x.(1+25)=650
=>5x.26=650=>5x=650:26=25=52
=>x=2
2x+ 3= x+ 2
2x- x= 2- 3
x= -1
vậy x=-1
b) \(3^{x-1}+5.3^{x-1}=162
\)
\(3^{x-1}.\left(1+5\right)=162\)
\(3^{x-1}.6=162\)
\(3^{x-1}=162:6\)\(\Rightarrow3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
a, 3x-1(1+5)=162
=>3x-1.6=162
=>3x-1=27
=>3x-1=33
=>x-1=3
=>4
b, x.(3+x)=0
=>x=0 hoặc 3+x=0
=>x=0 hoặc x= -3
3x-1+5.3x-1=162
=>3x-1.6=162
=>3x-1=162:6
=>3x-1=27=33
=>x-1=3
=>x=4
