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Ta có : \(\left(2^2:\frac{4}{3}-\frac{1}{2}\right).\frac{6}{5}-17\)
=\(=\left(4.\frac{3}{4}-\frac{1}{2}\right).\frac{6}{5}-17\)
\(=\frac{5}{2}.\frac{6}{5}-17\)
\(=3-17=-14\)
Tụi quá mới lớp 5 thui
\(a,\frac{4}{5}-\frac{1}{3}=\frac{4.3}{5.3}-\frac{5.1}{5.3}=\frac{12}{15}-\frac{5}{15}=\frac{7}{15}.\)
\(b,2\frac{1}{2}:\left(-\frac{8}{3}\right)=\frac{5}{2}\cdot\frac{-3}{8}=\frac{-15}{16}\)
\(c,16\frac{2}{7}\cdot\frac{3}{5}+28\frac{5}{7}\cdot\frac{3}{5}=\frac{3}{5}\left(\frac{114}{7}+\frac{201}{7}\right)=\frac{3}{5}\cdot\frac{315}{7}=\frac{189}{7}=27\)
\(d,\left(\frac{3}{4}\right)^4\cdot\left(\frac{4}{3}\right)^5=\frac{3^4}{4^4}\cdot\frac{4^5}{3^5}=\frac{4}{3}\)
a: \(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)=\dfrac{5}{3}\cdot12=20\)
b: \(=\left(4\cdot\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17=\dfrac{1}{2}\cdot\dfrac{6}{5}-17=\dfrac{3}{5}-17=-\dfrac{82}{5}\)
c: \(=-\left(\dfrac{1}{3}\right)^{50}\cdot3^{50}-\dfrac{2}{3}\cdot\dfrac{1}{4}=-1-\dfrac{1}{6}=-\dfrac{7}{6}\)
e: \(=5.7\left(-6.5-3.5\right)=-5.7\cdot10=-57\)
16\(\frac{2}{7}\):\(\left(\frac{-3}{5}\right)+28\frac{2}{7}:\frac{3}{5}\)
=\(\frac{114}{7}.\frac{-5}{3}+\frac{198}{7}.\frac{5}{3}\)
=\(\frac{-190}{7}+\frac{330}{7}\)
=\(\frac{140}{7}\)
=20
Chúc bn học tốt!
\(^{ }_{ }\)