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a) Ta có:
+) \(3^{2n}=\left(3^2\right)^n=9^n\)
+) \(2^{3n}=\left(2^3\right)^n=8^n\)
Vì 9>8 nên \(3^{2n}>2^{3n}\)
b) Ta có: \(5^{23}=5.5^{22}\)
Vì \(5.5^{22}< 6.5^{22}\) nên \(5^{23}< 6.5^{22}\)
c) Ta có: +) \(27^{15}=\left(3^3\right)^{15}=3^{45}\)
+) \(81^{11}=\left(3^4\right)^{11}=3^{44}\)
Vì \(3^{45}>3^{44}\) nên \(27^{15}>81^{11}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)3^200=3^2.100=9^100
2^300=2^3.100=8^100
Suy ra 3^200>2^300
b)125^5=(5^3)^5=5^15
25^7=(5^2)7=5^14
Suy ra 125^5>25^7
c)9^20=(3^2)^20=3^40
27^13=(3^3)13=3^39
Suy ra 9^20>27^13
d)3^54=3^6.9=(3^6)^27=729^9
2^81=2^9.9=512^9
Suy ra 3^54>2^81
e)10^30=10^3.10=1000^10
2^100=2^10.10=1024^10
Suy ra 10^30<2^100
f)5^40=5^4.10=625^10
Suy ra 5^40>620^10
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.2^{60}=\left(2^{10}\right)^6=1024^6\)
\(3^{36}=\left(3^6\right)^6=729^6\)
Vì vậy \(2^{60}>3^{36}\)
\(b.10^{18}=\left(10^2\right)^9=100^9\)
\(5^{27}=\left(5^3\right)^9=125^9\)
Vì vậy \(10^{18}< 5^{27}\)
a) 260 và 336
260 = ( 25 )12 = 3212
336 = ( 33 )12 = 2712
\(\Rightarrow\) 3212 > 2712\(\Rightarrow\) 260 > 336
b) 1018 và 527
1018 = ( 102 )9 = 1009
527 = ( 53 )9 = 1259
\(\Rightarrow\) 1009 < 1259 \(\Rightarrow\) 1018 < 527
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\overline{a,87}\) + \(\overline{2,b2}\)
= \(\overline{a,0}\) + 0,87 + 2,02 + \(\overline{0,b}\)
= \(\overline{a,b}\) + 2,89
vì 2,89 > 2,86 vậy \(\overline{a,87}\) + \(\overline{2,b2}\) > \(\overline{a,b}\) + 2,86
b, \(\overline{a,bc}\) + 20,04+ 28,63
= \(\overline{a,bc}\) + 48,67
= 48,67 + \(\overline{a,b}\) + \(\overline{0,0c}\)
=\(\overline{48,67c}\) + \(\overline{a,b}\)
\(\overline{3a,81}\) + \(\overline{4,b5}\) + 13,9
= 30,81 + \(\overline{a,0}\) + 4,05 + 13,9 + \(\overline{0,b}\)
= 48,76 + \(\overline{a,b}\)
Vì 48,76 > \(\overline{48,67c}\)
Nên \(\overline{3a,81}\) + \(\overline{4,b5}\) + 13,9 > \(\overline{a,bc}\) + 20,04 + 28,63
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
a.
\(\overline{a,87}+\overline{2,b2}=a+0,87+2,02+\overline{0,b}\\ =(a+\overline{0,b})+(0,87+2,02)\\ =\overline{a,b}+2,89\)
b.
\(\overline{3a,81}+\overline{4,b5}+\overline{13,9c}=30,81+a+4,05+\overline{0,b}+13,9+\overline{0,0c}\\ =(30,81+4,05+13,9)+(a+\overline{0,b}+\overline{0,0c})\\ =48,76+\overline{a,bc}=\overline{a,bc}+20,36+28,4> \overline{a,bc}+20,36+28,04 \)
![](https://rs.olm.vn/images/avt/0.png?1311)
dễ mà :
1, 4/6=2/3
18/27=2/3
nen 4/6=18/27
2,12/20=3/5
22/55=2/5
vi 3/5 > 2/5
nen 12/20>22/55
3, 5/6=1-1/6
1111/1212=1-101/1212
vi 1/6>101/1212 nen 5/6<1111/1212