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18 tháng 6 2018

       x4+2008x2+2007x+2008

<=> x4-x+2008x2+2008x+2008

<=> x(x3-1)+2008(x2+x+1)

<=> x(x-1)(x2+x+1)+2008(x2+x+1)

<=> (x2+x+1)(x2-x+2008)

6 tháng 4 2021

\(x^4+2008x^2+2007x+2008\\ =x^4-x+2008\left(x^2+x+1\right)=x\left(x^3-1\right)+2008\left(x^2+x+1\right)=x\left(x-1\right)\left(x^2+x+1\right)+2008\left(x^2+x+1\right)\\ =\left(x^2+x+1\right)\left(x^2-x+2008\right)\)

Ta có: \(x^4+2008x^2+2007x+2008\)

\(=x^4-x+2008\left(x^2+x+1\right)\)

\(=x\left(x^3-1\right)+2008\left(x^2+x+1\right)\)

\(=x\left(x-1\right)\left(x^2+x+1\right)+2008\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^2-x+2008\right)\)

14 tháng 3 2022

2x^4 hay x^4

7 tháng 2 2018

mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

7 tháng 2 2018

  x^4 + 2008x^2 + 2007x + 2008

\(=x^4+x^2+2007x^2+2007x+2007+1\)

\(=x^4+x^2+1+2007\left(x^2+x+1\right)\)

\(=\left(x^2+1\right)^2-x^2+2007\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^2-x+1\right)+2007\left(x^2+x+1\right)\)

\(=\left(x^2+x+1\right)\left(x^2-x+2008\right)\)

14 tháng 2 2016

x^4+2008x^2+2007x+2008

=x^4+2008x^2+2008x-x+2008

=(x^4-x)+(2008x^2+2008x+2008)

=x(x^3-1)+2008(x^2+x+1)

=x(x-1)(x^2+x+1)+2008(x^2+x+1)

=(x^2+x+1)(x^2-x+2008)

14 tháng 3 2015

\(\left(x^4+x^2+1\right)+\left(2007x^2+2007x+2007\right)\)

=\(\left(x^2+x+1\right)\left(x^2-x+1\right)+2007\left(x^2+x+1\right)\)

=\(\left(x^2+x+1\right)\left(x^2-x+2008\right)\)

29 tháng 12 2017

x4_x+2008(x2+x+1)=x(x-1)(x2+x+1)+2008(x2+x+1)=(x2-x+2008)(x2+x+1)

Ta có: \(1+6x-6x^2-x^3\)

\(=-x^3-6x^2+6x+1\)

\(=\left(-x^3+1\right)-6x\left(x-1\right)\)

\(=-\left(x-1\right)\left(x^2+x+1\right)-6x\cdot\left(x-1\right)\)

\(=\left(x-1\right)\left(-x^2-x-1-6x\right)\)

\(=-\left(x-1\right)\left(x^2+7x+1\right)\)

17 tháng 8 2021

\(1+6x-6x^2-x^3\)

= (1-x^3)+(6x-6x^2)

=(1-x)(1+x+x^2)+6x(1-x)

=(1-x)( 1+ x+ x^2 + 6x)

=(1-x)(1+x^2 +7x)

Đây bạn ơi!

31 tháng 7 2023

\(\dfrac{1}{2}x^3+4\)

\(=\dfrac{1}{2}\left(x^3+8\right)\)

\(=\dfrac{1}{2}\left(x^3+2^3\right)\)

\(=\dfrac{1}{2}\left(x+2\right)\left(x^2-2\cdot x+2^2\right)\)

\(=\dfrac{1}{2}\left(x+2\right)\left(x^2-2x+4\right)\)

=1/2(x^3+8)

=1/2(x+2)(x^2-2x+4)

5 tháng 12 2017

=x4+2008x2+2008x-x+2008

=(x4-x)+(2008x2+2008x+2008)

=x(x3-1)+2008(x2+x+1)

=x(x-1)(x2+x+1)+2008(x2+x+1)

=(x2+x++1)(x2-x+2008)