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\(1-\left(x-1\right):3=\dfrac{2}{3}\)
\(\Rightarrow1-\left(x-1\right)=\dfrac{2}{3}.3\)
\(\Rightarrow1-\left(x-1\right)=2\)
\(\Rightarrow x-1=1-2\)
\(\Rightarrow x-1=\left(-1\right)\)
\(\Rightarrow x=\left(-1\right)+1\)
\(\Rightarrow x=0\)
\(A=1+3+3^2+3^3+...+3^{20}\)
=> \(3A=3+3^2+3^3+3^4+...+3^{21}\)
=> \(3A-A=3^{21}-1\)
=> \(2A=3^{21}-1\)
=> \(A=\frac{3^{21}-1}{2}\)
-.-? lớp 6
Có \(\left(5x-7\right)\left(2x+3\right)-\left(7x+2\right)\left(x-4\right)\)
\(=10x^2+15x-14x-21-7x^2+28x-2x+8\)
\(=\left(10x^2-7x^2\right)+\left(15x-14x+28x-2x\right)+\left(-21+8\right)\)
\(=3x^2+27x-13\)
Thay x = 1/2 vào biểu thức đã rút gọn
\(\Rightarrow3\left(\frac{1}{2}\right)^2+27.\frac{1}{2}-13=\frac{5}{4}\)
Vậy giá trị biểu thức là 5/4
(5x-7)(2x+3)-(7x+2)(x-4)
=10x2+15x-14x-21-(7x2-7x+2x-8)
=10x2-x-21-7x2+7x-2x+8
=3x2+4x-13
Thay x=1/2 vào BT ta được:
3*(1/2)2+4*1/2-13
=3/4+2-13
=3/4-11
=-41/4
a) \(\frac{113}{13}-\frac{24}{7}-\frac{53}{13}=\frac{60}{13}-\frac{24}{7}\)
=\(\frac{420-312}{91}=\frac{108}{91}\)
b) \(\frac{2}{7}.\left(\frac{51}{4}-\frac{31}{4}\right)=\frac{2}{7}.5=\frac{10}{7}\)
c) \(\frac{3}{5}+1-\frac{1}{20}\)= \(\frac{12}{20}+\frac{20}{20}-\frac{1}{20}=\frac{31}{20}\)
\(=\dfrac{10}{17}-\dfrac{5}{3}+7-\dfrac{8}{13}+\dfrac{11}{25}\)
\(=\dfrac{30}{51}-\dfrac{85}{51}+\dfrac{175}{25}+\dfrac{11}{25}-\dfrac{8}{13}\)
\(=\dfrac{-55}{51}+\dfrac{186}{25}-\dfrac{8}{13}\)
\(=\dfrac{-55\cdot325+186\cdot663-8\cdot1275}{16575}=\dfrac{95243}{16575}\)
A=1+3+32 +...+3299 +3300
3A=3+32 +...+3299 +3300 +3301
3A-A=3301 - 1
=> A=\(\frac{3^{^{301}}-1}{2}\)